# Quantitative Aptitude: Data Interpretation Set 15 (Missing DI)

Tabular Data Interpretation on Missing Values. Missing DI Questions

Direction (1-5): In the graph below data about number of employees in four company A,B,C and D is give. Each company has only male or female employees of whom some are married and some are unmarried. Some values are missing in the table. Find the values on the basis of given information and answer accordingly.

 Comp any Total Empl-oyees Males Females Marr-ied Males Unma-rried Males Married Females Unma-rried Females A 756 526 – 325 – – – B – – – 215 – 254 – C – 159 – – – – – D 224 142 82 – – – –

1. If the number of unmarried female in company A is 2 more than half the number of married female in the same company. Find the difference between unmarried male in Company Aand unmarried female in Company A
A) 125
B) 130
C) 123
D) 120
E) 118
Option C
Solution
:
Total Female = 756-526 = 230 ;
Let married female = x ; => Unmarried female = x/2 + 2
=>x + x/2 + 2=230
=>married female = 152; unmarried female = 78
Unmarried male= total male- married male = 756-325= 201
difference unmarried male- unmarried female = 201-78 = 123
2. The number of unmarried male in company B is 26 more than the married male in the same company. The difference between the number of unmarried male and unmarried female in the company B is 122. Find the total number of employee in company B, if the total number of male in Company B is greater than the total number of female in company B.
A) 768
B) 867
C) 748
D) 829
E) 826
Option D
Solution
:
Males(Unmarried in B) = 215+26 = 241;
Females(Unmarried) =241-122 = 119
males = 215+241 = 456;
females = 254+119 = 373
total=456+373=829
3. Number of women in Company C is 147 more than the number of women in company A. If the sum of Married male and Married female in company C is 115, then find the sum of Unmarried male and unmarried female in Company C.
A) 418
B) 421
C) 415
D) 467
E) 435
Option B
Solution
:
Number of Female in Company C= 230+147=377
Male=159
Given that Married(Male+female)= 115
hence Unmarried(male+female)= total(male+female)-married(male+female)
=>unmarried(male+Female)=536-115=421
4. The number of married female and unmarried female in company D are equal. If the number of married male in company D is 5 more than the number of married female in company D, then find the difference between unmarried male and unmarried female in company D.
A) 142
B) 224
C) 79
D) 55
E) 102
Option D
Solution
:
Married female=unmarried female= 82/2=41
Male married=41+5=46; Male unmarried = 142-46=96;
Difference = 96-41=55
5. The number of married male in company D is 46. If 124 male from company A of whom 62 are married, are transferred to company D, then find the new number of unmarried male in company D.
A) 124
B) 62
C) 158
D) 166
E) 168
Option C
Solution
:
Unmarried Male in D= 96
Unmarried Male in Company A who are transferred to D = 124-62=62
Unmarried Male in Company D(new)= 96+62=158

Direction (6-10): In the table below data related to five items A,B,C,D and E are given. Cost Price(in Rupees), Marked Price(in Rupees), Selling Price(in Rupees) , Discount percentage and Profit percentage of some items are given. Some values are missing in the table. Find the values on the basis of given information and answer accordingly.

 Item Cost Price (in Rs.) Marked Price (in Rs.) % discount % Profit Selling Price (in Rs.) A – – 10% – 180 B – – 10% – – C 110 – 5% 29(6/11)% – D 300 400 – – 340 E – 500 – – –

1. If the marked price of item B is Rs 100 more than the marked price of item A. Then find the Selling price of item B.
A) Rs 250
B) Rs 270
C) RS 300
D) Rs 280
E) Cannot be determined
Option B
Solution
:
MP of A = 180*100/90= 200
MP of B= 200+100=300
SP of B= 300*90/100=Rs 270
2. The cost price of item A is how much less than its marked price(in Rupees) if the profit % after selling item A is double the % discount offered on Item A.
A) Rs 60
B) Rs 55
C) Rs 45
D) Rs 40
E) Rs 50
Option E
Solution
:
%P=20% =>CP=Rs 150
MP=180*100/90=Rs 200
diff=200-150=Rs 50
3. Find the difference between Marked Price and Selling Price of item C.
A) Rs 7.5
B) Rs 8
C) Rs 10
D) Rs 50
E) Rs 5
Option A
Solution
:
SP=110*([100+ 29(6)/11)/100]= Rs 142.5
MP=142.5*100/95= Rs 150
Difference = 150-142.5= Rs 7.5
4. Find the profit % of item E if the % discount od item E = % discount of item C and the Cost Price of E is 1.5 times the cost price of Item D.
A) 5%
B) 6%
C) 5(5/9)%
D) 6(1/3) %
E) None of these
Option C
Solution
:
CP(E)= 1.5*300=Rs 450;
SP = 500*95/100 =Rs 475
%P=(475-450)/450 *100=50/9%= 5(5/9)%
5. Find the % discount and % profit of item D.
A) Discount= 10% ; Profit= 13(2/3)%
B) Discount= 25% ; Profit= 15%
C) Discount= 10% ; Profit= 18%
D) Discount= 15% ; Profit= 13(1/3)%
E) None of these
Option D
Solution
:
%d= (MP-Sp)/MP*100
%p= (SP-CP)/CP*100

## 7 Thoughts to “Quantitative Aptitude: Data Interpretation Set 15 (Missing DI)”

1. akduuuuuu

thankyou mam 🙂

2. sTrike Like a Puma

Thank u

3. purvi

thanku

4. Arnav

maam can u pls expln Q8
soln

1. Shubhra

In which step do u have doubt ??