Quantitative Aptitude: Data Interpretation Questions – Set 72

Direction (1-5): The following table shows the expenditure and income of a certain company in 5 years. Upon which its profit% and loss% are also given. Some values are missing. Study the table carefully and answer the questions based on data in table and particular questions.

1. Profit in 2013 is how much percent more as compared to profit in 2011?
   A) 63.23%
   B) 56.76%
   C) 45.83%
   D) 59.82%
   E) 44.98%
   
   View Answer

   Option C
   Solution:
   In 2011, profit = 15/100 * 96 = 14.4 millions
   In 2013, profit = 80/100 * 105 = 21 millions
   Required % =(21 – 14.4)/14.4 * 100 = 45.83%
2. In 2015, expenditure of company was 15% more as compared to 2012. Find income generated by company in 2015.
   A) 125.488 millions
   B) 124.488 millions
   C) 125.468 millions
   D) 116.488 millions
   E) 115.488 millions
   
   View Answer

   Option A
   Solution:
   In 2015, expenditure = 115/100 * 124 = 142.6 miilions
   So income = 88/100 * 142.6 = 125.488 millions
3. Loss incurred by company in 2012 was 16.6 millions more than profit of company in 2011, what is the loss% incurred by company in 2012? 
   A) 17% 
   B) 28%    
   C) 22%   
   D) 25%
   E) 23%     
   
   View Answer

     Option D
   Solution:
   Profit in 2011 = 15/100 * 96 = 14.4 millions
   So loss in 2012 = 16.6 + 14.4 = 31 millions
   So loss% = 31/124 * 100 = 25%
4. In 2014, profit% of company was 60% more than in 2011. Find percent increase (approximately) in expenditure of company in 2014 as compared to previous year.
   A) 41%
   B) 29% 
   C) 45%
   D) 34%
   E) 38%
   
   View Answer

     Option E
   Solution:
   In 2014, profit% = 160/100 * 15 = 24%
   So expenditure in 2014  = 179.8 * 100/124 = 145 millions
   So required % = (145-105)/105 * 100 = 38%
5. Using the data from table and above 4 questions, find the average profit of company in all years.
   A) 4.4176 millions
   B) 4.4176 millions
   C) 4.4176 millions
   D) 4.4176 millions
   E) 4.4176 millions
   
   View Answer

   Option B
   Solution:
   Profit in 2011 = 14.4 millions
   Loss in 2012 = 31 millions
   Profit in 2013 = 21 millions
   Profit in 2014 = 24% of 145 = 34.8 millions
   Loss in 2015 = (142.6 – 125.488) = 17.112 millions
   So average = (14.4 – 31 + 21 + 34.8 – 17.112)/5 = 4.4176 millions

Direction (6-10): Study the following table to answer the questions that follow. Some values are missing. Study the table carefully and answer the questions based on data in table and particular questions.

6. To fill a tank, pipes A and C were opened at 2:10 PM. After 5 minutes pipe A was closed and at the same time pipe P got opened. After some time it was found that tank was 2/3rd empty, at what time it was observed?
   A) 2:32 PM
   B) 2:30 PM
   C) 2:27 PM
   D) 2:35 PM
   E) 2:20 PM
   
   View Answer

   Option D
   Solution:
   A and C work for 5 minutes – (1/15 + 1/25) * 5 = 8/15 tank fill
   Now A was closed and C and P work
   In 1 minute they work = (1/25 – 1/20) = -1/100 — means empty
   let they C and P work for x minutes up to when tank was found 2/3rd empty
   So
   8/15 + (-1/100)*x = 1/3        ….   [ 1/3rd tank is fill at this time]
   Solve,  x = 20 mins
   So the time when 2/3rd empty tank was observed – 2:10 + 5 minutes + 20 minutes = 2:35 PM
   
7. A tank was 2/5th full. To fill it more, pipe D was to be opened, but accidentally pipe Q got opened. When it was noticed after 4 minutes, pipe Q was closed. And now to fill tank quickly, pipe C was opened. What time could have been saved if pipe Q was not opened?
   A) 7.45 minutes  
   B) 5.35 minutes  
   C) 5.25 minutes  
   D) 8.35 minutes  
   E) 7.25 minutes  
   
   View Answer

   Option E
   Solution:
   Tank was 2/5th full. So to fill 3/5th tank, D will take 3/5 * 30 = 18 minutes …………………….(1)
   Now
   Pipe Q was opened for 4 minutes, so it emptied = 1/16 * 4 = 1/4th tank
   Now tank filled is = 2/5 – 1/4 = 3/20
   Now pipe C was opened, to fill 17/20th tank, C takes = 17/20 * 25 = 85/4  = 21.25 minutes
   So total time now taken to fill tank = 4 + 21.25 = 25.25 minutes  ……………………..(2)
   So time that could have been saved = 25.25 – 18 = 7.25 minutes  
   
8. There was some garbage in a tank. To remove the garbage, pipes A and R worked alternately for 3 minutes each starting with A. The procedure continued for 24 minutes, after which pipes A and D were opened to fill the tank. If the tank was filled in next 7 minutes, find the time in which pipe R can empty the full tank.
   A) 24 minutes
   B) 28 minutes
   C) 18 minutes
   D) 20 minutes
   E) 32 minutes
   
   View Answer

   Option A
   Solution:
   Procedure continued for 24 minutes, so pipes A and R both worked for 12 minutes each, giving 3 minutes each in turn.
   So in 12 minutes, pipe A’s work = 1/15 *12 = 4/5
   In 12 minutes, pipe R’s work = 1/x *12 = 12/x       [Let x = time in which pipe R can empty the tank]
   Now A and D worked for 7 minutes, so their work in 7 minutes = (1/15 + 1/30) * 7 = 7/10
   So 
   4/5 – 12/x + 7/10 = 1
   Solve, x = 24 minutes
   
9. A tank is to be filled by using pipes B and D simultaneously. After 9 minutes, some garbage was observed in tank so pipes B and D were closed and pipe S was opened. After 6 minutes, it was found, that tank is clean so pipe S was closed and again pipes B and D were opened, after which they filled the tank in 6 minutes. If pipe S alone can empty 2/9th tank in 4 minutes, in how much time pipe B can fill the fill tank?
   A) 20 minutes
   B) 16 minutes
   C) 15 minutes
   D) 24 minutes
   E) 18 minutes
   
   View Answer

   Option E
   Solution:
   S can empty 2/9th tank in 4 minutes, so full tank in 9/2 * 4 = 18 minutes
   So now
   (1/B + 1/30) * 9 + (-1/18) *6 + (1/B + 1/30) * 6 = 1
   (1/B + 1/30) * 15 = 1 + 1/3
   (1/B + 1/30) * 15 = 4/3
   Solve, B = 18
10. Using the data from table and above questions, which of the following combination of pipes will fill the tank in less time as compared to other combinations given?
    A) A-B-S
    B) B-C-P
    C) A-D-Q
    D) A-B-P
    E) B-D-R
    
    View Answer

    Option D
    Solution:
    A) A-B-S 
    [1/15 + 1/18 – 1/18] — 1/15 so this combination will fill tank in 15 minutes 
    B) B-C-P
    [1/18 + 1/25 – 1/20] — 41/900 so this combination will fill tank in 900/41 = 21.9 minutes
    Similarly
    C) A-D-Q — 80/3  = 26.6 minutes
    D) A-B-P — 180/13  = 13.8 minutes
    E) B-D-R — 360/17 = 21.2 minutes

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