Data Interpretation Questions (DI) for IBPS PO 2017, IBPS PO, NIACL, NICL, SBI PO RBI Grade B, Dena Bank PO PGDBF, BOI, Bank of Baroda and other competitive exams.

**Direction (1-5): Study the following information and answer the questions that follow:**

There are 6 people A, B, C, D, E and F. They require certain days to complete a piece of work. The graph below shows by what percent person B, C, D, E and F are more efficient than A. Answer the questions based on this data.

- If C can do a work in 120 days then how many days would B take to do the same piece of work?

A) 80 days

B) 100 days

C) 96 days

D) 106 days

E) 88 days

- B starts the work and after working for 80 days he leaves. After this D takes over the work and finishes it in 120 days. How much time will E and F take together to complete the same work?

A) 84 (8/9) days

B) 88 (8/9) days

C) 78 (8/9) days

D) 79 (8/9) days

E) 80 (8/9) days

- To do the same piece of work D and E together take 125/18 days more than the days taken by B and C together. In how many days A and F together can do the work?

A) 62 (5/23) days

B) 65 (7/23) days

C) 62 (7/23) days

D) 62 (9/23) days

E) 65 (5/23) days

- When B works at half of his overall efficiency he tales 45 days more than what C takes to complete the full work. If the same work is to be completed by D and F together with D having been worked for 10 days alone then how many days will D and F together take to complete the remaining work?

A) 30 (18/23) days

B) 31 (15/23) days

C) 30 (18/23) days

D) 34 (18/23) days

E) 30 (15/23) days

- Person Z who is 50% more efficient than E takes 80 days less than B to complete the work. Identify the correct statement from the given:

(i) Difference between time taken by C and time taken by Z to complete the work individually is more than 100.

(ii) A and Z together can do the work in 85 days.

(iii) If Z works for 50 days and the remaining work is done by A alone for 315 days the work gets completed

A) Only (i)

B) Only (ii) and (iii)

C) Both (i) anf (ii)

D) Both (i) and (iii)

E) All (i), (ii) and (iii)

**Direction (6-8): Study the following information and answer the questions that follow:**

In a boating competition there are 3 boats X, Y and Z taking in the race. The river in which the race is to be held is divided into three equal parts AB, BC and CD. To complete the race a boast must travel from A to D downstream and back from D to A upstream.

The speed of stream in part BC is 50% of the speed of stream in part AB, while the speed of stream in part CD is 150% of the speed of the stream in part AB.

Speed of boat X in still water= 6 kmph;

Speed of boat Y in still water= 5 kmph

Speed of boat Z in still water= 8 kmph

- If boat Y takes 1 hour to travel from point B to C downstream that is 6 km in distance. Find the time that boat X will take to travel from A to D downstream.

A) 3 (15/28) hours

B) 2 (23/84) hours

C) 4 (1/4) hours

D) 4(3/4) hours

E) 3 (15/17) hours

- When the speed of the stream in region CD is 3 kmph boat X takes 47 hour move from point D to point A upstream. Find the time required for boat Y to cover the distance CD downstream.

A) 8 hours

B) 9 hours

C) 7 hours

D) 7.5 hours

E) 8.5 hours

- X, Y and Z starts the race from position A. What distance more would boat Z have travelled than boat Y at the time when boat Y reaches point B? (Distance AD= 210 km and speed is stream in region BC is 1 kmph)

A) 20 km

B) 25 km

C) 27 km

D) 28 km

E) 30 km

**Direction (6-8): Study the following information and answer the questions that follow:**

Two trains of length 1.1 km and 0.9 km are moving in the opposite direction at a speed of ‘X kmph’ and ‘1.5X kmph’ respectively. The time taken by the slower train to completely cross the faster train is 48 seconds.

- Find the speed of train with length 0.9 km

A) 60 kmph

B) 90 kmph

C) 120 kmph

D) 150 kmph

E) 180 kmph

- Find the relative speed of the two trains when moving in same direction in m/s (approx).

A) 9.1 m/s

B) 7.2 m/s

C) 10.2 m/s

D) 6.7 m/s

E) 8.3 m/s

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sir…in second question ans is wrong…:)))

which step?

2400/13 + 1200/7 ans is coming diff..:)

what should it be?

means denominator is 91

should be 356 approx

it will be 13/2400 + 7/1200

then reverse of the value that comes

sir v r calculating total work na???

no time is asked

How much

timewill E and F take together to complete the same work?13/1200+ 7/2400 =33/2400 =2400/33 =800/11??

13/1200 nhi hai; 13/2400 hai.. see..

and 7/1200 hai

okkk sir….:)))

@@disqus_0OrBOABGUE:disqus can you help me out in this ? i mentioned it above

where bro????

I got it now .

nhi bro ans sahi hai

mne inversion kr dia tha isly thnk ssi

sir ques 4 me E= 450/7 q nhi hua

replace E with F.. now changed

OK SIR THANKU

Sir mera ans 500/23 aa rha hai ?

tell the steps

sir plz batao ki kis step me galti kar rhi hu

for that u will have to explain me this method;; i dont use it..

tell why 150, 120, 12, 7.5,

sir its the efficiency ratio…;))

solve 4th and tell what answer u r getting

okk sir but i got stuck up in question 333 .:((

eff wale se nhi aa rha 3 ka ans

haaa sso but aana chaiye mn whi se try kr rha huuu…:(((

ho jaye to mujhe bhi batana plz

see,, i asked u something;; why have u taken total work=150*10?

i dont use this method;; so asking

sir mujhe bhi bahi confusion ho rha hai

i will give u the solution by lcm method tomorrow

ok sir

sir Q6.ka answer 191/84 aa rha h

see now…

siso..us question mn b kuch problem h given ans and jo mujhe mil rha h dono alg aa rhe h…:((

mera 1250/23 aa rha hai

3rd ka na same mera b…:))

let A=x days

Then,D=xdays,E=100x/140=5x/7days

D+E=5x/12days

Now B=100x/150=2x/3days

C=100x/120=5x/6days

B+C=10x/27days

Given,

5x/12-10x/27=125/18

x=150days

A=150,F=150*100/130=1500/13

A+F=1/150+13/1500=23/1500

efficiency se nikal k btao bro yeh soln same posted h…:)

bro me aise hi solve kiya..efficiency se confuse ho jata hu

heheehhehe…ok.okk thanks bro…:)

a : b :c

100:150:120— effi

10:15:12

c- half of B = 45

12-7.5= 4.5

4.5——-45

1—–10

TOTAL WORK 150*10= 1500

now

A:D:F

100:100:130

WORK OF D IN 10 DAYS = 100*10= 1000

REMAINING 1500-1000= 500

TOTAL EFF. OF d+f = 10+13 = 23

REMANING DAYS = 500/23

why total work 150*10?

sir instead of 4x/3 it should be x/3 as 2x/3 *1/2 =x/3

d ki efficency 100 h sir?????

0% more than A,, means he takes same time as A takes

means if a =100 then d =100+0% of 100 =100 le skte sir???

haa same

sir in question 5 z is 50% more efficient then E so efficiency of z =(1.5 * efficiency of E) SO E efficiency is 1.4 so Z efficiency will be 1.4 *1.5 =2.1 but as per ans its efficiency is 2.8 ,i think it is wrong , would you please check that.

ok wait; 4th done?

sir in 4th efficiency should b x/3 instead of 4x/3…:)

for ex if x =30 then 2x/3 =20

and 4x/3 =40 then a/c to condition 1/2 of 20 should be 10 but its coming 40…so x/3 should b there sir…:)

4x/3 is not the efficiency,, it is the number of days that he will take

so if efficiency is become half,, the number of days that he takes is getting doubled

sir aaj k questions bikl smj nhi aa rha h jb efficency di hui h thn alg alg x se kyu kr rhe h ….sir…:(((

do with any method; answer same hona chahye

whi to nhi aa rha ans same sir…:))

only 4th na? ans kya aarha hai?

yess whi sir…;)

ans kya aarha?

21(17/23) sir

efficiency ratio

b—————c

150———–120 =>5————4

now efficiency of b gets halved

=>now b =2.5

b——————–c

2.5——————4

=>days ratio =4————-2.5

now 1.5 ratio = 45

=>1 ratio =30

=>4 ratio =120 =b

=>2.5 ratio =75 =c

total work done by b and c togather =(2.5*120)+(75*4) =600

now efficiency ratio of d and f

d—————-f

10————–13

work done by d in 10 days =10*10=100

remaining work =600 -100 =500

now total days d and f take togather to complete the remaining work

d(t) =500/23 =21(17/23) days

maine bhi yahi method se kiya hai mera toh saho a raha hai answer

yes mera b aa chuka usme thoda mistk h…:)

sir???????

i will have to see this method;; answer is correct;;

check now

sir correction in question 4 also i think…;))))

ok wait

sir d+e h ya d+f h???? pehle d+e shw ho rha tha ab D+f shw ho rha h????

in 4th na?? — its D + F now

ty..)

Q 3 and 4 not understandable

ques or solution?

question

from we start ??

3) B and C sath me jitne din me kaam kar sakte hai ; D aur E ko utne days se 125/18 days aur jyada lagta hai utna hi kaam krne me…

to ab find karo ki A and F kitne din me sath kaam kar sakte hai

B and C ki efficiency pata hai with respect to A,, to pehle B and C ka time nikalo kitna time me kreneg,, then D and E ka nikalo;; subtract and equate to 125/18 as in solution

ok sir got it

thnxx

3,4 ka ansr nhi aa rha ?

doing by lcm method?

150+120 is the efficiency of b and c

after it what to do sir i m not getting the ansr

lcm se nhi hua ye kisi ka ques;; i dont use this method..

A ka efficiency 100 le k kr rhi hu nhi aa rha

yes wahi bola maine, ki ye wala ques efficiency wale method se koi nhi kar paya… try with normal method

?????

Ok sir thankyou

i have done this by lcm method usinf efficiency..i have got the same answer

sir efficiency method se bhi yhi ans aa rha hh ryt ans h…:)

efficiency ratio => b—————-c

150———–120

5————–4

now days ratio=>b——————c

4—————–5

now b’s eff.is halved so 2.5=> days will b doubled =8

=> new days ratio=> b—————c

8—————5

now 3 ratio =45 => 1 ratio =15

=> 8 ratio =b=120 days

and 5 ratio =c=75 days

now work done will b same in both cases even though efficiency is halved

so total work done by b and c =>120*5+75*4=900

now eff of d and f => 10:13

now work done by d in 10 days =>10*10 =100

remaining work =900-100 =800

now work done by both =800/(13+10) =800/23 =34(18/23) days

sir..aapne 4th question ka nas nhi btya which 1 is ryt????

given ans is right..

then how diffrence in ans is comong sir????

i will tell,, when i get the solution using efficiency method… ans is coming same by that method too,, one of my frnd has solved,, i will give you the solution when I get it

process sir aapk frnd ne solve kia h thn process i wll match that wth my soln and find out wher i am going wrong sir….:)))) becoz i tried so many tyms but getting the same ans…:)

yes still i am not having that solution.. i will give it

okk sir waiting……:)

efficiency method % based?/

i wud also lyk to knw..:)

see here bro

cd = 150/100 ab

=>ab =100/150 cd =>2/3 cd

now cd =3km/hr =>ab =2km/hr…:)

nice set of questions…

🙂