**Directions (1-5): Read the following information carefully and answer the questions given below it: **

Eight persons B, D, F, H, J, L, N and P are standing in a row facing north and all are standing at a distance of 1km, 2km, 3km and so on from their immediate neighbours but not necessarily in the same order. Two persons are at a same distance of 5km from their immediate neighbours. D is 3km left of F and 6km away from L. D is standing immediately between J and N at 5km and 2km respectively. P is 4km left of J. F is second to the left of H. Person on the extreme left is 10km away from J. P starts moving towards the south and after going 3km it takes right turn and going 2km and reached point X. Another person K, which moves more than 3km but less than 8km towards the north of point X (also divisible by 3), going Y km towards east and stops at point C. If Y is the shortest distance of B and P’s last position. F moves 3km towards north direction, and then takes a left turn and goes 5km straight and then it turns again to its right direction and moves another 7km and halts at point Z.

- How many persons are there in between ‘J’ and ‘H’?
TwoFiveSixFourNone of theseOption D

**Solution:**

1. D is standing immediately between J and N at 5km and 2km respectively. P is 4km left of J.

2. D is 3km left of F and 6km away from L. F is second to the left of H. Person on the extreme left is 10km away from J.

3. Two persons are at a same distance of 5km from their immediate neighbours.

4. P starts moving towards the south and after going 3km it takes right turn and going 2km and reached point X.

5. Another person K, which moves more than 3km but less than 8km towards the north of point X (also divisible by 3), going Y km towards east and stops at point C. If Y is the shortest distance of B and P’s last position.

Y = √((4)^{2}+ (3)^{2}) = √(16+9) = 5km

Hence, K moves 6km in north direction.

6. F moves 3km towards north direction, and then takes a left turn and goes 5km straight and then it turns again to its right direction and moves another 7km and halts at point Z.

Hence, there are four persons between ‘J’ and ‘H’. - Which person will be met first, if ‘F’ starts moving in the West direction?
DJNBPOption C

Hence, ‘F’ first met ‘N’ when move towards West. - What is the shortest distance between ‘L’ and dog P’?
11km13km18km15km19kmOption D

Hence, the shortest distance between ‘L’ and ‘P’ is 15km. - What is the shortest distance K and F from their new positions?
5km√67km14km√65kmNone of theseOption D

Hence, shortest distance between ‘K’ and ‘F’ is √(7^{2}+ 4^{2}) = √(49+16) = √65km - What is the new position of ‘P’ with respect to the ‘B’? 1) 2) 3) 4) East 5) North Ans: 3
North – WestSouth – WestSouth – EastEastNorthOption C

Hence, new position of ‘P’ with respect to ‘B’ is south – East. - Given X#S, XS = 3m, N*X. Find distance between N and O?
4m5m6m7mCannot be determinedOption B

X#S means X is of west of S, XS = 3m, N*X means N is of north of X.

Hence NO = 3 + 2 = 5m - If N*S, then which of the following is true regarding points N and S?
S*%NN*%SN&^SS&^NNone of theseOption D

If SR = 4m then SN must be 6m and if SR = 6m then SN must be 4m.

Hence, S&^N means S is south of N at a distance of either 4 or 6 m. - A man starts walking from point M walks for 5m in ‘@’ direction, reaches point J, turns ‘&’ direction and now walks 7m to reach point S. Given J*S. What is the distance between points O and M and consider question number 1 also.
√39m√34m√43m4√7m4√2mOption B

X#S means X is of west of S, XS = 3m, N*X means N is of north of X.

J*S – J is north of S. and JS = 7 m, which is only possible when MN = 3 m from Q1, NO = 5m So MO = √(3^{2}+ 5^{2}) = √34 m - If distance point S and Q is 6√2m, then find distance between points S and O?
2√5m8√5m5√5m7√6m5√2mOption A

SQ= 6√2 m

So RS = √(SQ^{2}– RQ^{2}) = √(6√2)^{2}– 6^{2}) = √36 = 6 m

Assume point A – east of S and south of O

So SO = √(SA^{2}+ OA^{2})

SA = RQ – OP = 2 m,

OA = PQ – RS = 10-6 = 4m,

now find SO = 2√5 m - If Y&^P and S#Y, what is the maximum area of the quadrilateral formed by joining points Y, S, R and Q?
25m228m216m236m2None of theseOption D

Y&^P – Y is south of P and at a distance of 4 or 6 m.

S is west of Y and figure formed by joining given points is a rectangle.

So if PY = 4, YQ = RS = 6, and if PY – 6, then YQ = RS = 4.

Area will be maximum in 1st case.

So Area of rectangle YQRS = RQ*PQ = 6*6 = 36 m2

**Directions(6-10): Read the following information carefully to answer the questions that follow.**

The questions are based on following coding formats:

* – North

& – South

@ – East

# – West

^ – Either 4 or 6 m

% – Either 3 or 10 m

Examples:

A&B means A is South of B,

A*#B means A is North-West of B,

A#^B means A is West of B at a distance of either 4 or 6 m.

Conditions given are as:

I. M*%N

II. M*#O

III. O@N

IV. O#^P

V. Q&%P

VI. R#^Q

VII. S*^R

VIII. S&#O