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There are 35 questions and time limit is 45 minutes. Some questions are for 1 point, other for 2. Points are indicated on the right hand side of question number.
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Question 1 of 35
1. Question
2 points
Directions (1-5): Study the following carefully to answer the questions that follow:
Some students participated in three different activities – painting, swimming and dancing. The total students who took part in painting is 3500 of which 5% students took part in both painting and swimming only. The number of students who took part in both dancing and swimming only is 50% greater than the number of students who took part in all 3 activities. The number of students who took part in only swimming is 100 less than the number of students who took part in only dancing. The total number of students who took part in dancing but not painting is 3675. The number of students who took part in only swimming is 2950 more than the number of students who took part in all three activities. The number of students who took part in painting only is 1925 more than the number of students who took part in painting and dancing only.
Find the ratio between number of students who took part in painting and dancing only and thoseÂ who took part in swimming and dancing only
Correct
Who took part in only painting = a Who took part in painting + swimming = b Who took part in painting = a + b + d + e Who took part in all 3 = e a + b + e + d = 3500 [Given] Noe 5% of 3500 = b [Given] So b = 175 So a + e + d = 3500 – 175 = 3325 …….. (1) Next: f = 150/100 * e [Given] c = g – 100 [Given] f + g = 3675 [Given] c – e = 2950 [Given] Here we have 4 variables (c, e, f, g) and 4 equations Solve all equations to find the values c = 3200, e = 250, f = 375, g = 3300 So from (1), a + d = 3075 a = 1625 + d [Given] Now from these 2 equations a = 2500, d = 575 So a = 2500, b = 175, c = 3200, d = 575, e = 250, f = 375, g = 3300
So here we need d : f 575 : 375 = 23 : 15
Incorrect
Who took part in only painting = a Who took part in painting + swimming = b Who took part in painting = a + b + d + e Who took part in all 3 = e a + b + e + d = 3500 [Given] Noe 5% of 3500 = b [Given] So b = 175 So a + e + d = 3500 – 175 = 3325 …….. (1) Next: f = 150/100 * e [Given] c = g – 100 [Given] f + g = 3675 [Given] c – e = 2950 [Given] Here we have 4 variables (c, e, f, g) and 4 equations Solve all equations to find the values c = 3200, e = 250, f = 375, g = 3300 So from (1), a + d = 3075 a = 1625 + d [Given] Now from these 2 equations a = 2500, d = 575 So a = 2500, b = 175, c = 3200, d = 575, e = 250, f = 375, g = 3300
So here we need d : f 575 : 375 = 23 : 15
Unattempted
Who took part in only painting = a Who took part in painting + swimming = b Who took part in painting = a + b + d + e Who took part in all 3 = e a + b + e + d = 3500 [Given] Noe 5% of 3500 = b [Given] So b = 175 So a + e + d = 3500 – 175 = 3325 …….. (1) Next: f = 150/100 * e [Given] c = g – 100 [Given] f + g = 3675 [Given] c – e = 2950 [Given] Here we have 4 variables (c, e, f, g) and 4 equations Solve all equations to find the values c = 3200, e = 250, f = 375, g = 3300 So from (1), a + d = 3075 a = 1625 + d [Given] Now from these 2 equations a = 2500, d = 575 So a = 2500, b = 175, c = 3200, d = 575, e = 250, f = 375, g = 3300
So here we need d : f 575 : 375 = 23 : 15
Question 2 of 35
2. Question
2 points
Directions (1-5): Study the following carefully to answer the questions that follow:
Some students participated in three different activities – painting, swimming and dancing. The total students who took part in painting is 3500 of which 5% students took part in both painting and swimming only. The number of students who took part in both dancing and swimming only is 50% greater than the number of students who took part in all 3 activities. The number of students who took part in only swimming is 100 less than the number of students who took part in only dancing. The total number of students who took part in dancing but not painting is 3675. The number of students who took part in only swimming is 2950 more than the number of students who took part in all three activities. The number of students who took part in painting only is 1925 more than the number of students who took part in painting and dancing only.
What is the number of people who took part in more than one activity?
Correct
a = 2500, b = 175, c = 3200, d = 575, e = 250, f = 375, g = 3300
SoÂ who took part in more than one activity = b + d + e + f = 175 + 575 + 250 + 375 = 1375
Incorrect
a = 2500, b = 175, c = 3200, d = 575, e = 250, f = 375, g = 3300
SoÂ who took part in more than one activity = b + d + e + f = 175 + 575 + 250 + 375 = 1375
Unattempted
a = 2500, b = 175, c = 3200, d = 575, e = 250, f = 375, g = 3300
SoÂ who took part in more than one activity = b + d + e + f = 175 + 575 + 250 + 375 = 1375
Question 3 of 35
3. Question
2 points
Directions (1-5): Study the following carefully to answer the questions that follow:
Some students participated in three different activities – painting, swimming and dancing. The total students who took part in painting is 3500 of which 5% students took part in both painting and swimming only. The number of students who took part in both dancing and swimming only is 50% greater than the number of students who took part in all 3 activities. The number of students who took part in only swimming is 100 less than the number of students who took part in only dancing. The total number of students who took part in dancing but not painting is 3675. The number of students who took part in only swimming is 2950 more than the number of students who took part in all three activities. The number of students who took part in painting only is 1925 more than the number of students who took part in painting and dancing only.
What is the number of people who took part in only one activity?
Correct
a = 2500, b = 175, c = 3200, d = 575, e = 250, f = 375, g = 3300
People who took part in only one activity = a + c + g = 2500 + 3200 + 3300 = 9000
Incorrect
a = 2500, b = 175, c = 3200, d = 575, e = 250, f = 375, g = 3300
People who took part in only one activity = a + c + g = 2500 + 3200 + 3300 = 9000
Unattempted
a = 2500, b = 175, c = 3200, d = 575, e = 250, f = 375, g = 3300
People who took part in only one activity = a + c + g = 2500 + 3200 + 3300 = 9000
Question 4 of 35
4. Question
2 points
Directions (1-5): Study the following carefully to answer the questions that follow:
Some students participated in three different activities – painting, swimming and dancing. The total students who took part in painting is 3500 of which 5% students took part in both painting and swimming only. The number of students who took part in both dancing and swimming only is 50% greater than the number of students who took part in all 3 activities. The number of students who took part in only swimming is 100 less than the number of students who took part in only dancing. The total number of students who took part in dancing but not painting is 3675. The number of students who took part in only swimming is 2950 more than the number of students who took part in all three activities. The number of students who took part in painting only is 1925 more than the number of students who took part in painting and dancing only.
What is the different between the number of people who took part in all three activities and who took part in painting and swimming only?
Correct
a = 2500, b = 175, c = 3200, d = 575, e = 250, f = 375, g = 3300
Required difference = Â e – b = 250 – 175 = 75
Incorrect
a = 2500, b = 175, c = 3200, d = 575, e = 250, f = 375, g = 3300
Required difference = Â e – b = 250 – 175 = 75
Unattempted
a = 2500, b = 175, c = 3200, d = 575, e = 250, f = 375, g = 3300
Required difference = Â e – b = 250 – 175 = 75
Question 5 of 35
5. Question
2 points
Directions (1-5): Study the following carefully to answer the questions that follow:
Some students participated in three different activities – painting, swimming and dancing. The total students who took part in painting is 3500 of which 5% students took part in both painting and swimming only. The number of students who took part in both dancing and swimming only is 50% greater than the number of students who took part in all 3 activities. The number of students who took part in only swimming is 100 less than the number of students who took part in only dancing. The total number of students who took part in dancing but not painting is 3675. The number of students who took part in only swimming is 2950 more than the number of students who took part in all three activities. The number of students who took part in painting only is 1925 more than the number of students who took part in painting and dancing only.
Number of people who took part in painting and dancing only is what percent greater than number of people who took part in swimming and dancing only?
Correct
a = 2500, b = 175, c = 3200, d = 575, e = 250, f = 375, g = 3300
Required % = (575- 375)/375 * 100 = 53 1/3%
Incorrect
a = 2500, b = 175, c = 3200, d = 575, e = 250, f = 375, g = 3300
Required % = (575- 375)/375 * 100 = 53 1/3%
Unattempted
a = 2500, b = 175, c = 3200, d = 575, e = 250, f = 375, g = 3300
Required % = (575- 375)/375 * 100 = 53 1/3%
Question 6 of 35
6. Question
1 points
Directions (6-8): Each question below contains a statement followed by Quantity I and Quantity II. Find both to find the relationship among them. Mark your answer accordingly.
Quantity I: Cost Price of an article if it is sold making a loss of 20% given that if the cost price was 15% less, a lossÂ of Rs 6 wasÂ made. Quantity II: Â Labeled Price of an article of cost price Rs 240 on which after giving a discount of 10% a profitÂ of 20% is made.
Correct
I: Let CP = Rs 100, then at 20% loss, SP = Rs 80
Now if CP is 15% less, means CP = Rs 85, then loss is = 85 â€“ 80 = Rs 5
but given loss is Rs 12
So if loss is Rs 5, then CP = Rs 100
If loss is Rs 12, then CP is 100/5 * 6 = Rs 120
II: Use formula MP = (100+profit%)/(100-dicount%) * CP
So MP = (100+20)/(100-10) * 240 = Rs 320
Hence II > I
Incorrect
I: Let CP = Rs 100, then at 20% loss, SP = Rs 80
Now if CP is 15% less, means CP = Rs 85, then loss is = 85 â€“ 80 = Rs 5
but given loss is Rs 12
So if loss is Rs 5, then CP = Rs 100
If loss is Rs 12, then CP is 100/5 * 6 = Rs 120
II: Use formula MP = (100+profit%)/(100-dicount%) * CP
So MP = (100+20)/(100-10) * 240 = Rs 320
Hence II > I
Unattempted
I: Let CP = Rs 100, then at 20% loss, SP = Rs 80
Now if CP is 15% less, means CP = Rs 85, then loss is = 85 â€“ 80 = Rs 5
but given loss is Rs 12
So if loss is Rs 5, then CP = Rs 100
If loss is Rs 12, then CP is 100/5 * 6 = Rs 120
II: Use formula MP = (100+profit%)/(100-dicount%) * CP
So MP = (100+20)/(100-10) * 240 = Rs 320
Hence II > I
Question 7 of 35
7. Question
1 points
Directions (6-8): Each question below contains a statement followed by Quantity I and Quantity II. Find both to find the relationship among them. Mark your answer accordingly.
Quantity I: Speed of boat in still water if in a total ofÂ 12 hours, it can cover a distance of 36 km going downstream and back. Given the speed of current isÂ 4 km/hr Quantity II: Â Average speed of a boy from his home to school if his average speed is 10 km/hr from school to home and he covers a total of 30 km in 3 hours.
Correct
I: Let speed of boat = x km/hr So 36/(x+4) + 36/(x-4) = 12 Solve, x = 8 km/hr II : Distance from home to school is 30/2 = 15 km Let speed from home to school is x km/hr So using distance = total time * average speed 15 = 3 *[10*x/(10+x)] Solve, x = 10 km/hr Hence II > I
Incorrect
I: Let speed of boat = x km/hr So 36/(x+4) + 36/(x-4) = 12 Solve, x = 8 km/hr II : Distance from home to school is 30/2 = 15 km Let speed from home to school is x km/hr So using distance = total time * average speed 15 = 3 *[10*x/(10+x)] Solve, x = 10 km/hr Hence II > I
Unattempted
I: Let speed of boat = x km/hr So 36/(x+4) + 36/(x-4) = 12 Solve, x = 8 km/hr II : Distance from home to school is 30/2 = 15 km Let speed from home to school is x km/hr So using distance = total time * average speed 15 = 3 *[10*x/(10+x)] Solve, x = 10 km/hr Hence II > I
Question 8 of 35
8. Question
1 points
Directions (6-8): Each question below contains a statement followed by Quantity I and Quantity II. Find both to find the relationship among them. Mark your answer accordingly.
Quantity I: Time taken by A to complete 1/5^{th} of work if B takes 6 days to complete 3/5^{th}of work and together they take 5 days to complete 3/4^{th} of work Quantity II: Â Time taken by a train to cross a platform of length 60 km given that it crosses a pole in two and a half hours running at 60 km/hr
Correct
I: A and B completes 3/4^{th} work in 5 days, so complete 1 work in 4/3 * 5 = 20/3 days B complete 3/5 work in 6 days, so complete work in 5/3 * 6Â = 10 days So in 1 day A completes = 3/20 â€“ 1/10 = 1/20 So to complete 1/5^{th} work = 1/5 * 20 = 4 days II: length of train = 2.5 * 60 = 150 km So time taken to cross platform of length 60 km with speed 60 km/hr = (150+60)/60 = 3.5 hrs Hence I > II
Incorrect
I: A and B completes 3/4^{th} work in 5 days, so complete 1 work in 4/3 * 5 = 20/3 days B complete 3/5 work in 6 days, so complete work in 5/3 * 6Â = 10 days So in 1 day A completes = 3/20 â€“ 1/10 = 1/20 So to complete 1/5^{th} work = 1/5 * 20 = 4 days II: length of train = 2.5 * 60 = 150 km So time taken to cross platform of length 60 km with speed 60 km/hr = (150+60)/60 = 3.5 hrs Hence I > II
Unattempted
I: A and B completes 3/4^{th} work in 5 days, so complete 1 work in 4/3 * 5 = 20/3 days B complete 3/5 work in 6 days, so complete work in 5/3 * 6Â = 10 days So in 1 day A completes = 3/20 â€“ 1/10 = 1/20 So to complete 1/5^{th} work = 1/5 * 20 = 4 days II: length of train = 2.5 * 60 = 150 km So time taken to cross platform of length 60 km with speed 60 km/hr = (150+60)/60 = 3.5 hrs Hence I > II
Question 9 of 35
9. Question
1 points
Directions (9-11): Study the following carefully to answer the questions that follow:
A, B, and C started a business by investing Rs X, Rs (X+800), and Rs (X+1200) respectively. After 8 months of the start of business, A Â added Rs 600 and B withdrew Rs 600 respectively in their respective investments. After a year, out of the total profit of Rs 23,000, B got his shares equal to Rs 7500.
Find X.
Correct
Ratio of shares of A : B : C is X*8 + Â (X+600)*4 : (X+800)*8 + (X+200)*4 : (X+1200)*12 12X + 2400 : 12X + 7200 : 12X + 14400 (X+200) : (X+600) : (X+1200) So according to question: (X+600)/(X+200 + X+600 + X+1200) * 23000 = 7500 Solve, X = Rs 2400
Incorrect
Ratio of shares of A : B : C is X*8 + Â (X+600)*4 : (X+800)*8 + (X+200)*4 : (X+1200)*12 12X + 2400 : 12X + 7200 : 12X + 14400 (X+200) : (X+600) : (X+1200) So according to question: (X+600)/(X+200 + X+600 + X+1200) * 23000 = 7500 Solve, X = Rs 2400
Unattempted
Ratio of shares of A : B : C is X*8 + Â (X+600)*4 : (X+800)*8 + (X+200)*4 : (X+1200)*12 12X + 2400 : 12X + 7200 : 12X + 14400 (X+200) : (X+600) : (X+1200) So according to question: (X+600)/(X+200 + X+600 + X+1200) * 23000 = 7500 Solve, X = Rs 2400
Question 10 of 35
10. Question
1 points
Directions (9-11): Study the following carefully to answer the questions that follow:
A, B, and C started a business by investing Rs X, Rs (X+800), and Rs (X+1200) respectively. After 8 months of the start of business, A Â added Rs 600 and B withdrew Rs 600 respectively in their respective investments. After a year, out of the total profit of Rs 23,000, B got his shares equal to Rs 7500.
What is the difference between the shares of A and C from the total profit?
Correct
X = Rs 2400 SoÂ Ratio of shares of A : B : C is 2400*8 + Â (2400+600)*4 : (2400+800)*8 + (2400+200)*4 : (2400+1200)*12
13 : 15 : 18
SoÂ difference between the shares of A and C = (18-15)/(13+15+18) * 23000 = Rs 2750
Incorrect
X = Rs 2400 SoÂ Ratio of shares of A : B : C is 2400*8 + Â (2400+600)*4 : (2400+800)*8 + (2400+200)*4 : (2400+1200)*12
13 : 15 : 18
SoÂ difference between the shares of A and C = (18-15)/(13+15+18) * 23000 = Rs 2750
Unattempted
X = Rs 2400 SoÂ Ratio of shares of A : B : C is 2400*8 + Â (2400+600)*4 : (2400+800)*8 + (2400+200)*4 : (2400+1200)*12
13 : 15 : 18
SoÂ difference between the shares of A and C = (18-15)/(13+15+18) * 23000 = Rs 2750
Question 11 of 35
11. Question
1 points
Directions (9-11): Study the following carefully to answer the questions that follow:
A, B, and C started a business by investing Rs X, Rs (X+800), and Rs (X+1200) respectively. After 8 months of the start of business, A Â added Rs 600 and B withdrew Rs 600 respectively in their respective investments. After a year, out of the total profit of Rs 23,000, B got his shares equal to Rs 7500.
If all of A, B and C would have invested their initial investments for 12 months, and also another partner partner D joined them at the same time by investing Rs 2800, then find the share of B and D together from the total annual profit of Rs 22,800?
Correct
Ratio of shares of A : B : C : D is 2400 : 3200 : 3600 : 2800 6 : 8 : 9 : 7 So required answer = (8+7)/(6+8+9+7) * 22800 = Rs 11,400
Incorrect
Ratio of shares of A : B : C : D is 2400 : 3200 : 3600 : 2800 6 : 8 : 9 : 7 So required answer = (8+7)/(6+8+9+7) * 22800 = Rs 11,400
Unattempted
Ratio of shares of A : B : C : D is 2400 : 3200 : 3600 : 2800 6 : 8 : 9 : 7 So required answer = (8+7)/(6+8+9+7) * 22800 = Rs 11,400
Question 12 of 35
12. Question
2 points
Directions (12-16):Â Study the following bar graphÂ carefully and answer the questions that follow:
If the cost price of P and R is equal to Rs 960 each. Find the difference in their Market Prices.
Correct
For P => Profit% = 30% = 3/10 [CP = 10, SP = 10+3 = 13] Discount = 20% = 1/5 [MP = 5, SP = 5-1 = 4] Make SP same CP : SP : MP is 40 : 52 : 65 â€¦â€¦â€¦â€¦â€¦â€¦(1) Now for R => Profit% = 20% = 1/5 [CP = 5, SP = 5+1 = 6] Discount = 10% = 1/10 [MP = 10, SP = 10-1 = 9] Make SP same CP : SP : MP is 15 : 18 : 20â€¦â€¦â€¦â€¦â€¦â€¦.(2) Make CP of P and R same by multiplying eq. (1) by 3 and (2) by 8, gives For P: CP : SP : MP is 120 : 156 : 195 And For R: CP : SP : MP is 120 : 144 : 160 So 120 = 960 [as given in question] => 1 = 8 Difference in MP = 195-160 = 35, so => 35 = 35*8 = Rs 280
Incorrect
For P => Profit% = 30% = 3/10 [CP = 10, SP = 10+3 = 13] Discount = 20% = 1/5 [MP = 5, SP = 5-1 = 4] Make SP same CP : SP : MP is 40 : 52 : 65 â€¦â€¦â€¦â€¦â€¦â€¦(1) Now for R => Profit% = 20% = 1/5 [CP = 5, SP = 5+1 = 6] Discount = 10% = 1/10 [MP = 10, SP = 10-1 = 9] Make SP same CP : SP : MP is 15 : 18 : 20â€¦â€¦â€¦â€¦â€¦â€¦.(2) Make CP of P and R same by multiplying eq. (1) by 3 and (2) by 8, gives For P: CP : SP : MP is 120 : 156 : 195 And For R: CP : SP : MP is 120 : 144 : 160 So 120 = 960 [as given in question] => 1 = 8 Difference in MP = 195-160 = 35, so => 35 = 35*8 = Rs 280
Unattempted
For P => Profit% = 30% = 3/10 [CP = 10, SP = 10+3 = 13] Discount = 20% = 1/5 [MP = 5, SP = 5-1 = 4] Make SP same CP : SP : MP is 40 : 52 : 65 â€¦â€¦â€¦â€¦â€¦â€¦(1) Now for R => Profit% = 20% = 1/5 [CP = 5, SP = 5+1 = 6] Discount = 10% = 1/10 [MP = 10, SP = 10-1 = 9] Make SP same CP : SP : MP is 15 : 18 : 20â€¦â€¦â€¦â€¦â€¦â€¦.(2) Make CP of P and R same by multiplying eq. (1) by 3 and (2) by 8, gives For P: CP : SP : MP is 120 : 156 : 195 And For R: CP : SP : MP is 120 : 144 : 160 So 120 = 960 [as given in question] => 1 = 8 Difference in MP = 195-160 = 35, so => 35 = 35*8 = Rs 280
Question 13 of 35
13. Question
2 points
Directions (12-16):Â Study the following bar graphÂ carefully and answer the questions that follow:
If the market price of Q is 250% of market price of R, then find the selling price of R, if market price of Q is Rs 3500.
Correct
For Q: CPâ€¦.SPâ€¦..MP is 36â€¦â€¦..45â€¦â€¦â€¦50 â€¦â€¦â€¦â€¦â€¦â€¦â€¦..(1) For R: CPâ€¦.SPâ€¦..MP is 15â€¦â€¦..18â€¦â€¦â€¦20 â€¦â€¦â€¦..â€¦â€¦â€¦â€¦(2) MP of Q is 250% of R 250% of 20 = 50 Which is same as in equation (1) CPâ€¦â€¦â€¦SPâ€¦â€¦â€¦MP is 36â€¦â€¦..45â€¦â€¦â€¦50 Now 50 = 3500 1 = 700 So 18 = 1260
Incorrect
For Q: CPâ€¦.SPâ€¦..MP is 36â€¦â€¦..45â€¦â€¦â€¦50 â€¦â€¦â€¦â€¦â€¦â€¦â€¦..(1) For R: CPâ€¦.SPâ€¦..MP is 15â€¦â€¦..18â€¦â€¦â€¦20 â€¦â€¦â€¦..â€¦â€¦â€¦â€¦(2) MP of Q is 250% of R 250% of 20 = 50 Which is same as in equation (1) CPâ€¦â€¦â€¦SPâ€¦â€¦â€¦MP is 36â€¦â€¦..45â€¦â€¦â€¦50 Now 50 = 3500 1 = 700 So 18 = 1260
Unattempted
For Q: CPâ€¦.SPâ€¦..MP is 36â€¦â€¦..45â€¦â€¦â€¦50 â€¦â€¦â€¦â€¦â€¦â€¦â€¦..(1) For R: CPâ€¦.SPâ€¦..MP is 15â€¦â€¦..18â€¦â€¦â€¦20 â€¦â€¦â€¦..â€¦â€¦â€¦â€¦(2) MP of Q is 250% of R 250% of 20 = 50 Which is same as in equation (1) CPâ€¦â€¦â€¦SPâ€¦â€¦â€¦MP is 36â€¦â€¦..45â€¦â€¦â€¦50 Now 50 = 3500 1 = 700 So 18 = 1260
Question 14 of 35
14. Question
2 points
Directions (12-16):Â Study the following bar graphÂ carefully and answer the questions that follow:
Find the ratio of selling price of Q and T if the cost price of both is same.
Correct
For Q: CPâ€¦.SPâ€¦..MP is 36â€¦â€¦..45â€¦â€¦â€¦50 â€¦â€¦â€¦â€¦â€¦â€¦â€¦..(1) For T: CPâ€¦..SPâ€¦..MP is 12 â€¦â€¦..15â€¦â€¦â€¦.20 â€¦â€¦â€¦â€¦â€¦â€¦â€¦(2) Make CP same, Multiply eq. (2) by 3 (1) gives.,, 36â€¦â€¦..45â€¦â€¦â€¦50 (2) gives,, 36â€¦â€¦â€¦..45â€¦..â€¦â€¦30 SP of S : R is 45 : 45 = 1 : 1
Incorrect
For Q: CPâ€¦.SPâ€¦..MP is 36â€¦â€¦..45â€¦â€¦â€¦50 â€¦â€¦â€¦â€¦â€¦â€¦â€¦..(1) For T: CPâ€¦..SPâ€¦..MP is 12 â€¦â€¦..15â€¦â€¦â€¦.20 â€¦â€¦â€¦â€¦â€¦â€¦â€¦(2) Make CP same, Multiply eq. (2) by 3 (1) gives.,, 36â€¦â€¦..45â€¦â€¦â€¦50 (2) gives,, 36â€¦â€¦â€¦..45â€¦..â€¦â€¦30 SP of S : R is 45 : 45 = 1 : 1
Unattempted
For Q: CPâ€¦.SPâ€¦..MP is 36â€¦â€¦..45â€¦â€¦â€¦50 â€¦â€¦â€¦â€¦â€¦â€¦â€¦..(1) For T: CPâ€¦..SPâ€¦..MP is 12 â€¦â€¦..15â€¦â€¦â€¦.20 â€¦â€¦â€¦â€¦â€¦â€¦â€¦(2) Make CP same, Multiply eq. (2) by 3 (1) gives.,, 36â€¦â€¦..45â€¦â€¦â€¦50 (2) gives,, 36â€¦â€¦â€¦..45â€¦..â€¦â€¦30 SP of S : R is 45 : 45 = 1 : 1
Question 15 of 35
15. Question
2 points
Directions (12-16):Â Study the following bar graphÂ carefully and answer the questions that follow:
Find the marketÂ price of P if the ratio of costÂ price of P and T is 10 : 3 and the cost price of T is Rs 3960.
Correct
For P: CPâ€¦..SPâ€¦..MP is 40 â€¦â€¦..52â€¦â€¦â€¦.65 â€¦â€¦â€¦â€¦â€¦â€¦â€¦(1) For T: CPâ€¦..SPâ€¦..MP is 12 â€¦â€¦..15â€¦â€¦â€¦.20 â€¦â€¦â€¦â€¦â€¦â€¦â€¦(2) Here already ratio of CP of P : T is 10 : 3 So, 12 == 3960 1 == 330 MP of P = 65 == 21450
Incorrect
For P: CPâ€¦..SPâ€¦..MP is 40 â€¦â€¦..52â€¦â€¦â€¦.65 â€¦â€¦â€¦â€¦â€¦â€¦â€¦(1) For T: CPâ€¦..SPâ€¦..MP is 12 â€¦â€¦..15â€¦â€¦â€¦.20 â€¦â€¦â€¦â€¦â€¦â€¦â€¦(2) Here already ratio of CP of P : T is 10 : 3 So, 12 == 3960 1 == 330 MP of P = 65 == 21450
Unattempted
For P: CPâ€¦..SPâ€¦..MP is 40 â€¦â€¦..52â€¦â€¦â€¦.65 â€¦â€¦â€¦â€¦â€¦â€¦â€¦(1) For T: CPâ€¦..SPâ€¦..MP is 12 â€¦â€¦..15â€¦â€¦â€¦.20 â€¦â€¦â€¦â€¦â€¦â€¦â€¦(2) Here already ratio of CP of P : T is 10 : 3 So, 12 == 3960 1 == 330 MP of P = 65 == 21450
Question 16 of 35
16. Question
2 points
Directions (12-16):Â Study the following bar graphÂ carefully and answer the questions that follow:
If the cost price of R and T is same, then find how much % the selling price of R is more or less than that of T.
Correct
For R:
CPâ€¦..SPâ€¦..MP isÂ 15………18……….20â€¦â€¦â€¦â€¦â€¦â€¦.(1)
For T:
CPâ€¦..SPâ€¦..MP is 12 â€¦â€¦..15â€¦â€¦â€¦.20 â€¦â€¦â€¦â€¦â€¦â€¦(2)
Make CP same, Multiply eq. (1) by 4 and (2) by 5
R => 60……..72………..80
T => 60……..75………..100
So required % = (75-72)/75 * 100 = 4%
Incorrect
For R:
CPâ€¦..SPâ€¦..MP isÂ 15………18……….20â€¦â€¦â€¦â€¦â€¦â€¦.(1)
For T:
CPâ€¦..SPâ€¦..MP is 12 â€¦â€¦..15â€¦â€¦â€¦.20 â€¦â€¦â€¦â€¦â€¦â€¦(2)
Make CP same, Multiply eq. (1) by 4 and (2) by 5
R => 60……..72………..80
T => 60……..75………..100
So required % = (75-72)/75 * 100 = 4%
Unattempted
For R:
CPâ€¦..SPâ€¦..MP isÂ 15………18……….20â€¦â€¦â€¦â€¦â€¦â€¦.(1)
For T:
CPâ€¦..SPâ€¦..MP is 12 â€¦â€¦..15â€¦â€¦â€¦.20 â€¦â€¦â€¦â€¦â€¦â€¦(2)
Make CP same, Multiply eq. (1) by 4 and (2) by 5
R => 60……..72………..80
T => 60……..75………..100
So required % = (75-72)/75 * 100 = 4%
Question 17 of 35
17. Question
2 points
Directions (17-21): Study the following table to answer the questions that follow: The table shows the employees information in 5 different departments of a company.
If number of males and females who left the company from department A is equal, find the total number of males from departments C and A who did not left the job?
Correct
females who left from A = 12% of 350 = 42
So males who left from A also equals 42
So males who did not left from A = 420 – 42 = 378
Males who did not left from C = 480 – 5% of 480 = 456
Required total = 378 + 456 = 834
Incorrect
females who left from A = 12% of 350 = 42
So males who left from A also equals 42
So males who did not left from A = 420 – 42 = 378
Males who did not left from C = 480 – 5% of 480 = 456
Required total = 378 + 456 = 834
Unattempted
females who left from A = 12% of 350 = 42
So males who left from A also equals 42
So males who did not left from A = 420 – 42 = 378
Males who did not left from C = 480 – 5% of 480 = 456
Required total = 378 + 456 = 834
Question 18 of 35
18. Question
2 points
Directions (17-21): Study the following table to answer the questions that follow: The table shows the employees information in 5 different departments of a company.
The number of males who left the company from departments C and D is in the ratio 8 : 9 respectively. Total number of employees in department D and who left from D is 870 and 48 respectively. What % of males did not left from department D?
Correct
Males who left from C = 5% of 480 = 24
So in D = 9/8 * 24 = 27 [ratio is 8 : 9]
Let number of males in D = x, so females in D = (870-x)
Let y% of males from D left the company
So y% of x = 27
And
y% of x + 5% of (870-x) = 48
So 27 +Â 5% of (870-x) = 48
Solve, x = 450
Now y% of 450 = 27
Solve, y = 6
6% left, so who did not left = 94%
Incorrect
Males who left from C = 5% of 480 = 24
So in D = 9/8 * 24 = 27 [ratio is 8 : 9]
Let number of males in D = x, so females in D = (870-x)
Let y% of males from D left the company
So y% of x = 27
And
y% of x + 5% of (870-x) = 48
So 27 +Â 5% of (870-x) = 48
Solve, x = 450
Now y% of 450 = 27
Solve, y = 6
6% left, so who did not left = 94%
Unattempted
Males who left from C = 5% of 480 = 24
So in D = 9/8 * 24 = 27 [ratio is 8 : 9]
Let number of males in D = x, so females in D = (870-x)
Let y% of males from D left the company
So y% of x = 27
And
y% of x + 5% of (870-x) = 48
So 27 +Â 5% of (870-x) = 48
Solve, x = 450
Now y% of 450 = 27
Solve, y = 6
6% left, so who did not left = 94%
Question 19 of 35
19. Question
2 points
Directions (17-21): Study the following table to answer the questions that follow: The table shows the employees information in 5 different departments of a company.
Number of graduate males in department C is 127 more than number of graduate females in department B. If 33 1/3% of males who left from department C are post-graduates, then find the number of post-graduates who did not left from department C?
Correct
Number of graduate females in B = 55% of 380 = 209 SoÂ Number of graduate males in department C = 209 + 127 = 336 So post-graduate males in department C = 480 – 336 = 144 Total number of males who left from C = 5% of 480 = 24 Given 33 1/3% of 24 = post-graduates So those males who left from C and are post-graduates =Â 33 1/3% of 24 = 8 So who did not left = 144 – 8 = 136
Incorrect
Number of graduate females in B = 55% of 380 = 209 SoÂ Number of graduate males in department C = 209 + 127 = 336 So post-graduate males in department C = 480 – 336 = 144 Total number of males who left from C = 5% of 480 = 24 Given 33 1/3% of 24 = post-graduates So those males who left from C and are post-graduates =Â 33 1/3% of 24 = 8 So who did not left = 144 – 8 = 136
Unattempted
Number of graduate females in B = 55% of 380 = 209 SoÂ Number of graduate males in department C = 209 + 127 = 336 So post-graduate males in department C = 480 – 336 = 144 Total number of males who left from C = 5% of 480 = 24 Given 33 1/3% of 24 = post-graduates So those males who left from C and are post-graduates =Â 33 1/3% of 24 = 8 So who did not left = 144 – 8 = 136
Question 20 of 35
20. Question
2 points
Directions (17-21): Study the following table to answer the questions that follow: The table shows the employees information in 5 different departments of a company.
29% of number of females who left from department E are graduates. If % of number of graduate females who left from department E with respect to total number of graduate females from department E is 4%, then find the number of females from department E who left the company. (Number of females in E = 400).
Correct
Let x% females left the company from dept E Given:
Solve, x = 12% SoÂ number of females from department F who left the company = 12/100 * 400 = 48
Incorrect
Let x% females left the company from dept E Given:
Solve, x = 12% SoÂ number of females from department F who left the company = 12/100 * 400 = 48
Unattempted
Let x% females left the company from dept E Given:
Solve, x = 12% SoÂ number of females from department F who left the company = 12/100 * 400 = 48
Question 21 of 35
21. Question
2 points
Directions (17-21): Study the following table to answer the questions that follow: The table shows the employees information in 5 different departments of a company.
If there are total 1000 employees in department C, find the total number of female employees in departments B and C or company.
Correct
Total employees in C = 1000 So number of females = 1000 – 480 = 520 So required total = 55% of 380 + 80% of 520 = 625
Incorrect
Total employees in C = 1000 So number of females = 1000 – 480 = 520 So required total = 55% of 380 + 80% of 520 = 625
Unattempted
Total employees in C = 1000 So number of females = 1000 – 480 = 520 So required total = 55% of 380 + 80% of 520 = 625
Question 22 of 35
22. Question
2 points
Directions (22-26): In each of the following questions, a question is followed by three statements numbered I, II and III. Read all the statements and answer accordingly.
What is the speed of boat in still water? Statement I: The boat can cover 16 km downstream distance in 2 hours. Statement II: Speed of the stream is one-thirdÂ the speed of boat in still water. Statement III: The boat can cover 16 km upstream distance in 4 hours.
Correct
Let speed of boat = u, and stream = v From I: u + v = 16/2 = 8 km/hr From II: v = u/3 From III: u â€“ v = 16/4 = 4 So solving I and II â€˜uâ€™ can be found. Similarly by solving II and III and by solving I and III
Incorrect
Let speed of boat = u, and stream = v From I: u + v = 16/2 = 8 km/hr From II: v = u/3 From III: u â€“ v = 16/4 = 4 So solving I and II â€˜uâ€™ can be found. Similarly by solving II and III and by solving I and III
Unattempted
Let speed of boat = u, and stream = v From I: u + v = 16/2 = 8 km/hr From II: v = u/3 From III: u â€“ v = 16/4 = 4 So solving I and II â€˜uâ€™ can be found. Similarly by solving II and III and by solving I and III
Question 23 of 35
23. Question
2 points
Directions (22-26): In each of the following questions, a question is followed by three statements numbered I, II and III. Read all the statements and answer accordingly.
A person borrowed some money at compound interest for 2 years. What will be the amount required to return after 2 years? Statement I: If the amount was borrowed at simple interest, then after 5 years Rs 600 was required to pay as simple interest.Â
Statement II: The rate of interest is 6% per annum Statement III: The sum of money borrowed is 10 times the amount required to be paid as simple interest after 2 years.
Correct
From I:Â SI = 600, R = 5 years
So 600 = P*R*5/100 So P*R = 12000 From II: RÂ = 6% So from I andÂ II, get P, and then from P, R and T, get amount at CI From III: P = 10 SI
SI = P*R*T/100
So SI = (10SI) * R * 2/100
From here , R = 5%
So from I andÂ III, get P, and then from P, R and T, get amount at CI
Incorrect
From I:Â SI = 600, R = 5 years
So 600 = P*R*5/100 So P*R = 12000 From II: RÂ = 6% So from I andÂ II, get P, and then from P, R and T, get amount at CI From III: P = 10 SI
SI = P*R*T/100
So SI = (10SI) * R * 2/100
From here , R = 5%
So from I andÂ III, get P, and then from P, R and T, get amount at CI
Unattempted
From I:Â SI = 600, R = 5 years
So 600 = P*R*5/100 So P*R = 12000 From II: RÂ = 6% So from I andÂ II, get P, and then from P, R and T, get amount at CI From III: P = 10 SI
SI = P*R*T/100
So SI = (10SI) * R * 2/100
From here , R = 5%
So from I andÂ III, get P, and then from P, R and T, get amount at CI
Question 24 of 35
24. Question
2 points
Directions (22-26): In each of the following questions, a question is followed by three statements numbered I, II and III. Read all the statements and answer accordingly.
What was the profit earned by selling an article? Statement I: The article was sold for Rs 950 after getting a discount of 5% on the labelled price. Statement II:Â The article was bought for Rs 540 after getting a discount of 10% Statement III: A profit of 2% is made on the labelled price in buying that article.
Correct
From I and III: I: we can find the MP of article as (100/95) Ã— 950 = Rs 1000 From III: we can find the CP of article by using the MP from statement I as (102/100) Ã— 1000 = Rs 1020 Now we have both SP and CP to find the profit%
From II: CP = 540, discount = 10%
Incorrect
From I and III: I: we can find the MP of article as (100/95) Ã— 950 = Rs 1000 From III: we can find the CP of article by using the MP from statement I as (102/100) Ã— 1000 = Rs 1020 Now we have both SP and CP to find the profit%
From II: CP = 540, discount = 10%
Unattempted
From I and III: I: we can find the MP of article as (100/95) Ã— 950 = Rs 1000 From III: we can find the CP of article by using the MP from statement I as (102/100) Ã— 1000 = Rs 1020 Now we have both SP and CP to find the profit%
From II: CP = 540, discount = 10%
Question 25 of 35
25. Question
2 points
Directions (22-26): In each of the following questions, a question is followed by three statements numbered I, II and III. Read all the statements and answer accordingly.
What is the cost of flooring a rectangular hall? Statement I: The ratio of length and breadth of the hall is 5:4.
Statement II: The length of the hall is 50 metres and the cost of flooring is Rs. 1000 per square metre.
Statement III: The perimeter of the hall is 180 metres and the cost of flooring is Rs. 1000 per square metre.
Correct
Using any two statement, the length and breadth can be found. And Rate of flooring is also available.
Incorrect
Using any two statement, the length and breadth can be found. And Rate of flooring is also available.
Unattempted
Using any two statement, the length and breadth can be found. And Rate of flooring is also available.
Question 26 of 35
26. Question
2 points
Directions (22-26): In each of the following questions, a question is followed by three statements numbered I, II and III. Read all the statements and answer accordingly.
What is the principal amount? Statement I: The Simple Interest obtained on the principal after 2 years at 8% rate of interest is Rs 450 less than the compound interest obtained on the same principal after 2 years at 8% per annum. StatementII: The sum becomes double in 10 years at 6% per annum rate of simple interest. Statement III: The compound interest obtained on the principal amount is Rs 4540 after 2 years at the rate of 8% compounded annually.
Correct
From I : Pr^{2}/100^{2} = 450. So P can be found. From III: using the compound interest formula, P can be find out
Incorrect
From I : Pr^{2}/100^{2} = 450. So P can be found. From III: using the compound interest formula, P can be find out
Unattempted
From I : Pr^{2}/100^{2} = 450. So P can be found. From III: using the compound interest formula, P can be find out
Question 27 of 35
27. Question
2 points
Directions (27-31): The following bar graph depicts the percentage wise distribution of what people eat in their breakfast in 5 states. Study the bar graph and answer the questions that follow:
If the ratio of number of people who eat oats in states A and D is 5 : 9 respectively, then what is the ratio of number of people who eat wheat in these two states respectively?
Correct
Let number of people in state A = x, and that in D = y
So
(10% of x)/(12% if y) = 5/9
Solve, x/y = 2/3
So required ratio is
48% of x : 20% of y
Put value of x or y from above
Ratio is 8 : 5
Incorrect
Let number of people in state A = x, and that in D = y
So
(10% of x)/(12% if y) = 5/9
Solve, x/y = 2/3
So required ratio is
48% of x : 20% of y
Put value of x or y from above
Ratio is 8 : 5
Unattempted
Let number of people in state A = x, and that in D = y
So
(10% of x)/(12% if y) = 5/9
Solve, x/y = 2/3
So required ratio is
48% of x : 20% of y
Put value of x or y from above
Ratio is 8 : 5
Question 28 of 35
28. Question
2 points
Directions (27-31): The following bar graph depicts the percentage wise distribution of what people eat in their breakfast in 5 states. Study the bar graph and answer the questions that follow:
The number of people who eat cornflakes in state C is four-fifth ofÂ number of people who eat cornflakes in state E. If the number of people who eat wheat in state C is 96,000, then find the total number of people in state E?
Correct
Let total number of people in state C = x
So 40% of x = 96000
Solve, x = 2,40,000
Now
15% of 2,40,000 = 4/5 of 12% of y
Solve, y = 3,75,000 =Â total number of people in state E
Incorrect
Let total number of people in state C = x
So 40% of x = 96000
Solve, x = 2,40,000
Now
15% of 2,40,000 = 4/5 of 12% of y
Solve, y = 3,75,000 =Â total number of people in state E
Unattempted
Let total number of people in state C = x
So 40% of x = 96000
Solve, x = 2,40,000
Now
15% of 2,40,000 = 4/5 of 12% of y
Solve, y = 3,75,000 =Â total number of people in state E
Question 29 of 35
29. Question
2 points
Directions (27-31): The following bar graph depicts the percentage wise distribution of what people eat in their breakfast in 5 states. Study the bar graph and answer the questions that follow:
The number of people who eat millet in state B is 4200 more thanÂ number of people who eat millet in state D. If theÂ total number of people in state B is 10,000 more thanÂ total number of people in state D, find the total number of people who eat wheat in both states together?
Correct
Let number of people in state B = x, and that in D = y So 7% of x = 4200 + 6% of y Also x= 10,000 + y Solve both equations x = 3,60,000 and y = 3,50,000 So required total = 47% of 360000 + 20% of 350000 = 169200 + 70000 = 2,39,200
Incorrect
Let number of people in state B = x, and that in D = y So 7% of x = 4200 + 6% of y Also x= 10,000 + y Solve both equations x = 3,60,000 and y = 3,50,000 So required total = 47% of 360000 + 20% of 350000 = 169200 + 70000 = 2,39,200
Unattempted
Let number of people in state B = x, and that in D = y So 7% of x = 4200 + 6% of y Also x= 10,000 + y Solve both equations x = 3,60,000 and y = 3,50,000 So required total = 47% of 360000 + 20% of 350000 = 169200 + 70000 = 2,39,200
Question 30 of 35
30. Question
2 points
Directions (27-31): The following bar graph depicts the percentage wise distribution of what people eat in their breakfast in 5 states. Study the bar graph and answer the questions that follow:
The difference between the number of people who eat rice and cornflakes in state E is 1,62,000. What isÂ the number of people in state 3 except the number of people who eat cornflakes in the same state?
Correct
Let number of people in state E
Given: (48-12)% of x = 162000
Solve, x = 4,50,000
So required total = (4+20+48+ 16)% of 4,50,000 = 3,96,000
Incorrect
Let number of people in state E
Given: (48-12)% of x = 162000
Solve, x = 4,50,000
So required total = (4+20+48+ 16)% of 4,50,000 = 3,96,000
Unattempted
Let number of people in state E
Given: (48-12)% of x = 162000
Solve, x = 4,50,000
So required total = (4+20+48+ 16)% of 4,50,000 = 3,96,000
Question 31 of 35
31. Question
2 points
Directions (27-31): The following bar graph depicts the percentage wise distribution of what people eat in their breakfast in 5 states. Study the bar graph and answer the questions that follow:
The ratio between the number of people who eat rice in states A and B is 10 : 9 and ratioÂ between the number of people who eat oatsÂ in states B and D is 5 : 3. Find the ratio of number of people in state A : D : B respectively.
Correct
Let number of people in state A = x, in B = y, and in D = z
So
(25% of x)/(21% of y) = 10/9
Solve, x/y Â = 14/15
Also
(15% of y)/(12% of z) = 5/3
Solve, y/z Â = 4/3
x/y Â = 14/15 andÂ y/z Â = 4/3
So x : y : z = 14*4 : 15*4 : 15*3 = 56 : 60 : 45
So required ratio is 56 : 45 : 60
Incorrect
Let number of people in state A = x, in B = y, and in D = z
So
(25% of x)/(21% of y) = 10/9
Solve, x/y Â = 14/15
Also
(15% of y)/(12% of z) = 5/3
Solve, y/z Â = 4/3
x/y Â = 14/15 andÂ y/z Â = 4/3
So x : y : z = 14*4 : 15*4 : 15*3 = 56 : 60 : 45
So required ratio is 56 : 45 : 60
Unattempted
Let number of people in state A = x, in B = y, and in D = z
So
(25% of x)/(21% of y) = 10/9
Solve, x/y Â = 14/15
Also
(15% of y)/(12% of z) = 5/3
Solve, y/z Â = 4/3
x/y Â = 14/15 andÂ y/z Â = 4/3
So x : y : z = 14*4 : 15*4 : 15*3 = 56 : 60 : 45
So required ratio is 56 : 45 : 60
Question 32 of 35
32. Question
1 points
Directions (32-33): Study the following information to answer the questions that follow: An urn contains some balls colored white, blue and green. The probability of choosing a white ball is 1/2 and the probability of choosing a green ball is 1/4. There are 10 blue balls.
What is the probability of choosing one blue ball?
Correct
Probability of choosing one blue ball = 1 â€“ (1/2 + 1/4) = 1/4
Incorrect
Probability of choosing one blue ball = 1 â€“ (1/2 + 1/4) = 1/4
Unattempted
Probability of choosing one blue ball = 1 â€“ (1/2 + 1/4) = 1/4
Question 33 of 35
33. Question
1 points
Directions (32-33): Study the following information to answer the questions that follow: An urn contains some balls colored white, blue and green. The probability of choosing a white ball is 1/2 and the probability of choosing a green ball is 1/4. There are 10 blue balls.
If the balls are numbered 1, 2, â€¦. up to number of balls in the urn, what is the probability of choosing a ball containing a multiple of 3 and 5?
Correct
Probability of choosing one blue ball is 1/4
And total blue balls are 10. So with 10/40 we get probability as 1/4
So total balls must be 40
There are 30 balls in the urn.
Multiples of 3 up to 40 = 40/3 = 13 (take only whole number before the decimal part)
Multiples of 5 up to 40 = 40/5 = 18
Multiples of 15 (3Ã—5) up to 40 = 40/15 = 2
So total such numbers are = 13 + 18 â€“ 2 = 29
So required probability = 29/40
Incorrect
Probability of choosing one blue ball is 1/4
And total blue balls are 10. So with 10/40 we get probability as 1/4
So total balls must be 40
There are 30 balls in the urn.
Multiples of 3 up to 40 = 40/3 = 13 (take only whole number before the decimal part)
Multiples of 5 up to 40 = 40/5 = 18
Multiples of 15 (3Ã—5) up to 40 = 40/15 = 2
So total such numbers are = 13 + 18 â€“ 2 = 29
So required probability = 29/40
Unattempted
Probability of choosing one blue ball is 1/4
And total blue balls are 10. So with 10/40 we get probability as 1/4
So total balls must be 40
There are 30 balls in the urn.
Multiples of 3 up to 40 = 40/3 = 13 (take only whole number before the decimal part)
Multiples of 5 up to 40 = 40/5 = 18
Multiples of 15 (3Ã—5) up to 40 = 40/15 = 2
So total such numbers are = 13 + 18 â€“ 2 = 29
So required probability = 29/40
Question 34 of 35
34. Question
1 points
Directions (34-35): Study the following pie-chart and answer the questions that follow: The pie-chart shows the degree wise distribution of number of employees of a company in 5 different countries – A, B, C, D and E.
If there are 7440 employees in country D, then what is the number of employees in countries A and E together?
Correct
Let x is the number of employees in all countries together So 62/360 * x = 7440 Solve, x = 43200 So no. of employees in A+E = (35+55)/360 * 43200 = 10800
Incorrect
Let x is the number of employees in all countries together So 62/360 * x = 7440 Solve, x = 43200 So no. of employees in A+E = (35+55)/360 * 43200 = 10800
Unattempted
Let x is the number of employees in all countries together So 62/360 * x = 7440 Solve, x = 43200 So no. of employees in A+E = (35+55)/360 * 43200 = 10800
Question 35 of 35
35. Question
1 points
Directions (34-35): Study the following pie-chart and answer the questions that follow: The pie-chart shows the degree wise distribution of number of employees of a company in 5 different countries – A, B, C, D and E.
There are 43,200 employees in all 5 countries together. If the company opens it branch in one more country F, then the quadrant corresponding to country C becomes 84^{o} then find the degree value (approximately) of quadrant formed by country F in given pie-chart.
Correct
Employees in country C = 98/360 * 43200 = 11760 So now after adding country F to pie-chart, Let total number of employees in 6 countries together is now x So 84/360 * x = 11760 Solve, x = 50400 So number of employees in F =Â 50400 – 43200 = 7200 So y/360 * 50400 = 7200 Solve, y = 51^{o}
can you please explain question number 20..??
which step u dint get ?
mam actually it was just the misprint in the question that made me confuse… there is F in place of E…kindly correct it
yes its E