**Directions(1-5):** Find out the odd number from the series.

- 216,52,24,22,40,166
222164024166Option C

*0.25-2

*0.5-2

*1-2

*2-2

*4-2

42 should be in place of 40. - 16,116,516,1416,3216,5516
1651611632161416Option D

+10^2,+20^2,+30^2,+40^2,+50^2

3016 should be in place of 3216. - 16,37,67,95,134,181
37671613495Option B

+21,+26,+32,+39,+47

63 should be in place of 67. - 47,48,56,83,150,272,488
56150474883Option B

+1^3,+2^3, ,+3^3, ,+4^3, ,+5^3, ,+6^3

147 should be in place of 150. - 42,57,83,121,168,231
4257121231168Option C

+(4^2-1), +(5^2-1), +(6^2-1), +(7^2-1), +(8^2-1)

118 should be in place of 121. - A,B and C are colleagues. Find the age of A.

Statement I: B is 16 years older than C and A is 6 years younger than B. After 4 years, the respective ratio of the ages of A and B will become 20:23.

Statement II: Average of age of A,B and C is 34 years 8 months. Age of A is 10 years more than age of C.II is alone sufficient not I.Either I or II.I is alone sufficient not II.Neither I nor II.Both I and II.Option C

From I: Let the age of C be x years.

Age of B = x+16 years Age of A = x+10 years

Now, (x+16+4)/(x+10+4)= 23/20

=> x = 26

Age of A = 36 years I alone is sufficient to answer the question.

From II: Let the age of C be y years.

Age of A = y+10 years

Let the age of B be z years.

So,y+y+10+z = 104

II alone is not sufficient to answer the question. - 480 litres of mixture of milk and water is poured in a vessel of sufficiently large quantity (x+20) litres of water is added to the vessel. Find the value of x.

Statement I: Ratio of milk to water in the initial mixture is 7:5 resp. and ratio of milk to water in the final mixture is 14:13 resp.

Statement II: Final quantity of mixture in the vessel was (500+x) litres.Neither I nor II.Either I or II.II is alone sufficient not I.I is alone sufficient not II.Both I and II.Option D

From I:

Quantity of the mixture in the vessel initially = (7/12)*480 =280 litres and initial quantity of water in the vessel = 200 litres

Now, 280/(200+x+20)=14/13

=> x = 40

I is alone sufficient to get the answer of the question.

From II: 480+(x+20) = (500+x)

II alone is not sufficient to get the answer of the question. - A bag contains (x-2) black balls, (x+4) white balls, and (x+8) brown balls. Find the number of balls in the bag.

Statement I: The ratio of number of black balls to the number of white balls in the bag is 8:11.

Statement II: The total number of balls In the bag is 4 times the number of black balls in the bag.Both I and II.II is alone sufficient not I.Either I or II.I is alone sufficient not II.Neither I nor II.Option C

Total number of balls in the bag =(x-2)+(x+4)+(x+8) = 3x+10

From I: (x-2)/(x+4) = 8/11

=>x = 18

Total number of balls in the bag = 3*18+10 = 64

I is alone sufficient to get the answer of the question.

From II: 3x+10 = 4(x-2)

=> x = 18

Total number of balls in the bag = 3*18+10 = 64

II is alone sufficient to get the answer of the question.

Either I or II alone sufficient to get the answer of the question. - There are three pipes A,B and C. Two of them are inlet pipes and one is outlet pipe. Which pipe is outlet pipe?

Statement I: A and B can fill the tank in 20 minutes while B and C can fill the tank in 30 minutes.

Statement II: A and C together can fill the tank in (20/3) minutes.Both I and II.Neither I nor II.Either I or II.II is alone sufficient not I.I is alone sufficient not II.Option A

From I: Total work LCM(20 and 30) = 60 units

Number of units of water filled by A and B together in one minute = 60/20 = 3 units

Number of units of water filled by C and B together in one minute = 60/30 = 2 units

I alone is not sufficient to get the answer of the question.

From II: II alone is not sufficient to get the answer of the question.

Combining I and II, we get Total work LCM(20 and 30) = 60 units

Number of units of water filled by A and B together in one minute = 60/20 = 3 units

Number of units of water filled by C and B together in one minute = 60/30 = 2 units

Number of units of water filled by C and A together in one minute = 60/(20/3) = 9 units

Number of units of water filled by (A+2B+C) in one minute = 3+2 = 5 units

Now, A+2B+C = 5 =>9+2B = 5

=>B = -2

B is outlet pipe. - What is the time taker by train to travel form Delhi to Chandigarh. The distance between Delhi and Chandigarh is 270 km.

Statement I: Time taken by train to cross a platform of length 350 m is 40 sec.

Statement II: Time taken by train to cross a man standing on platform is (50/3) sec.Neither I nor II.I is alone sufficient not II.Both I and II.Either I or II.II is alone sufficient not I.Option C

Let length and speed of the train be “l” m and “s” m/s resp.

From I: (I+350)/s = 40

I alone is not sufficient to get the answer of the question.

From II: I/s = 50/3

II alone is not sufficient to get the answer of the question.

Combining I and II , we get

(50s/3)+350 = 40s

=> s = 15 m/s = 54 km/hr.

Required time = 270/54 =5 hours

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