Reasoning: Direction Sense Questions Set 8 (IBPS PO 2017 Mains Based)

 
Coded Directions Sense Questions, type of which were asked in IBPS PO Mains 2017 Exam

Directions (1-5): Read the following information carefully to answer the questions that follow. The questions are based on following coding formats:
# – North
@ – South
% – East
$ – West
! – Either 4 or 6 m
& – Either 3 or 10 m
Examples: P@Q means P is South of Q, P#$Q means P is North-West of Q, P$!Q means P is West of Q at a distance of either 4 or 6 m.
Conditions given are as:
I. A#&B
II. A#$C
III. C%B
IV. C$!D
V. E@&D
VI. F$!E
VII. G#!F
VIII. G@$C

  1. Given H$G, HG= 3 m, B#H. Find distance between B and C.
    4 m
    5 m
    6 m
    8 m
    Cannot be determined
    Option B
    Explanation:
    To make G south-west of C, length of CD should be smaller than FE, which is possible when CD = 4 m, and FE = 6 m. Also FG should be smaller than DE, which is possible with FG = 4 or 6 and DE = 10 m

    Assume point P – north of G and west of C. So PC = 2 m (FE-CD). Since B is north of H, so BP = HG = 3 m
    So BC = BP+PC = 3+2 = 5 m
  2. If B#G, then which of the following is true regarding points B and G?
    G#&B
    B#&G
    B@!G
    G@!B
    None of these
    Option D
    Explanation:

    FG = 4 or 6 m,
    DE = 10 m as explained in Q1.
    B is west of D. So FB should be 10 m
    Hence, if FG = 4, then GB = 6, and if FG = 6, then GB = 4, G!B
  3. A man starts walking from point A, walks for 5 m in ‘%’ direction, reaches point J, turns ‘@’ direction, and now walks 7 m to reach point G. Given J#G. What is the distance between points C and A. [Also take data from Question No. 1]
    √38 m
    4√5 m
    √34 m
    4√6 m
    √42 m
    Option C
    Explanation:
    J#G – J is north of G. and JG = 7 m, which is only possible when AB = 3 m
    from Q1, BC = 5m
    So AC = √(32 + 52) = √34 m
  4. If distance between points G and E is 6√2 m, the
    2√5 m
    3√5 m
    5√6 m
    4√6 m
    5√2 m
    Option A
    Explanation:

    GE= 6√2 m
    So FG = √(GE2 – FE2) = √(6√2)2 – 62) = √36 = 6 m
    Assume point S – east of G and south of C
    So GC = √(GS2 + CS2)
    GS = FE – CD = 2 m, CS = DE – FG = 10-6 = 4m, now find GC = 2√5 m
  5. If K@!D and G$K, what is the maximum area of the quadrilateral formed by joining points K, G, F and E?
    24 m2
    30 m2
    18 m2
    36 m2
    None of these
    Option D
    Explanation:
    K@!D – K is south of D and at a distance of 4 or 6 m.
    G is west of K. So figure formed by joining given points is a rectangle.
    So if DK = 4, KE = FG = 6, and if DK – 6, then KE = FG = 4. Area will be maximum in 1st case. So Ar of rectangle KEFG = FE*De = 6*6 = 36 m2

Directions (6-10): Read the following information carefully to answer the questions that follow. The questions are based on following coding formats:
$ – North
@ – South
# – East
% – West
! – Either 3 or 8 m
& – Either 4 or 9 m
© – Either 1 or 6 m
Examples: P@Q means P is South of Q, P$%Q means P is North-West of Q, P#!Q means P is East of Q at a distance of either 3 or 8 m.
Conditions given are as:
I. A%!B
II. A$!C
III. C%&D
IV. E@&B
V. D$©F
VI. E#F

  1. If distance between points P and D is 8 m, P$D, P%B, find the distance between points P and B.
    4 m
    5 m
    3 m
    8 m
    None of these
    Option A
    Explanation:
    Since E is east of F, so AB should be greater than CD, which is possible with CD = 4, AB = 8

    Point P is 8 m north of point D, point P is west of point B
    So PB = AB-CD = 8-4 = 4 m
  2. Given that L@!A, and L$C, find the distance between points L and C.
    2 m
    7 m
    8 m
    3 m
    5 m
    Option E
    Explanation:
    For L to be north of C and A to be north of L, length AL should be 3, and AC be 8. so LC = AC-AL = 8-3 = 5 m
  3. If K@C, then which of the following is definitely false?
    F#K
    E$#K
    A$K
    B$%K
    K@%D
    Option D
    Explanation:
    We have to find the one which is definitely false, for 1st and 2nd options, there is a possibility. In D, B is north-west of K, but B will be definitely north-east of K.
  4. If distance between points D and F is greater than distance between points B and E, then which of the given conditions above will contradict given that E#F is definitely true?
    A%!B
    A$!C
    C%&D
    E@&B
    D$©F
    Option B
    Explanation:
    For Q, conditions will be DF = 6, and BE = 4. Now keeping F west of E as same, we get

    So in this, A is south of C.
  5. If distance between points B and E is 4 m, find the distance and direction of point A with respect to point D?
    8 m
    10 m
    11 m
    5 m
    4 m
    Option D
    Explanation:
    If BE = 4, then DF = 1 and AC = 3, so
    AD = √(AC2+CD2) = √(9+16) = 5 m


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11 Thoughts to “Reasoning: Direction Sense Questions Set 8 (IBPS PO 2017 Mains Based)”

  1. DAS

    mam in question 1
    Conditions given are as:
    I. A#&B
    II. A#$C
    III. C%B
    IV. C$!D
    V. E@&D
    VI. A$!E
    VII. G#!F
    VIII. G@$C
    in the above condition vi, in place of A$!E,F$!E should be there. Otherwise how can FE=6m
    please reply mam.
    thank you

  2. DAS

    Since B is north of H, so BP = HG = 3 m
    mam this line i can’t understand
    please reply

    1. Take point H west of G and also H south of B
      So BP will be equal to HG

      1. Ashaa

        Mam in ques 3, ans should be root 58 ( sq of 3 + sq of 7) ??

      2. Ashaa

        How bc = 5? It should be 7..no???? As aj= 5

  3. DAS

    @Shubhra_AspirantsZone:disqus mam ?????

  4. ครђ

    Thanks Mam :))

    Is Q4 incomplete @Shubhra_AspirantsZone:disqus mam?

  5. Rahul Warrier

    pls can we have some sample quest …it will be usefull for Mah cet eam

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