**Coded Directions Sense Questions, type of which were asked in IBPS PO Mains 2017 Exam**

**Directions (1-5): Read the following information carefully to answer the questions that follow. The questions are based on following coding formats:**

# – North

@ – South

% – East

$ – West

! – Either 4 or 6 m

& – Either 3 or 10 m

Examples: P@Q means P is South of Q, P#$Q means P is North-West of Q, P$!Q means P is West of Q at a distance of either 4 or 6 m.

Conditions given are as:

I. A#&B

II. A#$C

III. C%B

IV. C$!D

V. E@&D

VI. F$!E

VII. G#!F

VIII. G@$C

- Given H$G, HG= 3 m, B#H. Find distance between B and C.
4 m5 m6 m8 mCannot be determinedOption B

Explanation:

To make G south-west of C, length of CD should be smaller than FE, which is possible when CD = 4 m, and FE = 6 m. Also FG should be smaller than DE, which is possible with FG = 4 or 6 and DE = 10 m

Assume point P – north of G and west of C. So PC = 2 m (FE-CD). Since B is north of H, so BP = HG = 3 m

So BC = BP+PC = 3+2 = 5 m

- If B#G, then which of the following is true regarding points B and G?
G#&BB#&GB@!GG@!BNone of theseOption D

Explanation:

FG = 4 or 6 m,

DE = 10 m as explained in Q1.

B is west of D. So FB should be 10 m

Hence, if FG = 4, then GB = 6, and if FG = 6, then GB = 4, G!B

- A man starts walking from point A, walks for 5 m in ‘%’ direction, reaches point J, turns ‘@’ direction, and now walks 7 m to reach point G. Given J#G. What is the distance between points C and A. [Also take data from Question No. 1]
√38 m4√5 m√34 m4√6 m√42 mOption C

Explanation:

J#G – J is north of G. and JG = 7 m, which is only possible when AB = 3 m

from Q1, BC = 5m

So AC = √(3^{2}+ 5^{2}) = √34 m - If distance between points G and E is 6√2 m, the
2√5 m3√5 m5√6 m4√6 m5√2 mOption A

Explanation:

GE= 6√2 m

So FG = √(GE^{2}– FE^{2}) = √(6√2)^{2}– 6^{2}) = √36 = 6 m

Assume point S – east of G and south of C

So GC = √(GS^{2}+ CS^{2})

GS = FE – CD = 2 m, CS = DE – FG = 10-6 = 4m, now find GC = 2√5 m - If K@!D and G$K, what is the maximum area of the quadrilateral formed by joining points K, G, F and E?
24 m
^{2}30 m^{2}18 m^{2}36 m^{2}None of theseOption D

Explanation:

K@!D – K is south of D and at a distance of 4 or 6 m.

G is west of K. So figure formed by joining given points is a rectangle.

So if DK = 4, KE = FG = 6, and if DK – 6, then KE = FG = 4. Area will be maximum in 1st case. So Ar of rectangle KEFG = FE*De = 6*6 = 36 m^{2}

**Directions (6-10): Read the following information carefully to answer the questions that follow. The questions are based on following coding formats:**

$ – North

@ – South

# – East

% – West

! – Either 3 or 8 m

& – Either 4 or 9 m

© – Either 1 or 6 m

Examples: P@Q means P is South of Q, P$%Q means P is North-West of Q, P#!Q means P is East of Q at a distance of either 3 or 8 m.

Conditions given are as:

I. A%!B

II. A$!C

III. C%&D

IV. E@&B

V. D$©F

VI. E#F

- If distance between points P and D is 8 m, P$D, P%B, find the distance between points P and B.
4 m5 m3 m8 mNone of theseOption A

Explanation:

Since E is east of F, so AB should be greater than CD, which is possible with CD = 4, AB = 8

Point P is 8 m north of point D, point P is west of point B

So PB = AB-CD = 8-4 = 4 m - Given that L@!A, and L$C, find the distance between points L and C.
2 m7 m8 m3 m5 mOption E

Explanation:

For L to be north of C and A to be north of L, length AL should be 3, and AC be 8. so LC = AC-AL = 8-3 = 5 m - If K@C, then which of the following is definitely false?
F#KE$#KA$KB$%KK@%DOption D

Explanation:

We have to find the one which is definitely false, for 1st and 2nd options, there is a possibility. In D, B is north-west of K, but B will be definitely north-east of K. - If distance between points D and F is greater than distance between points B and E, then which of the given conditions above will contradict given that E#F is definitely true?
A%!BA$!CC%&DE@&BD$©FOption B

Explanation:

For Q, conditions will be DF = 6, and BE = 4. Now keeping F west of E as same, we get

So in this, A is south of C. - If distance between points B and E is 4 m, find the distance and direction of point A with respect to point D?
8 m10 m11 m5 m4 mOption D

Explanation:

If BE = 4, then DF = 1 and AC = 3, so

AD = √(AC^{2}+CD^{2}) = √(9+16) = 5 m

mam in question 1

Conditions given are as:

I. A#&B

II. A#$C

III. C%B

IV. C$!D

V. E@&D

VI. A$!E

VII. G#!F

VIII. G@$C

in the above condition vi, in place of A$!E,F$!E should be there. Otherwise how can FE=6m

please reply mam.

thank you

Yes it is F only

Thanku az

Since B is north of H, so BP = HG = 3 m

mam this line i can’t understand

please reply

Take point H west of G and also H south of B

So BP will be equal to HG

THANK YOU MAM

Mam in ques 3, ans should be root 58 ( sq of 3 + sq of 7) ??

How bc = 5? It should be 7..no???? As aj= 5

@Shubhra_AspirantsZone:disqus mam ?????

Thanks Mam :))

Is Q4 incomplete @Shubhra_AspirantsZone:disqus mam?

pls can we have some sample quest …it will be usefull for Mah cet eam