- The parameter of a square is equal to the perimeter of a rectangle of length 14 cm and breadth 20 cm. Find the circumference of a semicircle (approx.) whose diameter is equal to the side of the square.
A) 32 cm
B) 22 cm
C) 30 cm
D) 27 cm
E) 19 cm
- There are two circles of different radius such that radius of the smaller circle is three – sevens that of the larger circle. A square whose area equals 3969 sq cm has its side as thrice the radius of the larger circle. What is the circumference of the smaller circle?
A) 59 cm
B) 56.5 cm
C) 49.5 cm
D) 65.5 cm
E) 62 cm
- A Birthday cap is in the form of a right circular cone which has base of radius as 9 cm and height equal to 12 cm. Find the approximate area of the sheet required to make 8 such caps.
A) 3225 cm2
B) 3278 cm2
C) 3132 cm2
D) 3392 cm2
E) 3045 cm2
- The barrel of a fountain pen is cylindrical in shape which radius of base as 0.7 cm and is 5 cm long. One such barrel in the pen can be used to write 300 words. A barrel full of ink which has a capacity of 14 cu cm can be used to write how many words approximately?
A) 598
B) 656
C) 508
D) 545
E) 687
- A vessel is in the form of a hemi-spherical bowl on which is mounted a hollow cylinder. The diameter of the sphere is 14 cm and the total height of vessel is 15 cm, find the capacity of the vessel.
A) 1977.23 cm3
B) 1999.45 cm3
C) 1840.67 cm3
D) 1950.67 cm3
E) 1833.27 cm3
- A car has wheels of diameter 70 m. How many revolutions can the wheel complete in 20 minutes if the car is travelling at a speed of 110 m/s?
A) 550
B) 580
C) 630
D) 640
E) 600
- A clock has its minute hand of length 7 cm. What area will it swept in covering 10 minutes?
A) 32.17 cm2
B) 35.67 cm2
C) 45.45 cm2
D) 41.23 cm2
E) None of these
- Find the area of shaded region (approximately) in the given figure if AB = 12 cm and BC = 9 cm with O being the centre of circle.
A) 40 cm cm2
B) 27 cm cm2
C) 23 cm2
D) 39 cm2
E) 34 cm2
- The diameters of the internal and external surfaces of a hollow spherical shell are 10cm and 6 cm respectively. If it is melted and recasted into a solid cylinder of length 8/3 cm, find the diameter of the cylinder.
A) 28√2 cm
B) 14√2 cm
C) 26√2 cm
D) 18√2 cm
E) 22√2 cm
- The radii of two cylinders are in the ratio 4 : 5 and their curved surface areas are in the ratio 3 : 5. What is the ratio of their volumes?
A) 11 : 24
B) 13 : 21
C) 7 : 19
D) 11 : 15
E) 12 : 25
Related posts
-
Static GK Quiz for Upcoming Exams Set – 664
Static GK Questions for SBI PO/Clerk, IBPS RRB, IBPS... -
Static GK Quiz for Upcoming Exams Set – 663
Static GK Questions for SBI PO/Clerk, IBPS RRB, IBPS... -
The Hindu Editorial Vocabulary – Set 216
The Hindu Editorial Vocabulary Words with Meanings for various...
21 Thoughts to “Quantitative Aptitude: Mensuration Set 2”
Comments are closed.
Q4. One such barrel in the pen can be used to write 1200 words.
But u used:
A barrel which has capacity 7.7 cm2 can write 300 words
Check this questions please. either should be 1200 words than options doesnt match or vv.
Yes yes 300
muje dissussion me join hona hai kaise join hote hai pls help mam
visit here : http://aspirantszone.com/discussion-zone-20-march-2017/
r = 9, h = 12
So slant height, l = √(92+122) = 15 cm
So curved surface area of a cap = πrl = 22/7 * 9 * 15 = 396 sq. cm
So curved surface area of 8 such cap = 396*8 = 3168 sq. cm which is also equal to area of sheet required to make 8 such caps
22/7 * 9 * 15 = 424.28 sq. cm so curved surface area of 8 such caps = 424.28 * 8 =3394.28 sq. cm
plz do correction mam/sir
Yes yes
ok mam
Height of the cylinder formed = 8/3 cm
Let the radius of the cylinder be ‘r’ cm
Volume of the cylinder = πr2h
= 22/7 * r2 * 8/3
= 22/7 * r3 * 8/3 = 9856 / 3
r3 = 392
r = 14√2 cm
So Diameter of the cylinder = 2 x 14√2 =28√2 cm
r cube or r square correct plz
Square
thanku mam 🙂
thanks
Thank you, I have recently been looking for information approximately
this topic for a while and yours is the greatest I’ve found out so far.
However, what concerning the bottom line? Are you certain concerning the
source?
I’ve been surfing on-line greater than 3 hours these days, but I never discovered any attention-grabbing article
like yours. It’s pretty worth enough for me.
In my opinion, if all website owners and bloggers made good content as you probably did, the web
shall be much more useful than ever before.
There’s certainly a great deal to find out about this subject.
I like all the points you’ve made.
This blog was… how do you say it? Relevant!! Finally I’ve found something which helped me.
Appreciate it!
Hi, I do think this is a great blog. I stumbledupon it 😉 I’m going to
return yet again since i have book marked it. Money and
freedom is the best way to change, may you be rich and
continue to guide other people.
890995 553192Hi. Cool article. There is actually a problem with the web website in firefox, and you might want to test this The browser will be the marketplace leader and a huge portion of folks will miss your superb writing due to this problem. 944489
Article writing is also a fun, if you know then you can write
otherwise it is difficult to write.
Simply wish to say your article is as surprising.
The clearness to your publish is simply spectacular and i can think you’re an expert in this subject.
Fine with your permission let me to snatch your RSS feed to keep up to date with
approaching post. Thanks 1,000,000 and please carry on the
gratifying work.
I will immediately seize your rss feed as I can’t find your e-mail subscription hyperlink or e-newsletter service.
Do you’ve any? Please let me recognise in order that I may subscribe.
Thanks.
Nice post. I learn something new and challenging on blogs I stumbleupon every day.
It’s always exciting to read content from other authors and use something from their web sites.