- Find the average increase rate, if increase in the population in the first year is 40% and that in the second year is 20%.
38362934NoneOption D

Solution:

Let the population be 100.

Then 100 * 140/100 * 120/100 = 168.

Increment is 68%

Average increment is 68/2 = 34.

- A trader mixes three types of tea in the ratio 4 : 3 : 5 costing 15 rupees per kg., 20 rupees per kg. and 30 rupees per kg. respectively. He sells the mixture at 25 rupees per kg. Find his profit percentage
11 1/9%12%10 2/3%14%NoneOption A

Solution:

Let the quantity of three types of tea were 4x, 3x and 5x.

Total SP=12x*25=300x

Total CP =4x*15 + 3x*20 + 5x+30=270x.

Profit %ge = (300x-270x) / 270x *100

=(30x/270x )* 100

=100/9=11 1/9%.

- In a town, the population was 4000. In one year, male population increased by 10% and female population increased by 5% but the total population increased by 7.5%. Initially the number of males in the town was
1800200021002150NoneOption B

Solution:

Let the no of male population be x

Then female population=(4000-x)

x*110/100 + (4000-x)*105/100=4000*107.5/100

5x/100+ 4200=4300

x=2000.

- 15 years ago the ratio of the age of A and B is 5:4. 12 years hence the ratio of ages of A and B will be 14 : 13. Find the ratio of their present ages:
9:1011:910:99:11NoneOption C

Solution:

Let 15 years ago the ages of A and B be 5x and 4x.

(5x+15+12)/(4x+15+12) = 14/13

(5x+27)/(4x+27)=14/13

65x+(27*13) = 56x +(27*14)

9x=27

x=3.

Present ages of A and B be 30:27=10:9.

- Sajiya, Sharifa and Yashmitha invested Rs. 10000, Rs. 12000 and Rs. 8000 respectively in a business. Sajiya left after six months. If after ten months, there was a gain of Rs. 1820, then what will be the share of Yashmitha?
Rs530Rs650Rs480Rs560NoneOption D

Solution:

Sajiya : Sharifa : Yashmitha

10*6 : 12*10 : 8*10=3:6:4

13(6+4+3)…….. 1820

4 …………….. ?==>Rs 560.

- One fill pipe A is 4 times efficient than second fill pipe B and takes 33 minutes less than the fill pipe B. When will the cistern be full if both pipes are opened together?
9min8.8min9.4min8.5minNoneOption B

Solution:

Pipe A:B=4:1

Difference (4-1) 3 ……… 33

………. 4 …….. ?==>44min

…………… 1 ………….. ?==>11min

1min work of A and B is

1/11+1/44=5/44

Then time=44/5=8.8min.

- The difference between the length and breadth of a rectangle is 20m. If its perimeter is 100 m, then its area is:
525m
^{2}495m^{2}510m^{2}444m^{2}NoneOption A

Solution:

l-b=20

Perimeter 2(l+b)=100

Then l+b=50

Solving both equation l=35m and b=15m.

Area=35*15=525m^{2}.

- A man buys a chair and table for Rs. 6000. He sells the chair at a loss of 10% and the table at gain of 10%. He still gains Rs. 100 on the whole. Cost price of chair is
Rs1800Rs2500Rs2200Rs2400NoneOption B

Solution:

If the CP of the chair be Rs. x then,

Total SP = (x*90)/100+((6000-x)*110/100);

9x+66000-11x = 61000;

2x = 66000-61000 = 5000;

x = Rs. 2500.

- Two cards are drawn together from a pack of 52 cards. The probability that one is a heart and one is a Spade, is:
199/1214169/1326146/1251128/1435NoneOption B

Solution:

(13C1*13C1)/52C2

=(13*13)/(26*51)

=169/1326.

- A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is:
Rs587Rs546Rs624Rs698NoneOption D

Solution:

S.I. for 1 year = Rs. (854 – 815) = Rs. 39.

S.I. for 3 years = Rs.(39 * 3) = Rs. 117.

Therefore Principal = Rs. (815 – 117) = Rs. 698.

THANK U MAM