# Mixed Quantitative Aptitude Questions For Clerk Mains Set 65

1. A milkman sells the milk at cost price but mixes water in the milk. In this way he earns 60/4% profit. In what ratio does he mix milk and water?
14:3
12:1
20:3
15:2
None
Option C
Solution:
Let CP of 1 litre pure milk=Rs1
CP of mixture=100/(100+60/4)=Rs20/23
Milk…………..Water
1……………….0
……….20/23
20/23…………… 3/23
==>20:3.
2. The number of students in the three sections of a class are in the ratio 1:2:3. The average marks scored in each of these sections is in the ratio 4:3:1. By what percent is the average mark of the second section more than the class average?
24.6%
29.8%
33.5%
38.4%
None
Option D
Solution:
Let the number of students be x, 2x, 3x.
Let the average marks be 4y,3y,y.
Average mark of class = ( 4xy+6xy+3xy)/( x+2x+3x)
=13xy/6x
=13y/6
Percentage difference = ( 3y – 13y/6)/13y/6 *100=38.4%.
3. A and B started a business in partnership by investing Rs 8000 and Rs 3000 respectively. Condition of partnership is that B got Rs 100 per month for management of the business. Remaining profit has to be distributed in the ratio of their investments. Find the share of their profit, if the annual profit is Rs 4500.
Rs1800, Rs2000
Rs2200, Rs2300
Rs1500, Rs1800
Rs2000, Rs2200
None
Option B
Solution:
Ratio of investment A: B 8000:4000=2:1
Profit of A=2x
Profit of B=x+12*100
=x+1200
Then 2x+x+1200=4500
x=1100.
A’s profit=Rs2200
B’s profit=Rs2300.
4. If the rate of interest is 20% p.a. and Rs. 8000 lent at the compound interest, half yearly. What is the equivalent simple rate of interest for first year?
18%
21%
14%
12%
None
Option B
Solution:
Amount= P(1+r/100)n
=8000*(1+10/100)2
=Rs9680.
CI=9680-8000
=1680.
r=(1680*100) / 8000
r=21%.
5. An alloy contains Copper, sulphur and lead in the ratio 2:3:1 and another contains sulphur, lead and tin in the ratio 5:4:3. If equal weights of both alloys are melted together to form a third alloy, then the weight of tin per kg in new alloy will be
1/8kg
2/5kg
1/6kg
3/8kg
None
Option A
Solution:
Ratio of Copper, sulphur and lead is given as,
2 : 3 : 1.
Now, let the first alloy be 12 kg (taken as 4 kg Copper, 6 kg sulphur and 2 Kg Lead).
Weight of second alloy = 12 kg as, C : T : L = 5 : 4 : 3. (taken as 5 kg sulphur, 4 kg lead and 3 Kg tin.)
Alloys are mixed together to form third alloy. Then the ratio of content in it,
4 : (6+5) : (2+4) : 3
Weight of third alloy = 12+12 = 24 Kg.
So, weight of the tin = 3/24 = 1/8 kg.
6. The present ages of A,B and C are in proportions 4:7:9. Eight years ago, the sum of their ages was 56. What are their present ages (in years)?
16, 28, 36
12, 21, 27
20, 35, 45
8, 14, 18
None
Option A
Solution:
Let present age of A,B and C be 4x, 7x and 9x respectively.
(4x-8) + (7x-8) +(9x-8) = 56
x=4.
Present age of A, B and C are 16, 28, 36.
7. In a garden, the ratio of the number of banana tree to that of apple trees is 7:9 respectively. If the total number of trees is 288, then how many apple trees are there in the garden?
170
156
145
162
None
Option D
Solution:
Total trees=288.
Ratio 7:9
16. == 288
9 …… ?==>162.
8. In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 2 : 4 : 5. If there is Rs. 46 in all, how many 5 p coins are there?
40
35
45
30
None
Option A
Solution:
Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively.
Then, sum of their values
=25*2x/100 + 10*4x/100 + 5*5x/100
=115x/100 =23x/20
23x/20=46
x=(46*20)/23
=40.
9. A dam’s height increases annually by 1/8th of its height. By how much will it’s height increase after 2.5 years if it stands today at 10 m height?
3.44m
4.65m
2.50m
3.75m
None
Option A
Solution:
Its height after 2.5years will be = 10 {(1+1/8)2 * (1+1/16)}
=10(81/64*17/16)=13.44
Increase in height=13.44-10=3.44m.
10. Two boats A and B start towards each other from two places, 150 km apart. Speed of the boats A and B in still water are 12 km/h and 18 km/h respectively. If A proceeds down and B up the stream, they will meet after
8hrs
3hrs
5hrs
4hrs
None
Option C
Solution:
Let the speed of the stream be x kmph and both the boats meet after t hour.
(12+x)*t+(18-x)*t = 150
12t+18t = 150
30t = 150
t=5hrs.

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