Directions(1-5): What will come in place of question mark ‘?’ in the following questions.
- ? = (7.12^1.98 + 23.88^2.01)/(3.05^1.96 + 3.86^2.11)
1520182512Option D
? = (7.12^1.98 + 23.88^2.01)/(3.05^1.96 + 3.86^2.11)
=> ? = (7^2 + 24^2)/(3^2+4^2) => ? = (49+576)/(9+16) => ? = 25 - ? = (1224.5)^1/2*12.02^2 + 34.11*21.97
57885665521055165700Option A
? = (1224.5)^1/2*12.02^2 + 34.11*21.97
=> ? = 35*12^2 + 34*22
=>? = 5040 + 748
=> ? = 5788 - ? = 17.18 * 30.02+ 39.8% of (19.95*18.12)
641633654600620Option C
? = 17.18 * 30.02+ 39.8% of (19.95*18.12)
=> ? = 17*30+40% of (20*18)
=> ? = 510 + 0.4*360
=> ? = 654 - ? = 21^2 + (507*273)/39^2
542550511523532Option E
? = 21^2 + (507*273)/39^2
=> ? = 441 + (39*13*39*7)/39^2
=> ? = 441+91
=> ? = 532 - ? = 15% of (15*5*2) + 37.5% of (25*5*4)
225215200210232Option D
? = 15% of (15*5*2) + 37.5% of (25*5*4)
=> ? = 15% of 150 + 37.5% of 500
=> ? = 22.5+187.5
=> ? = 210 - The HCF and the LCM of two numbers ‘a’ and ‘b’ is 7 and 1001 resp. If the value of ‘a’ is 77. Find the value of b.
7780918875Option C
Product of two numbers = LCM*HCF 77*b = 7*1001
=> b = 91 - A shopkeeper sells 3 pens at the cost price of 4 pens. If the cost price of each pen is Rs.6. Find the profit% gained by the shopkeeper on each pen.
25.08%22.22%20.35%33.33%30.15%Option D
CP of 4 pens = 6*4 = Rs.24
SP of 1 pen = 24/3 = Rs.8
Profit% = [8-6]/6*100 = 33.33% - Three types of rice of rate Rs.45/kg, Rs.35/kg and Rs.40/kg are blended to form a mixture of 30 kg and the ratio of their quantity in which they mixed is 6:5:4 resp. If a person wishes to buy 1 kg of the mixture then how much should he have to pay?
Rs.39.19Rs.32.28Rs.35.53Rs.40.33Rs.44.11Option D
Total cost of the mixture = 45*6/15+35*5/15+40*4/15
= Rs.1210
Required per kg price of the mixture = 1210/30 = Rs.40.33 - Train A which is 270 m long crosses a pole in 18 seconds. Length of train B is 50% more than the length of train A and it can cross a platform of 45 m completely, in t seconds. Find the value of t if speed of train B is double that of train A?
18 seconds12 seconds15 seconds17 seconds10 secondsOption C
Speed of train A = 270/18 = 15 m/s
Speed of train B = 15*2 = 30 m/s
Length of train B = 1.5*270 = 405 m
t = (405+45)/30 = 15 seconds - Five years ago, the average age of Raj, Simran and Baban was 31 years. At present, the average age of the family is reduced by 3 years and it was due to the birth of Raj, and Simran’s son Shahrukh during the 5 year period. Find the present age of Shahrukh.
6 years4 years3 years8 years5 yearsOption B
Raj+Simran+Baban = 31*3 = 93
New Average = 31-3 = 28
After 5 years ,
Shahrukh’s age = 112 – 15 – 93
= 4 years
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