Mixed Quantitative Aptitude Questions Set 115

  1. Rahul is 8 years older than Manish while Manish is 6 years older than Sonu. If ratio of age of Sonu to age of Rahul is 5 : 12 resp. What will be the age of Manish after 12 years?
    18 years
    12 years
    20 years
    15 years
    28 years
    Option E
    Let the age of Sonu be x years.
    Age of Manish = (x+6) years
    Age of Rahul = (x+14) years
    Now, x/(x+14) = 5/12
    => x = 10
    Age of Manish after 12 years = x + 6 + 12 = 28 years

     

  2. Mona spends (x+5)% and (x+10)% of his monthly income on rent and transport resp. After this he saves Rs.17820 out of his income of Rs.32400. Find his monthly expenditure on transport.
    Rs.2590
    Rs.3550
    Rs.4860
    Rs.4400
    Rs.4000
    Option C
    32400* [(x*5) + (x-10)]% = 32400 – 17820
    => x = 25
    Monthly expenditure on transport = 32400*(25 – 10)% = Rs.4860

     

  3. The downstream speed of a boat is 8 km/hr. more than the upstream speed. Time taken by the boat to travel 360 km downstream is 15 hours. Find the time taken by boat to travel 360 km upstream.
    23.5 hours
    15.6 hours
    12.3 hours
    22.5 hours
    20.6 hours
    Option D
    Let speed of boat and stream speed be x km/hr. and y km/hr. resp.
    (x + y) = (x – y) + 8
    => y = 4 km/hr.
    Also, 360 = 15(x + y)
    => x + y = 24
    So, x = 24 – 4 = 20 km/hr.
    Required time = 360/(20 – 4) = 22.5 hours

     

  4. In a match, 5 batsman contributed for scoring runs. The ratio of run scored by Virat and Rohit is 8:7 and total run scored by all the five batsman is 360. Find the ratio of run scored by Virat to total run scored by all the 5 batsman, if 5/12th of the total run scored by Virat and Rohit together.
    1 : 3
    2 : 9
    8 : 9
    6 : 7
    2 : 3
    Option B
    Let the runs scored by Virat and Rohit be 8x and 7x resp. 8x+7x = 5/12*360
    => x = 10 Runs scored by Virat = 8x = 80 Required ratio = 80 : 360 = 2 : 9

     

  5. A man distributes Rs.9600 among his three sons A,B and C in the ratio of 4:3:5 resp. but mistakenly he distributed in the ratio of 5:3:2 resp. Find the difference between the amount received by A and the amount he was supposed to receive.
    Rs.1600
    Rs.1700
    Rs.1300
    Rs.1500
    Rs.1000
    Option A
    Amount received by A initially = [4/(4+3+5)]*9600
    = Rs.3200
    Amount received by A mistakenly = [5/(4+3+5)]*9600 = Rs.4800
    Required Difference = 4800 – 3200 = Rs.1600

     

  6. A vessel contains mixture of milk and water mixed in the ratio of 21:10 resp. 124 litres of mixture is taken out of the vessel and replaced with 46 litres of water so that the ratio of the milk and water in the vessel becomes 4:3 resp. Find the difference between the initial quantities of milk and water in the vessel.
    111 litres
    115 litres
    122 litres
    132 litres
    120 litres
    Option D
    (21x – 84)/(10x – 40 + 46) = 4/3
    => x = 12
    Difference beyween the initial quantities of milk and water = 11*12 = 132 litres

     

  7. C and D decided to start a business with an investment of Rs.75000 and Rs.60000 resp. A and B joined the business with an investment of Rs.40000 and Rs.25000 after 3 months and 4 months fro m the start of business resp. If D investment Rs.15000 more at the beginning of the 11tg month, find his profit of share if they received a total profit of Rs.44200.
    Rs.10000
    Rs.15000
    Rs.13000
    Rs.14000
    Rs.16000
    Option B
    Ratio of profit share = A:B:C:D
    = (40000*9) : (25000*8) : (75000*12) : (60000*10 + 75000*2)
    = 36 : 20 : 90 : 75
    Profit share of D = [75/(36+20+90+75)]*44200 = Rs.15000

     

  8. The profit percentage earned on selling an article for Rs.2400 is twice the profit percentage earned selling an article for Rs.1800. Find the profit percentage on selling article for Rs.1600.
    24.14%
    17.17%
    33.33%
    30.12%
    25.25%
    Option C
    Let the CP be x.
    2400 – x = 2(1800 – x)
    => x = 1200
    Required Profit% = (1600 – 1200)/1200*100 = 33.33%

     

  9. The average weight of five friends P,Q,R,S and T is (x+6) years while the average weight of R and T is (x – 6) kg. If the weight of another person U is also added. The average weight of all of them is reduced by 5 kg. Find the value of ‘x’ if average weight of P,Q,S and U is 94.5.
    75
    88
    63
    90
    60
    Option D
    Total weight of friends P,Q,R,S and T
    = (x+6)*5 = 5(x+6) kg
    Total weight of P,Q and S = 5(x+6) – 2(x+6) = 3(x+14) kg
    Weight of U = (x+6-5)*6 – 5(x+6) = (x – 24) kg
    Now, [3(x+14) + (x- 24)] = 94.5*4
    => x = 90

     

  10. A bag contains 32 marbles of three different colors like Black, Violet and Red. The ratio of black marbles to violet marbles is 3:2, resp. and probability of choosing a red marble is 3/8. If two marbles are picked from the bag, what is the probability that one marble is violet and one marble is red.
    2/31
    6/35
    4/33
    6/31
    4/21
    Option D
    Let the number of marble be x.
    Probability of choosing a red marble = x/32 (x/32) = 3/8
    => x = 12
    Remaining balls = 32 – 12 = 20
    Number of violet marble = 2/5*20 = 8
    Number of black marble = 3/5*20 = 12
    Required Probability = (8C1*12C1)/32C2 = 6/31

     


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