Mixed Quantitative Aptitude Questions Set 124

Directions(1-5): What approximate value will come in place of question mark ‘?’ in the following questions.

1. 25.6% of 250 + √? = 119
   2110
   2255
   3025
   2995
   3030
   Option C
   250 × 25.6 100 + √? = 119
   ⇒ 64 + √? = 119
   ⇒ √? = 119 − 64 = 55
   ⇒ ? = 55 × 55 = 3025

    

2. [30% 𝑜𝑓 {(80% 𝑜𝑓 850) ÷ 34}] = ?
   8
   6
   9
   5
   4
   Option B
   ? = [ 30/100 × {( 80/100 × 850) ÷ 34}]
   = [ 30/100 × {680 ÷ 34}] = [ 30/100 × 20] = 6

    

3. 65% 𝑜𝑓 240+ ?% 𝑜𝑓 150 = 210
   52
   61
   44
   58
   36
   Option E
   65/100 𝑜𝑓 240 + ?/ 100 𝑜𝑓 150 = 210
   ⇒ 156 + 1.5 ×? = 210
   => ? = [210−156]/1.5 = 36

    

4. 1425 + 8560 + 1680 ÷ 200 = ?
   7788
   8595
   9110
   8800
   9993
   Option E
   ? = 1425 + 8560 + 1680 ÷ 200
   = 1425 + 8560 + 1680/200
   = 9985 + 8.4 = 9993.4 == 9993

    

5. ? % of 800 = 293 – 22% of 750
   12
   18
   16
   14
   10
   Option C
   [800 ×?]/ 100 = 293 − 750 × 22/100
   => 8 × ? = 293 − 165 = 128
   => ? = 128/8 = 16

    

6. The retail price of a water geyser is Rs. 1265. If the manufacturer gains 10%, the wholesale dealer gains 15% and the retailer gains 25%, then the cost of the product is:
   Rs. 800
   Rs. 900
   Rs. 600
   Rs. 400
   Rs. 500
   Option A
   Cost price = 100/110 × 100/115 × 100/125 × 1265
   = Rs. 800

    

7. A pipe can fill a cistern in 6 hrs. Due to a leak in its bottom, it is filled in 7 hrs. When the cistern is full, in how much time will it be emptied by the leak?
   47 hrs.
   40 hrs.
   50 hrs.
   42 hrs.
   38 hrs.
   Option D
   In one hour 1/ 6 – 1/ 7
   = 1/ 42 of the cistern is empty.
   The whole cistern will be emptied in 42 hrs.

    

8. Ram travels a certain distance at 3 km/h and reaches 15 minutes late. If he travels at 4 km/h, he reaches 15 minutes earlier. The distance he has to travel is:
   6 km
   7 km
   8 km
   9 km
   4 km
   Option A
   Let D be the required distance
   So, D/3 − D/4 = 15+15/60
   D = 6 km

    

9. A sum is invested for 3 years at compound interest at 5%, 10% and 20% respectively. In three years, if the sum amounts to Rs. 16,632, then find the sum.
   Rs.14,000
   Rs.16,000
   Rs.10,000
   Rs.12,000
   Rs.18,000
   Option D
   Let, P be the sum.
   16632 = P (1 + 5/ 100) (1 + 10 /100) (1 + 20/ 100) 16632
   16632 = P × 21/20 × 11/10 × 6/5
   P = Rs.12,000

    

10. A father’s age is three times the sum of the ages of his two children, but 20 years hence his age will be equal to the sum of their ages. Then, the father’s age is:
    10 years
    30 years
    50 years
    40 years
    20 years
    Option B
    Let the father’s age be x years and age of his children be a and b years (𝑎 + 𝑏) = 𝑥/3
    And (𝑎 + 𝑏) + 20 + 20 = 𝑥 + 20
    => 𝑥/3 + 20 = 𝑥
    => 𝑥 = 30 years