# Mixed Quantitative Aptitude Questions Set 137

Directions(1-5): Find the missing term ‘?’ of the following series.

1. 17,18,35,?,88,141
70
78
81
88
92
Option D
17+18
18+35
53+35
88+53
? = 88

2. 300,280,252,216,172,?
110
130
140
120
150
Option D
-4*5
-4*7
-4*9
-4*11
-4*13
? = 120

3. 19,20,42,129,?,2605
500
450
447
520
546
Option D
*1+1
*2+2
*3+3
*4+4
*5+5
? = 520

4. 17,38,80,143,227,?
345
300
332
318
325
Option C
+21*1
+21*2
+21*3
+21*4
+21*5
? = 332

5. 363,353,333,303,?,213
263
225
250
263
245
Option A
-10,-20,-30,-40,-50
? = 263

6. When 50% of first number is added to the second number then second number increases by 25% . Find the ratio of first number to the second number.
3:5
5:7
1:2
2:5
1:4
Option C
Let the first number be x and second number be y resp.
50% of x + y = 1.25y
=>x : y = 1:2

7. A mixture of contains 360 litres of milk and water in the ratio of 5:4 resp. x litres of mixture is taken out and replaced with same quality of water such that of milk and water becomes 1:1 resp.Find the value of x.
30
44
36
28
39
Option C
Quantity of milk = 5/9*360 = 200 L
Quantity of water = 4/9*360 = 160 L
200 – (5x/9) = 160 – (4x/9)+ x
=> x = 36 L

8. A,B and C started a business together with a total investment of Rs.3600. After a year , A and B received a profit of Rs.1500 and Rs.2000 out of the total profit of Rs.6000. Find the inital investment of C (in Rs.)
1000
1500
1400
1300
1200
Option B
Ratio of investment of A:B:C = 1500:2000:(6000-1500-2000)
= 3:4:5
Initial investment of C = 5/(3+4+5)*3600 = Rs.1500

9. The ratio of the units digit to the tens digit of two digit number is 4:1 and the sum of digits is 10. Find the product of digits of number.
10
14
16
19
13
Option C
Unit’s digit be 4x and ten’s digit be x resp.
4x+x = 10
x = 2
Required number = 28
Product of digits = 2*8 = 16

10. A bag contains (x+2) red balls, (x+3) green balls and (x+4) yellow balls. If the probability of drawing a red ball from the bag is 3/10. Find the number of green balls in the bag.
13
18
10
12
14
Option C
Total number of balls in the bag = 3x+9
Probability of drawing a re ball = 3/10
(x+2)/(3x+9) = 3/10
=>x = 7
Total number of green balls = 7+3 = 10

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