Mixed Quantitative Aptitude Questions Set 139

July 5, 2019 Banya

1. Rs. 1800 is given at 20% per annum SI while Rs (1800 – P) is given at 30% per annum CI. If the difference between both interests at the end of two years is Rs 315. Find P.
   200
   400
   300
   100
   500
   Option C
   Total S.I. = 1800×2×20/ 100 = Rs. 720
   Total C.I. = (1800 − 𝑝) [(1 + 30 100 ) 2 − 1] = (1800 − 𝑃) × 69/ 100
   ATQ, (1800 − 𝑃) × 69/ 100 − 720 = 315
   (1800 − 𝑃) = 100/ 69 × 1035
   1800 − 𝑃 = 1500
   ⇒ 𝑃 = 300
   

    

2. Three partners A , B and C invested their amounts in ratio 7:5:3. At the end of six months, A withdraws his amount such that his total investment will be equal to C’s initial investment. If C’ share in annual Profit is Rs. 3600. A’s annual profit will be ?
   5000
   4000
   3000
   6000
   2000
   Option D
   Let their initial investments be 7𝑥, 5𝑥 and 3𝑥 respectively.
   Ratio of their profit = 7𝑥 × 6 + 3𝑥 × 6 ∶ 5𝑥 × 12 ∶ 3𝑥 × 12
   = 60𝑥 ∶ 60𝑥 ∶ 36𝑥 = 15 ∶ 15 ∶ 9
   A’s profit = 3600 × 39/ 9 × 15/ 39
   = Rs. 6000
   

    

3. B’s age is 10 years older than A. If the ratio of B’s age 11 years hence and C’s present age is 3:2. At present C’s age is thrice A’s age. What will be the age of C after 7 years?
   22
   27
   25
   28
   21
   Option C
   Let, age of A be ‘𝑥’ years.
   Then age of B = ‘𝑥 + 10’ years
   And age of C = 3𝑥 years
   ATQ, (𝑥+10+11)/ 3𝑥 = 3/ 2
   (𝑥 + 21)2 = 9𝑥
   7𝑥 = 42
   ⇒ 𝑥 = 6
   Age of C after 7 years = 3𝑥 + 7
   = 18 + 7 = 25 years
   

    

4. If the ratio of curved surface area to the volume of cylinder is 4:7 while the ratio of diameter to the height of cylinder is 14:5. Find the total surface area of cylinder.?
   118
   120
   125
   110
   132
   Option E
   2𝜋𝑟ℎ/ 𝜋𝑟^ 2ℎ = 4/ 7
   2 𝑟 = 4/ 7
   𝑟 = 7/ 2
   2𝑟/ ℎ = 14/ 5
   ⇒ ℎ = 5 /2
   Total surface area = 2 × 22/ 7 × 7 /2 ( 7 /2 + 5/ 2 )
   = 22 × 12 /2 = 132
   

    

5. A and B sold two articles at 25% profit and 40% profit respectively. If total profit is Rs. 178 and the cost price of A is Rs 120 less than B. find the CP of B.
   280
   200
   320
   220
   300
   Option C
   Let, CP of B be 𝑥 + 120
   And that of A be 𝑥
   Then, 25/100 × 𝑥 + 40/100 (𝑥 + 120) = 178
   65𝑥 /100 + 48 = 178
   𝑥 = 200
   C.P. of B = 𝑥 + 120 = Rs. 320
   

    

Directions(6-10): What approximate value will come in place of question mark ‘?’ in the following questions.

6. 24.001 × 14.999 × 9.998 = ?
   3230
   3600
   3125
   3000
   3250
   Option B
   24.001 × 14.999 × 9.998 = ?
   24 × 15 × 10 ≈ 3600
   

    

7. 14.003√?+ 53.0345√? = 67/26.999 × (? )
   729
   772
   670
   789
   770
   Option A
   14.003√?+ 53.0345√? = 67/26.999 × (? )
   14√?+ 53√? = 67/27 ×?
   67√?= 67/ 27 ×?
   √? = 27
   ? = 729
   

    

8. 10.11×36.93+√48.875 × 19.99 = 17.231 × √?
   700
   900
   600
   800
   1000
   Option B
   10.11×36.93+√48.875 × 19.99 = 17.231 × √?
   10 × 37 + 7 × 20 = 17 × √?
   √? = 30
   ? = 900
   

    

9. 1898.88 ÷ 189.921 + 9.99 + (? )^2 = 83.89
   6
   7
   9
   8
   4
   Option D
   1898.88 ÷ 189.921 + 9.99 + (? )^2 = 83.89
   ≈ 1900 ÷ 190 + 10 +?^2 = 84
   ?^ 2 = 84 − 10 − 10
   ? = 8
   

    

10. 39.7% 𝑜𝑓 801 − 250.17 = ? −63% 𝑜𝑓 801
    567
    647
    663
    574
    600
    Option D
    39.7% 𝑜𝑓 801 − 250.17 = ? −63% 𝑜𝑓 801
    ≈ 40 × 8 – 250
    =? −63 × 8
    ?= 574
    

     

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