Mixed Quantitative Aptitude Questions Set 139

  1. Rs. 1800 is given at 20% per annum SI while Rs (1800 – P) is given at 30% per annum CI. If the difference between both interests at the end of two years is Rs 315. Find P.
    200
    400
    300
    100
    500
    Option C
    Total S.I. = 1800×2×20/ 100 = Rs. 720
    Total C.I. = (1800 − 𝑝) [(1 + 30 100 ) 2 − 1] = (1800 − 𝑃) × 69/ 100
    ATQ, (1800 − 𝑃) × 69/ 100 − 720 = 315
    (1800 − 𝑃) = 100/ 69 × 1035
    1800 − 𝑃 = 1500
    ⇒ 𝑃 = 300

     

  2. Three partners A , B and C invested their amounts in ratio 7:5:3. At the end of six months, A withdraws his amount such that his total investment will be equal to C’s initial investment. If C’ share in annual Profit is Rs. 3600. A’s annual profit will be ?
    5000
    4000
    3000
    6000
    2000
    Option D
    Let their initial investments be 7𝑥, 5𝑥 and 3𝑥 respectively.
    Ratio of their profit = 7𝑥 × 6 + 3𝑥 × 6 ∶ 5𝑥 × 12 ∶ 3𝑥 × 12
    = 60𝑥 ∶ 60𝑥 ∶ 36𝑥 = 15 ∶ 15 ∶ 9
    A’s profit = 3600 × 39/ 9 × 15/ 39
    = Rs. 6000

     

  3. B’s age is 10 years older than A. If the ratio of B’s age 11 years hence and C’s present age is 3:2. At present C’s age is thrice A’s age. What will be the age of C after 7 years?
    22
    27
    25
    28
    21
    Option C
    Let, age of A be ‘𝑥’ years.
    Then age of B = ‘𝑥 + 10’ years
    And age of C = 3𝑥 years
    ATQ, (𝑥+10+11)/ 3𝑥 = 3/ 2
    (𝑥 + 21)2 = 9𝑥
    7𝑥 = 42
    ⇒ 𝑥 = 6
    Age of C after 7 years = 3𝑥 + 7
    = 18 + 7 = 25 years

     

  4. If the ratio of curved surface area to the volume of cylinder is 4:7 while the ratio of diameter to the height of cylinder is 14:5. Find the total surface area of cylinder.?
    118
    120
    125
    110
    132
    Option E
    2𝜋𝑟ℎ/ 𝜋𝑟^ 2ℎ = 4/ 7
    2 𝑟 = 4/ 7
    𝑟 = 7/ 2
    2𝑟/ ℎ = 14/ 5
    ⇒ ℎ = 5 /2
    Total surface area = 2 × 22/ 7 × 7 /2 ( 7 /2 + 5/ 2 )
    = 22 × 12 /2 = 132

     

  5. A and B sold two articles at 25% profit and 40% profit respectively. If total profit is Rs. 178 and the cost price of A is Rs 120 less than B. find the CP of B.
    280
    200
    320
    220
    300
    Option C
    Let, CP of B be 𝑥 + 120
    And that of A be 𝑥
    Then, 25/100 × 𝑥 + 40/100 (𝑥 + 120) = 178
    65𝑥 /100 + 48 = 178
    𝑥 = 200
    C.P. of B = 𝑥 + 120 = Rs. 320

     

  6. Directions(6-10): What approximate value will come in place of question mark ‘?’ in the following questions.

  7. 24.001 × 14.999 × 9.998 = ?
    3230
    3600
    3125
    3000
    3250
    Option B
    24.001 × 14.999 × 9.998 = ?
    24 × 15 × 10 ≈ 3600

     

  8. 14.003√?+ 53.0345√? = 67/26.999 × (? )
    729
    772
    670
    789
    770
    Option A
    14.003√?+ 53.0345√? = 67/26.999 × (? )
    14√?+ 53√? = 67/27 ×?
    67√?= 67/ 27 ×?
    √? = 27
    ? = 729

     

  9. 10.11×36.93+√48.875 × 19.99 = 17.231 × √?
    700
    900
    600
    800
    1000
    Option B
    10.11×36.93+√48.875 × 19.99 = 17.231 × √?
    10 × 37 + 7 × 20 = 17 × √?
    √? = 30
    ? = 900

     

  10. 1898.88 ÷ 189.921 + 9.99 + (? )^2 = 83.89
    6
    7
    9
    8
    4
    Option D
    1898.88 ÷ 189.921 + 9.99 + (? )^2 = 83.89
    ≈ 1900 ÷ 190 + 10 +?^2 = 84
    ?^ 2 = 84 − 10 − 10
    ? = 8

     

  11. 39.7% 𝑜𝑓 801 − 250.17 = ? −63% 𝑜𝑓 801
    567
    647
    663
    574
    600
    Option D
    39.7% 𝑜𝑓 801 − 250.17 = ? −63% 𝑜𝑓 801
    ≈ 40 × 8 – 250
    =? −63 × 8
    ?= 574

     


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