**Directions(1-5):** Find the missing term ‘?’ of the following series.

- 525,524,516,489,?,300
320425325400300Option B

-1^3,-2^3,-3^3,-4^3,-5^3

? = 425 - 24,36,72,180,?,1890
500525515540536Option D

*1.5,*2,*2.5,*3,*3.5

? = 540 - 32,37,27,42,?,47
1815201022Option E

+5,-10,+15,-20,+25

?= 22 - 12,10,17,47,?,909
172180198177183Option E

*1-2

*2-3

*3-4

*4-5

*5-6

? = 183 - 24,43,81,138,?,309
200214232222220Option B

+19*1

+19*2

+19*3

+19*4

+19*5

? = 214 - A boy covers 5 km north from his home, and then turns right to cover some distance at the speed of 4.8km/hr. in 2.5hours to reach his school. Find the shortest distance between his home and school.
1520161310Option D

Distance = 4.8*2.5 = 12 km

Shortest distance= (12^2 + 5^2)^1/2 = 13 km - Find the rate at which Rs.11500 yields Rs.5060 compound interest after 2 years when compounded annually.
2218252026Option D

Let the rate be r% p.a.

5060 = 11500*{(1+r/100)^2 -1}

=> 16560/11500 = (1+r/100)^2

=>r = 20% - The profit percent on an article ‘X’ worth Rs.1500 is same as the loss percent on an article ‘Y’ worth Rs.2100. If the selling price of the article ‘Y’ is Rs.1680. Find the selling price of the article ‘X’.
10001200180014001600Option C

Loss percent on article Y = (2100- 1680)/2100

= 20%

Profit on X = 20%

SP of article X = 1.2*1500 = Rs.1800 - A and B monthly incomes were Rs. 42000 and Rs.30000 resp. If A’s expenditure was 2/3rd of his income and B’s expenditure was 3/4th of his income. Find the sum of the monthly savings of A and B?
2300025025244702150022600Option D

A’s savings = 1/3*42000 = Rs.14000

B’s savings = ¾*30000 = Rs.7500

Sum = Rs.21500 - The average height of all the males and all the females of a family is 172 cm and 180 cm resp. If the family has only married couples with no unmarried member. Find the average height of the family.
190145160176157Option D

Let the number of male members be x.

Required average = (172x+180x)/2x = 176 cm