# Mixed Quantitative Aptitude Questions Set 143

Directions(1-5): What approximate value will come in place of question mark ‘?’ in the following questions:

1. 1701 ÷ 2100 + 3087 ÷ 6300 + 832 ÷ 5200 =?
1.11
1.25
2.23
1.46
2.05
Option D
1701 ÷ 2100 + 3087 ÷ 6300 + 832 ÷ 5200 =?
? = 0.81 + 0.49 + 0.16 = 1.46

2. 39% of 450 + 51% of 340 – 40% of 255 =?
112.5
230.6
246.9
201.8
250.7
Option C
39% of 450 + 51% of 340 – 40% of 255 =?
? = 39/100 × 450 + 51/100 × 340 – 40/100 × 255
= 246.9

3. 17 × 25 – 240 +? ÷ 41 = 354
4540
5646
5060
6929
6000
Option D
17 × 25 – 240 +? ÷ 41 = 354
? /41 = 354 – 425 + 240
⇒ ? = 41 × 169
⇒ ? = 6929

4. 3.4 × 2.6 × 5.4 ÷ 1.8 ÷ 0.17 =? ÷ 0.8
120.6
100.7
121.6
130.8
124.8
Option E
3.4 × 2.6 × 5.4 ÷ 1.8 ÷ 0.17 =? ÷ 0.8
? /0.8 = 156
⇒ ? = 124.8

5. ? ÷ 13 + 2262 ÷ 39 × 243 + 273 ÷ 3 = 5 × (1481 + 1376)
1500
1600
1200
1300
1100
Option D
? ÷ 13 + 2262 ÷ 39 × 243 + 273 ÷ 3 = 5 × (1481 + 1376)
? /13 + 14094 + 91 = 14,285
⇒ ?/13 = 100
⇒ ? = 1300

6. A milkman has 20 L of pure milk. He sells 5 L of it at profit of 20% and he mixes 5 L water in remaining quantity of milk. If he sells whole quantity of mixture at cost price, then find his percentage profit?
36%
20%
30%
15%
10%
Option C
Let 1 L of milk cost = Rs.10
So, in selling 5 L of milk he get = 1 5 × 5 × 10 Profit
If he professes to sell mixture at cost price then his profit = 5 × 10 Rs.
Overall percentage profit = (50+10)/( 20×10) × 100 = 30%

7. The sum of the radius and height of a cylinder is 18m. The total surface area of the cylinder is 792 m², what is the volume of the cylinder ? (in m³)
1302
1552
1694
1660
1545
Option C
Given, h + r = 18 m
According to question,
2πr (h + r) = 792
2 × 22/7 × r × 18 = 792
r = 7m
And h= 11m
Volume of the cylinder = πr²h = 22/7 × 7 × 7 × 11 = 22 × 77 = 1694 m³

8. In a 90 litre mixture of milk and water, percentage of water is only 30%. The milkman gave 18 litres of this mixture to a customer and then added 18 litres of water to the remaining mixture. What is the percentage of milk in the final mixture ?
71%
62%
49%
56%
60%
Option D
Initial water = 30 100 × 90 = 27 L
And, milk = 90 – 27 = 63 L
Required percentage = [70/100 × (90 – 18)]/90 × 100 = 56%

9. If the area of a circle is 616 𝐜𝐦^𝟐 , what would be the total surface area of a hemisphere having the same radius as the circle ?
1556
1848
1990
1676
1562
Option B
Radius of circle = √ 616×7/22 = 14 cm
Total surface area of hemisphere = 3πr 2 = 3 × 22/7 × 14 × 14 = 1848 cm^2

10. There are two mixtures of honey and water, the quantity of honey in them being 40% and 75% of the mixture respectively. If 5 gallons of the first are mixed with 8 gallons of the second, what will be the ratio of honey to water in the new mixture ?
8:9
3:7
8:5
1:2
3:4
Option C
Required ratio = [40/100 × 5 + 75/100 × 8]/[60/ 100 × 5 + 25/100 × 8]
= [2 + 6]/[3 + 2] = 8: 5