# Mixed Quantitative Aptitude Questions Set 144

1. A shopkeeper sells two articles-A & B. Cost price of article-B is 20% less than cost price of article-A and shopkeeper sells article-A and article-B at 40% profit and 20% profit respectively. If selling price of article-A is Rs.528 more than selling price of article-B, then find cost price of article B?
Rs. 1000
Rs. 910
Rs. 900
Rs. 880
Rs. 960
Option E
Let cost price of article – A be Rs. 10x
So, cost price of article – B = 10x × 80/100 = Rs. 8x
And, Selling price of article – A = 10x × 140/100 = Rs. 14x
And selling price of article – B = 8x × 120/ 100 = Rs. 9.6 x
ATQ, 14x – 9.6x = 528
4.4x = 528
x = Rs.120
Hence, cost price of article – B = 8x = Rs. 960

2. Area of circle is 144π cm^2 and radius of circle is equal to diagonal of a square. Find perimeter of square.
20√5 cm
18√3 cm
24√2 cm
12√2 cm
20√3 cm
Option C
Area of circle = πr²
ATQ, πr² = 144π
⇒ r = 12cm
Let side of a square be ‘a’ cm.
So, a² + a² = (12)²
2a² = 144
a² = 72
a = 6√2 cm
So, required perimeter = 4a = 24√2 cm

3. Ayush invested Rs.5000 in a scheme-A on S.I. for two years and he further invested the amount received from scheme-A on C.I. at the rate of 10% compounding annually for two years. If he received Rs.1218 as C.I., then find rate of interest of scheme-A?
18%
12%
8%
10%
14%
Option C
Let rate of interest offered by scheme – A be R% p.a.
Amount invested by Ayush at C.I = 5000 × R × 2/100 + 5000 = (100R + 5000) Rs.
Equivalent rate of interest of 10% C.I. for two years = 10 + 10 + (10 × 10)/100 = 21%
ATQ, [(100 R+5000) × 21]/100 = 1218
⇒ 21R + 1050 = 1218
⇒ R = 8%

4. A vessel of capacity of 70 liters is completely filled with milk. ‘x’ liters are taken out from the vessel and replaced by water and this process is repeated one more time. If final quantity of milk in the vessel is 44.8 liters, then find value of ‘x’?
16
12
10
14
18
Option D
44.8 = 70 (1 − x /70)^2
16/25 = (1 – x/ 70)^2
So, x = 14, 126 lit.
As x cannot be greater than 70 litres
So, x =14 lit.
So, 14 liters of mixture can be taken out as capacity of vessel is only 70 liters.

5. In 2018, a school has 1200 students and ratio of boys to girls is 11 : 9. If 92% of the total students got passed in 2018 and 95% of the total boys got passed in 2018 then, find the percentage of girls who got passed in 2018?
74(1/3)%
89(1/5)%
80(1/2)%
88(1/3)%
81(1/2)%
Option D
Total number of students who got passed in 2018 = 1200 × 92/100 = 1104
Total number of boys who got passed in 2018 = 1200 × 11/20 × 95/100 = 627
Required % = (1104 − 627)/1200 × 9/20 × 100
= 477/540 × 100 = 265/3 = 88(1/3)%

6. Directions(6-10): What approximate value will come in place of question mark ‘?’ in the following questions.

7. 𝟐𝟑. 𝟖𝟑% 𝐨𝐟 𝟔𝟐𝟓. 𝟎𝟐 − 𝟏𝟎𝟎. 𝟎𝟏 =? % 𝐨𝐟 𝟑𝟓𝟗𝟗. 𝟗𝟗 + 𝟗𝟖. 𝟏𝟑 ÷ 𝟔. 𝟗𝟗𝟗
3
2
1
4
6
Option C
𝟐𝟑. 𝟖𝟑% 𝐨𝐟 𝟔𝟐𝟓. 𝟎𝟐 − 𝟏𝟎𝟎. 𝟎𝟏 =? % 𝐨𝐟 𝟑𝟓𝟗𝟗. 𝟗𝟗 + 𝟗𝟖. 𝟏𝟑 ÷ 𝟔. 𝟗𝟗𝟗
24/100 × 625 – 100 = ?/100 × 3600 + 98/7
⇒ 50 = ? × 36 + 14
⇒ ? = (50 – 14)/36
⇒ ? = 1

8. 𝟔𝟓𝟗. 𝟗𝟕 × (? )^𝟐 = (𝟔𝟒. 𝟗𝟐) ^𝟐 + 𝟐𝟒. 𝟗𝟗𝟕% 𝐨𝐟 𝟔𝟖𝟔𝟎. 𝟎𝟎𝟏
3
1
2
4
5
Option A
𝟔𝟓𝟗. 𝟗𝟕 × (? )^𝟐 = (𝟔𝟒. 𝟗𝟐) ^𝟐 + 𝟐𝟒. 𝟗𝟗𝟕% 𝐨𝐟 𝟔𝟖𝟔𝟎. 𝟎𝟎𝟏
660 ×(? )^2 = (65)² + 25/100 × 6860
=>660 × (? )^2= 4225 + 1715
=>(? )^2= 5940/660
=>? = √9
=> ? = 3

9. 𝟓𝟔𝟕𝟕. 𝟏𝟑𝟐𝟏 + 𝟒𝟗𝟏𝟑. 𝟗𝟏𝟑𝟑 − 𝟑𝟕𝟗𝟖. 𝟗𝟐 = ? +𝟐𝟎. 𝟎𝟎𝟓% 𝐨𝐟 𝟑𝟗𝟔𝟎. 𝟏𝟑𝟐1
5000
4000
3000
2000
6000
Option E
𝟓𝟔𝟕𝟕. 𝟏𝟑𝟐𝟏 + 𝟒𝟗𝟏𝟑. 𝟗𝟏𝟑𝟑 − 𝟑𝟕𝟗𝟖. 𝟗𝟐 = ? +𝟐𝟎. 𝟎𝟎𝟓% 𝐨𝐟 𝟑𝟗𝟔𝟎. 𝟏𝟑𝟐1
5677 + 4914 – 3799 = ? + 20/100 × 3960
=>6792 = ? + 792
=> ? = 6000

10. ? = 𝟓𝟔. 𝟗𝟏𝟓𝟔 𝐨𝐟 𝟐𝟖. 𝟎𝟓𝟔 ÷ 𝟕𝟔. 𝟎𝟕𝟓𝟒 × 𝟓. 𝟗𝟕𝟒
112
126
139
150
130
Option B
? = 𝟓𝟔. 𝟗𝟏𝟓𝟔 𝐨𝐟 𝟐𝟖. 𝟎𝟓𝟔 ÷ 𝟕𝟔. 𝟎𝟕𝟓𝟒 × 𝟓. 𝟗𝟕𝟒
=>? = 57 × 28 × 1/76 × 6
=>? = 126

11. 𝟏𝟏. 𝟗𝟗𝟒% 𝐨𝐟 𝟓𝟎𝟎. 𝟎𝟑 + 𝟏𝟔.𝟎𝟏×?/ 𝟐𝟎.𝟎𝟒 = 𝟏𝟓𝟎. 𝟎𝟏𝟐𝟑 + (𝟐𝟓. 𝟗𝟓𝟑𝟏 × 𝟑𝟓. 𝟏𝟐𝟏)
1122
1330
1250
1000
1200
Option C
𝟏𝟏. 𝟗𝟗𝟒% 𝐨𝐟 𝟓𝟎𝟎. 𝟎𝟑 + 𝟏𝟔.𝟎𝟏×?/ 𝟐𝟎.𝟎𝟒 = 𝟏𝟓𝟎. 𝟎𝟏𝟐𝟑 + (𝟐𝟓. 𝟗𝟓𝟑𝟏 × 𝟑𝟓. 𝟏𝟐𝟏)
12/100 × 500 + (16 × ?)/20 = 150 + (26 × 35)
=> 60 + (4 × ?)/ 5 = 150 + 910
=>4 × ?/5 = 1060 – 60
=>? = (1000 × 5)/ 4
=>? = 1250

## One Thought to “Mixed Quantitative Aptitude Questions Set 144”

1. merchant sales rep

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