# Mixed Quantitative Aptitude Questions Set 145

Directions(1-5): Table given below shows the data of students and teachers of different branches in an engineering college. Study the below mentioned table carefully to answer the following questions. 1. Number of teachers in Chemical branch is what percent of number of students in Mechanical branch?

2(3/8) %
5(3/7) %
2(5/9) %
1(3/8) %
5(5/9) %
Option E
Let number of students and teachers in Chemical branch be ‘13x’ & ‘x’ respectively.
So, 13x – x = 168
x = 14
And number of teachers in Chemical branch = x = 14
Let number of students and teachers in mechanical branch be 21y & 2y respectively.
So, 21y – 2y = 228
19y = 228
y = 12
Required Percentage = 14/252 × 100 = 5(5/9) %

2. If the ratio of number of boys to number of girls in Civil branch is 4 : 3, then find number of girls in Civil branch is what percent of number of teachers in that branch?
139(1/2)%
122(2/5)%
130(1/7)%
139(2/7)%
112(1/5)%
Option D
Let number of students & teachers in Civil branch be ‘13x’ and ‘4x’ respectively.
So, 13x – 4x = 126
x = 14
Hence, number of students in Civil branch = 13x = 182
Number of teachers in Civil branch = 4x = 56
Now, Number of girls in Civil branch = 182 × 3/7 = 78
Required % = 78/56 × 100 = 975/7 % = 139(2/7)%

3. Find the ratio of number of students in I.T. and Electrical branch together to number of teachers in I.T. and Electrical branch together.
40 : 3
41 : 6
43 : 16
42 : 7
49 : 3
Option B
Let number of students & teachers in I.T. branch be ‘19x’ & ‘3x’ respectively.
So, 19x – 3x = 256
x = 16
Hence, number of students in I.T. branch = 19x = 304
And number of teachers in I.T. branch = 3x = 48
Let number of students & teaches in Electrical branch be ‘15y’ & ‘2y’ respectively.
So, 15y – 2y = 234
y = 18
Hence, number of students in Electrical branch = 15y = 270
And number of teachers in Electrical branch = 2y = 36
Now, Required ratio = (304 + 270)/(48 +36) = 574:84 = 41 : 6

4. Number of teachers in I.T. branch is how much more or less than number of teachers in Chemical branch?
30
21
24
34
28
Option D
Let number of teachers & students in I.T. branch be ‘3x’ & ‘19x’ respectively.
So, 19x – 3x = 256
x = 16
So, number of teachers in I.T. branch = 3x = 48
Let numbers of teacher and students in Chemical branch be ‘y’ & ‘13y’ respectively.
So, 13y – y = 168
y = 14
Hence, number of teachers in Chemical branch = y = 14
Required difference = 48 – 14 = 34

5. Number of students in Mechanical branch is what percent of number of students in Computer Science branch?
75%
70%
77%
80%
84%
Option E
Let number of students & teachers in Computer Science branch be ‘12x’ & ‘x’ respectively.
So, 12x – x = 275
x = 25
So, number of students in Computer Science branch = 12x = 300
Now, let number of students & teachers in mechanical branch be ‘21y’ & ‘2y’ respectively.
So, 21y – 2y = 228
y = 12
Hence, number of students in Mechanical branch = 21y = 252
So, required % = 252/300 × 100 = 84%

6. Directions(6-10): Find the missing term ‘?’ of the following series.

7. 210, 130, 60, ?, 6, 2
30
21
25
22
26
Option A
6^3−6,5^3+5,4^3−4,3^3+3,2^3−2,1^3+1
3^3+3=30

8. 6 ,15, 45, 157.5, ?, 2835
600
550
525
630
515
Option D
×2.5,× 3,× 3.5,× 4
157.5 × 4 = 630

9. 567,1140, 2290, ?, 9206, 18434
4594
4250
4000
4128
4424
Option A
×2 + 6,×2 + 10,× 2 + 14,× 2+ 18
2290×2 +14 = 4594

10. 17, 38, ?, 508,2565,15426
100
115
123
120
125
Option C
×2+ 2^2,×3+3^2,× 4 + 4^2
38×3 +3^2 = 123

11. 2, 60,10, 120, 30, ?
200
220
225
222
210
Option E
1^3+1, 4^3 – 4,2^3+2,5^3 –5,3^3+3,6^3 – 6
6^3−6 = 210