**Directions(1-5):** Table given below shows the data of students and teachers of different branches in an engineering college. Study the below mentioned table carefully to answer the following questions.

- Number of teachers in Chemical branch is what percent of number of students in Mechanical branch?
2(3/8) %5(3/7) %2(5/9) %1(3/8) %5(5/9) %Option E

Let number of students and teachers in Chemical branch be ‘13x’ & ‘x’ respectively.

So, 13x – x = 168

x = 14

And number of teachers in Chemical branch = x = 14

Let number of students and teachers in mechanical branch be 21y & 2y respectively.

So, 21y – 2y = 228

19y = 228

y = 12

Required Percentage = 14/252 × 100 = 5(5/9) % - If the ratio of number of boys to number of girls in Civil branch is 4 : 3, then find number of girls in Civil branch is what percent of number of teachers in that branch?
139(1/2)%122(2/5)%130(1/7)%139(2/7)%112(1/5)%Option D

Let number of students & teachers in Civil branch be ‘13x’ and ‘4x’ respectively.

So, 13x – 4x = 126

x = 14

Hence, number of students in Civil branch = 13x = 182

Number of teachers in Civil branch = 4x = 56

Now, Number of girls in Civil branch = 182 × 3/7 = 78

Required % = 78/56 × 100 = 975/7 % = 139(2/7)% - Find the ratio of number of students in I.T. and Electrical branch together to number of teachers in I.T. and Electrical branch together.
40 : 341 : 643 : 1642 : 749 : 3Option B

Let number of students & teachers in I.T. branch be ‘19x’ & ‘3x’ respectively.

So, 19x – 3x = 256

x = 16

Hence, number of students in I.T. branch = 19x = 304

And number of teachers in I.T. branch = 3x = 48

Let number of students & teaches in Electrical branch be ‘15y’ & ‘2y’ respectively.

So, 15y – 2y = 234

y = 18

Hence, number of students in Electrical branch = 15y = 270

And number of teachers in Electrical branch = 2y = 36

Now, Required ratio = (304 + 270)/(48 +36) = 574:84 = 41 : 6 - Number of teachers in I.T. branch is how much more or less than number of teachers in Chemical branch?
3021243428Option D

Let number of teachers & students in I.T. branch be ‘3x’ & ‘19x’ respectively.

So, 19x – 3x = 256

x = 16

So, number of teachers in I.T. branch = 3x = 48

Let numbers of teacher and students in Chemical branch be ‘y’ & ‘13y’ respectively.

So, 13y – y = 168

y = 14

Hence, number of teachers in Chemical branch = y = 14

Required difference = 48 – 14 = 34 - Number of students in Mechanical branch is what percent of number of students in Computer Science branch?
75%70%77%80%84%Option E

Let number of students & teachers in Computer Science branch be ‘12x’ & ‘x’ respectively.

So, 12x – x = 275

x = 25

So, number of students in Computer Science branch = 12x = 300

Now, let number of students & teachers in mechanical branch be ‘21y’ & ‘2y’ respectively.

So, 21y – 2y = 228

y = 12

Hence, number of students in Mechanical branch = 21y = 252

So, required % = 252/300 × 100 = 84% - 210, 130, 60, ?, 6, 2
3021252226Option A

6^3−6,5^3+5,4^3−4,3^3+3,2^3−2,1^3+1

3^3+3=30 - 6 ,15, 45, 157.5, ?, 2835
600550525630515Option D

×2.5,× 3,× 3.5,× 4

157.5 × 4 = 630 - 567,1140, 2290, ?, 9206, 18434
45944250400041284424Option A

×2 + 6,×2 + 10,× 2 + 14,× 2+ 18

2290×2 +14 = 4594 - 17, 38, ?, 508,2565,15426
100115123120125Option C

×2+ 2^2,×3+3^2,× 4 + 4^2

38×3 +3^2 = 123 - 2, 60,10, 120, 30, ?
200220225222210Option E

1^3+1, 4^3 – 4,2^3+2,5^3 –5,3^3+3,6^3 – 6

6^3−6 = 210

**Directions(6-10):** Find the missing term ‘?’ of the following series.