**Directions(1-5):** Find the value of x and y and choose a correct option from the following questions.

- I. x^2 + 14x + 49 = 0

II. y^2 + 9y = 0

y > xx > yy >= xx >= yNo relationOption E

X = -7

y = 0,-9

No relation - I. 3x^2 – 4x – 32 = 0

II. 2y^2 – 17y + 36 = 0

x >= yy >= xx > yNo relationy > xOption B

X = 4,-8/3

y = 4,9/2

y >=x - I. 9x^2 – 29x + 22 = 0

II. y^2 – 7y + 12 = 0

x >= yy > xNo relationx > yy >= xOption B

x = 2, 11/9

y = 3,4

y > x - I. 4x + 7y = 42

II. 3x – 11y = – 1

x > yNo relationx >= yy >= xy > xOption A

X =7

y = 2

x>y - I. 3x^2 – 19x – 14 = 0

II. 2y^2 + 5y + 3 = 0

x >= yy >= xy > xx > yNo relationOption D

X = 7,-2/3

y = -3/2,-1

x > y - A lent Rs. 5000 to B for 2 years and Rs. 3000 to C for 4 years on simple interest at the same rate of interest and received Rs. 2200 in all from both of them as interest. The rate of interest per annum is:
16%18%10%12%14%Option C

5000×r×2 /100 + 3000×4×r /100 = 2200

=>22000r = 22000 × 10

=>r = 10% - What would be the compound interest on amount of Rs. 8000 at the rate of 15% per annum in three years?
Rs. 4234Rs. 4167Rs. 4000Rs. 4125Rs. 4040Option B

C.I.= 8000 (1+ 15/100)^3 – 8000

= 8000 ×( 23×23×23)/(20×20×20)− 8000 = Rs. 4167 - A certain number of men can finish a piece of work in 100 days. If however there were l0 men less, it would take another 10 days to finish the work. How many men were there originally?
907881110100Option D

x × 100 = (x − 10) × 110

=> 100x = 110x – 1100

=> 10x = 1100

=>x = 110 - A sum of Rs. 6,000 is deposited for 3 years at 5% per annuam compound interest (compounded annually). The difference of interests for 3 and 2 years will be :
Rs.389.14Rs.323.11Rs.313.14Rs.300.15Rs.330.75Option E

For 2 year, C.I = 6000 (1 + 5 /100)^2 −6000 = 615

For 3 year, C.I. = 6000 (1+ 5/ 100)^2 − 6000 = 945.75

Required different = Rs.330.75 - Ratio of upstream speed and downstream speed is 3 : 5. If a boat travels in upstream 22.5 km in 2:30 hrs, find the speed of boat in still water.
1020141217Option D

Let upstream speed = 3x

Downstream speed = 5x

22.5/3x = 22.5

x = 3

Downstream speed= 5 × 3 = 15

Speed of boat in still water = 1/2 (15 +9) = 12 kmph