# Mixed Quantitative Aptitude Questions Set 150

1. A person invests money in 3 different schemes for 3 years, 5 years and 6 years at 10%, 12% and 15% simple interest respectively. At the completion of each scheme, he gets the same interest. The ratio of his investments is:
4:3:3
3:2:1
6:3:2
5:2:4
1:1:2
Option C
(3×10%)of A = (5 × 12%) of B = (6 × 15%) of C
(A, B, C are the investments)
0.3 A = 0.6 B = 0.9 C
A:B:C: = 6:3:2

2. A sells a horse to B for Rs. 9720, thereby losing 19 per cent, B sells it to C at a price which would have given A 17 per cent profit. Find B’s gain.
4220
4400
4000
4141
4320
Option E
CP for A = 9720*100/(100-19) = 12000
SP with 17% profit for A = 12000*(100+17)/100 = 14040
B’s gain = 14040 – 9720 = 4320

3. In an election between 2 candidates, 75% of the voters cast their votes, out of which 2% votes were declared invalid. A candidate got 18522 votes which were 75% of the valid votes. The total number of voters enrolled in the election was:
28200
31300
24500
33600
30000
Option D
Let total number of voters = x
Voters who cast their votes = 0.75x
Valid votes polled for a candidate
=> 18522 = 0.98*0.75*0.75x
=>x = 33600

4. The length of each side of a rhombus is equal to the length of the side of square whose diagonal is 80√2. If the length of the diagonals of rhombus are in ratio 3:4, then its area (in cm^2) is:
6144
6424
6901
5580
6000
Option A
Length of each side of rhombus = 80 cm
Let the diagonals = 3x, 4x
(3x/2 )^2 + (4x/2 )^2 = 6400
X^2 = 6400 ×4/25 = 1024
=> x = 32
Area of rhombus = 1/2× 96 × 128 = 6144 cm^2

5. Two vessels A and B contains milk and water mixed in the ratio 8:5 and 5:2 respectively. The ratio in which these two mixture be mixed to get a new mixture containing 69(3/13)% milk is:
3:4
1:3
2:7
7:8
8:9
Option C
8/13 ==== 5/7
====9/13
2/91 ====1/13
2:7

6. Directions(6-10): What approximate value will come in place of question mark ‘?’ in the following questions.

7. ? = 𝟓𝟔. 𝟗𝟏𝟓𝟔 𝐨𝐟 𝟐𝟖. 𝟎𝟓𝟔 ÷ 𝟕𝟔. 𝟎𝟕𝟓𝟒 × 𝟓. 𝟗𝟕𝟒3
125
115
100
126
110
Option D
? = 𝟓𝟔. 𝟗𝟏𝟓𝟔 𝐨𝐟 𝟐𝟖. 𝟎𝟓𝟔 ÷ 𝟕𝟔. 𝟎𝟕𝟓𝟒 × 𝟓. 𝟗𝟕𝟒3
=>? = 57 × 28 × 1/76 × 6
=>? = 126

8. 𝟓𝟔𝟕𝟕. 𝟏𝟑𝟐𝟏 + 𝟒𝟗𝟏𝟑. 𝟗𝟏𝟑𝟑 − 𝟑𝟕𝟗𝟖. 𝟗𝟐 = ? +𝟐𝟎. 𝟎𝟎𝟓% 𝐨𝐟 𝟑𝟗𝟔𝟎. 𝟏𝟑𝟐1
6790
5670
6160
6000
5909
Option D
𝟓𝟔𝟕𝟕. 𝟏𝟑𝟐𝟏 + 𝟒𝟗𝟏𝟑. 𝟗𝟏𝟑𝟑 − 𝟑𝟕𝟗𝟖. 𝟗𝟐 = ? +𝟐𝟎. 𝟎𝟎𝟓% 𝐨𝐟 𝟑𝟗𝟔𝟎. 𝟏𝟑𝟐1
=>5677 + 4914 – 3799 = ? + 20/100 × 3960
=>6792 = ? + 792
=>? = 6000

9. 𝟔𝟓𝟗. 𝟗𝟕 × (? )^𝟐 = (𝟔𝟒. 𝟗𝟐)^𝟐 + 𝟐𝟒. 𝟗𝟗𝟕% 𝐨𝐟 𝟔𝟖𝟔𝟎. 𝟎𝟎𝟏3
2
5
3
1
6
Option C
𝟔𝟓𝟗. 𝟗𝟕 × (? )^𝟐 = (𝟔𝟒. 𝟗𝟐)^𝟐 + 𝟐𝟒. 𝟗𝟗𝟕% 𝐨𝐟 𝟔𝟖𝟔𝟎. 𝟎𝟎𝟏3
=> 660 ×(? )^2 = (65)² + 25/100 × 6860
=>660 × (? )^2= 4225 + 1715
=> (? )^2= 5940/660
=>? = √9
=>? = 3

10. 𝟐𝟑. 𝟖𝟑% 𝐨𝐟 𝟔𝟐𝟓. 𝟎𝟐 − 𝟏𝟎𝟎. 𝟎𝟏 =? % 𝐨𝐟 𝟑𝟓𝟗𝟗. 𝟗𝟗 + 𝟗𝟖.𝟏𝟑 ÷ 𝟔. 𝟗𝟗𝟗𝟗
2
1
3
5
4
Option B
𝟐𝟑. 𝟖𝟑% 𝐨𝐟 𝟔𝟐𝟓. 𝟎𝟐 − 𝟏𝟎𝟎. 𝟎𝟏 =? % 𝐨𝐟 𝟑𝟓𝟗𝟗. 𝟗𝟗 + 𝟗𝟖.𝟏𝟑 ÷ 𝟔. 𝟗𝟗𝟗𝟗
=> 24/100 × 625 – 100 = ?/100 × 3600 + 98/7
⇒ 50 = ? × 36 + 14
⇒ ? = (50 – 14)/36
⇒ ? = 1

11. 𝟏𝟏.𝟗𝟗𝟒% 𝐨𝐟 𝟓𝟎𝟎. 𝟎𝟑 + 𝟏𝟔.𝟎𝟏×?/𝟐𝟎.𝟎𝟒 = 𝟏𝟓𝟎. 𝟎𝟏𝟐𝟑 + (𝟐𝟓. 𝟗𝟓𝟑𝟏 × 𝟑𝟓. 𝟏𝟐𝟏)
1122
1250
1225
1420
1330
Option B
𝟏𝟏. 𝟗𝟗𝟒% 𝐨𝐟 𝟓𝟎𝟎. 𝟎𝟑 + 𝟏𝟔.𝟎𝟏×?/𝟐𝟎.𝟎𝟒 = 𝟏𝟓𝟎. 𝟎𝟏𝟐𝟑 + (𝟐𝟓. 𝟗𝟓𝟑𝟏 × 𝟑𝟓. 𝟏𝟐𝟏)
12/100 × 500 + 16 × ?/20 = 150 + (26 × 35)
=>60 + 4 × ?/ 5 = 150 + 910
=> 4 × ? /5 = 1060 – 60
=>? = 1000 × 5/4
=> ? = 1250