# Mixed Quantitative Aptitude Questions Set 151

Directions(1-5): Find the missing term ‘?’ of the following series.

1. 3, 11, 31, 69, 131, ?
220
200
215
230
223
Option E
1^3+2, 2^3+3, 3^3+4, 4^3+5, 5^3+6, 6^3+7
? = 223

2. 12, 25, 48, 99, 194, 393, ?
700
711
717
780
720
Option D
*2+1, *2-2, *2+3, *2-4, *2+5,*2-6
? = 780

3. 1, 13, 83, 419, 1679, ?
5151
5000
5039
5100
5230
Option C
*7+6,*6+5,*5+4,*4+3,*3+2
? = 5039

4. 15, 12, 31, 148, ?
1120
1000
1027
1122
1515
Option C
*1-3,*3-5,*5-7,*7-9
? = 1027

5. 117.5, 117, 119, 111, 143, ?
10
12
14
15
13
Option D
-0.5,+2,-8,+32,-128
? = 15

6. Satish and Bhavya entered into a partnership with Rs 15000 and Rs 18000 respectively. Abhishek joined them after ‘x’ months and contributes Rs 24000 and Bhavya left ‘x’ month before the end of year. If they share profit at the end of the year. If they share profit in the ratio 10 : 9 : 12. Find the value of ‘x’.
2
4
3
5
6
Option C
Satish : Bhavya : Abhishek
=>15* 12 : 18 *(12 x) : 24(12 x)
=>10 : 9 : 12
⇒ 15 × 12 /[18 × (12 − x)] = 10/9
⇒ 12 – x = 9
⇒ x = 3 month

7. Sakshi married 6 years ago. Today her age is 5/4 times her age at the time of her marriage and her son is 1/5 of her age. Find the ratio of Sakshi age to her son’s age after 10 years ?
3/4
2/3
1/2
5/2
1/3
Option D
Let present age of Sakshi = x
ATQ, 𝑥 = 5/4 (𝑥 − 6)
⇒ 4x = 5x – 30
⇒ x= 30
Present age of her son = 30/5 = 6 years
Required ratio = [30 + 10]/[ 6 + 10] = 40/16 = 5/2

8. Two boats, travelling at 5 Km/h and 10 Km/h respectively, head directly towards each other. They are now at a distance of 20 km from each other. How far apart are they (in Kms) one minute before they collide?
1/5
1/6
1/3
1/4
1/2
Option D
Relative speed of boats= 5+10 = 15 km/hr
In m/sec 15 × 5/18 = 25/6 m/sec.
Distance covered in one minute = 25/6 × 60 = 250 m = 1/4 km

9. If the volume and curved surface area of a cylinder 616 𝐦^𝟑 and 352m^2 respectively, what is the total surface area of the cylinder (in 𝐦^𝟐 )?
429
400
415
412
425
Option A
Πr^2h/ 2πrh = 616/352
=>𝑟 = 3.5 m
𝜋𝑟^2ℎ = 616
h = 616/(11 × 3.5) = 16 m
Total S.A. = 2𝜋𝑟ℎ + 2𝜋𝑟^2 = 2πr(h + r)
= 2 × 22/7 × 3.5(3.5 + 16)
= 429 m^2

10. In an alloy, zinc and copper are in the ratio 1 : 2. In the second alloy the same elements are in the ratio 2 : 3. In what ratio should these two alloys be mixed to form a new alloy in which the two elements are in ratio 5 : 8?
3:4
3:10
2:5
2:1
1:3
Option B
Required ratio = [1/ 65]/ [2 /39] = 3:10