Mixed Quantitative Aptitude Questions Set 151

Directions(1-5): Find the missing term ‘?’ of the following series.

  1. 3, 11, 31, 69, 131, ?
    220
    200
    215
    230
    223
    Option E
    1^3+2, 2^3+3, 3^3+4, 4^3+5, 5^3+6, 6^3+7
    ? = 223

     

  2. 12, 25, 48, 99, 194, 393, ?
    700
    711
    717
    780
    720
    Option D
    *2+1, *2-2, *2+3, *2-4, *2+5,*2-6
    ? = 780

     

  3. 1, 13, 83, 419, 1679, ?
    5151
    5000
    5039
    5100
    5230
    Option C
    *7+6,*6+5,*5+4,*4+3,*3+2
    ? = 5039

     

  4. 15, 12, 31, 148, ?
    1120
    1000
    1027
    1122
    1515
    Option C
    *1-3,*3-5,*5-7,*7-9
    ? = 1027

     

  5. 117.5, 117, 119, 111, 143, ?
    10
    12
    14
    15
    13
    Option D
    -0.5,+2,-8,+32,-128
    ? = 15

     

  6. Satish and Bhavya entered into a partnership with Rs 15000 and Rs 18000 respectively. Abhishek joined them after ‘x’ months and contributes Rs 24000 and Bhavya left ‘x’ month before the end of year. If they share profit at the end of the year. If they share profit in the ratio 10 : 9 : 12. Find the value of ‘x’.
    2
    4
    3
    5
    6
    Option C
    Satish : Bhavya : Abhishek
    =>15* 12 : 18 *(12 x) : 24(12 x)
    =>10 : 9 : 12
    ⇒ 15 × 12 /[18 × (12 − x)] = 10/9
    ⇒ 12 – x = 9
    ⇒ x = 3 month

     

  7. Sakshi married 6 years ago. Today her age is 5/4 times her age at the time of her marriage and her son is 1/5 of her age. Find the ratio of Sakshi age to her son’s age after 10 years ?
    3/4
    2/3
    1/2
    5/2
    1/3
    Option D
    Let present age of Sakshi = x
    ATQ, 𝑥 = 5/4 (𝑥 − 6)
    ⇒ 4x = 5x – 30
    ⇒ x= 30
    Present age of her son = 30/5 = 6 years
    Required ratio = [30 + 10]/[ 6 + 10] = 40/16 = 5/2

     

  8. Two boats, travelling at 5 Km/h and 10 Km/h respectively, head directly towards each other. They are now at a distance of 20 km from each other. How far apart are they (in Kms) one minute before they collide?
    1/5
    1/6
    1/3
    1/4
    1/2
    Option D
    Relative speed of boats= 5+10 = 15 km/hr
    In m/sec 15 × 5/18 = 25/6 m/sec.
    Distance covered in one minute = 25/6 × 60 = 250 m = 1/4 km

     

  9. If the volume and curved surface area of a cylinder 616 𝐦^𝟑 and 352m^2 respectively, what is the total surface area of the cylinder (in 𝐦^𝟐 )?
    429
    400
    415
    412
    425
    Option A
    Πr^2h/ 2πrh = 616/352
    =>𝑟 = 3.5 m
    𝜋𝑟^2ℎ = 616
    h = 616/(11 × 3.5) = 16 m
    Total S.A. = 2𝜋𝑟ℎ + 2𝜋𝑟^2 = 2πr(h + r)
    = 2 × 22/7 × 3.5(3.5 + 16)
    = 429 m^2

     

  10. In an alloy, zinc and copper are in the ratio 1 : 2. In the second alloy the same elements are in the ratio 2 : 3. In what ratio should these two alloys be mixed to form a new alloy in which the two elements are in ratio 5 : 8?
    3:4
    3:10
    2:5
    2:1
    1:3
    Option B
    Required ratio = [1/ 65]/ [2 /39] = 3:10

     


Related posts

Leave a Comment