Mixed Quantitative Aptitude Questions Set 156

Directions(1-5): Find the odd one out of the following series.

  1. 11,16,32,59,75,81
    75
    32
    16
    81
    11
    Option D
    +5^1,+4^2,+3^3,+2^4,+1^5
    76 should be in place of 81.

     

  2. 21,120,208,295,351,406
    21
    295
    120
    208
    406
    Option B
    +99,+88,+77,+66,+55
    285 should be in place of 295.

     

  3. 41,50,75,124,245,470
    41
    50
    470
    75
    124
    Option C
    +3^2,+5^2, +7^2, +11^2, +13^2
    414 should be in place of 470.

     

  4. 240,220,198,170,140,110
    240
    220
    140
    110
    170
    Option B
    -2*9, -2*8, -2*7, -2*6, -2*5
    222 should be in place of 220.

     

  5. 10,22,46,118,202,310
    22
    10
    118
    46
    202
    Option D
    +12*1, +12*3, +12*5, +12*7, +12*9
    58 should be in place of 46.

     

  6. A shopkeeper bought an article for Rs.10x and marked it ‘x’% above the cost price and sold it after two consecutive discounts of 20% and 25%. Find the difference between the marked price and the cost price of the article if in this transaction, he has a profit of Rs.384.
    Rs.1400
    Rs.1250
    Rs.1320
    Rs.1000
    Rs.1440
    Option E
    MP = 10x*(100+x)/100 = Rs.10x+0.1x^2
    SP = 10x+384 = (10x+0.1x^2)*0.75*0.80
    10x+384 = 6x+0.06x^2
    => 3x^2 -200x – 19200 = 0
    => x=120
    CP = Rs.1200
    MP = 1200*2.20 = Rs.2640
    Difference = 2640 – 1200 = Rs.1440

     

  7. P,Q and R started a business together with an initial investment in the ratio 4:7:10 resp. After one year P,Q and R made additional investments of Rs.4000, Rs. 4500 and Rs.5000 resp. Find the initial investment of Q, if the profit share of P out of the total profit of Rs.5310 after two years is Rs.1180.
    Rs.5125
    Rs.5200
    Rs.5250
    Rs.5115
    Rs.5000
    Option C
    Ratio of their investments = 4x+4x+4000:7x+7x+4500:10x+10x+5000
    = 8x+4000:14x+4500:20x+5000
    (8x+4000)/(42x+13500) = 1180/5310
    =>x = 750
    Initial investment of Q = 7*750 = Rs.5250

     

  8. Vessel A contains mixture of milk and water mixed in the ratio of 11:3 resp. Another Vessel B contains 72 litres mixture of milk and water mixed in the ratio of 7:2 resp. half of the mixture from Vessel A is taken out and poured in Vessel B. Now, the ratio of milk to water in Vessel B becomes is 61:17. Find the difference in the quantities of milk and water present in Vessel A initially.
    87
    80
    120
    96
    100
    Option D
    [(56+11x/2)]/[16 + 3x/2] = 61/17
    =>x = 12
    Difference = 132 – 36 = 96 L

     

  9. A contractor got a contract of constructing a bridge in 45 days. He employed 75 workers for the work but after 40 days he realized that only 75% of the work is done. How many more workers does he need to employ so as to complete the work on time?
    125
    100
    110
    115
    120
    Option A
    Let the contractor employed ‘x’ more workers after 40 days.
    (75*40)/0.75 = {(x+75)*5}/0.25
    => 20x + 1500 = 4000
    =>x = 125

     

  10. Present ages of A and B are in the ratio is 7:5 resp. Present age of C is 20% more than the age of B five years ago. Find the present age of A, if the present average age of A, B and C is 2 years more than the present age of B.
    20
    18
    16
    12
    28
    Option E
    Present age of C = (5x-5)*1.20 = 6x-6 years
    7x + 5x + 6x – 6 = 3*(5x+2)
    =>18x – 6 = 15x+6
    =>x = 4
    Present age of A = 28 years

     


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