**Directions(1-5):** Find the odd one out of the following series.

- 11,16,32,59,75,81
7532168111Option D

+5^1,+4^2,+3^3,+2^4,+1^5

76 should be in place of 81. - 21,120,208,295,351,406
21295120208406Option B

+99,+88,+77,+66,+55

285 should be in place of 295. - 41,50,75,124,245,470
415047075124Option C

+3^2,+5^2, +7^2, +11^2, +13^2

414 should be in place of 470. - 240,220,198,170,140,110
240220140110170Option B

-2*9, -2*8, -2*7, -2*6, -2*5

222 should be in place of 220. - 10,22,46,118,202,310
221011846202Option D

+12*1, +12*3, +12*5, +12*7, +12*9

58 should be in place of 46. - A shopkeeper bought an article for Rs.10x and marked it ‘x’% above the cost price and sold it after two consecutive discounts of 20% and 25%. Find the difference between the marked price and the cost price of the article if in this transaction, he has a profit of Rs.384.
Rs.1400Rs.1250Rs.1320Rs.1000Rs.1440Option E

MP = 10x*(100+x)/100 = Rs.10x+0.1x^2

SP = 10x+384 = (10x+0.1x^2)*0.75*0.80

10x+384 = 6x+0.06x^2

=> 3x^2 -200x – 19200 = 0

=> x=120

CP = Rs.1200

MP = 1200*2.20 = Rs.2640

Difference = 2640 – 1200 = Rs.1440 - P,Q and R started a business together with an initial investment in the ratio 4:7:10 resp. After one year P,Q and R made additional investments of Rs.4000, Rs. 4500 and Rs.5000 resp. Find the initial investment of Q, if the profit share of P out of the total profit of Rs.5310 after two years is Rs.1180.
Rs.5125Rs.5200Rs.5250Rs.5115Rs.5000Option C

Ratio of their investments = 4x+4x+4000:7x+7x+4500:10x+10x+5000

= 8x+4000:14x+4500:20x+5000

(8x+4000)/(42x+13500) = 1180/5310

=>x = 750

Initial investment of Q = 7*750 = Rs.5250 - Vessel A contains mixture of milk and water mixed in the ratio of 11:3 resp. Another Vessel B contains 72 litres mixture of milk and water mixed in the ratio of 7:2 resp. half of the mixture from Vessel A is taken out and poured in Vessel B. Now, the ratio of milk to water in Vessel B becomes is 61:17. Find the difference in the quantities of milk and water present in Vessel A initially.
878012096100Option D

[(56+11x/2)]/[16 + 3x/2] = 61/17

=>x = 12

Difference = 132 – 36 = 96 L - A contractor got a contract of constructing a bridge in 45 days. He employed 75 workers for the work but after 40 days he realized that only 75% of the work is done. How many more workers does he need to employ so as to complete the work on time?
125100110115120Option A

Let the contractor employed ‘x’ more workers after 40 days.

(75*40)/0.75 = {(x+75)*5}/0.25

=> 20x + 1500 = 4000

=>x = 125 - Present ages of A and B are in the ratio is 7:5 resp. Present age of C is 20% more than the age of B five years ago. Find the present age of A, if the present average age of A, B and C is 2 years more than the present age of B.
2018161228Option E

Present age of C = (5x-5)*1.20 = 6x-6 years

7x + 5x + 6x – 6 = 3*(5x+2)

=>18x – 6 = 15x+6

=>x = 4

Present age of A = 28 years