- When a person sold an article, his profit percent is 60% of the selling price. If the cost price is increased by 75% and the selling price remains the same, then find decrement in the profit is what percent of the selling price of the article?
50%40%10%30%20%Option D

Let the selling price be 250x

Profit = 150x CP=250x − 150x = 100x

Now, new C.P. = 100x × 175 100 = 175x

New S.P. = 250x

New profit = 250x – 175x = 75x

Required % = [(150x−75x)/250x] × 100 = 30% - An article is marked 6(2/3)% above the cost price and loss incurred on selling that article is 25% of the discount given on it. Then, find the discount % given?
50(1/3)%52(1/5)%51(1/4)%53(1/3)%50(1/2)%Option D

Let the cost price be Rs 3x Then the marked price= Rs 5x

And let the discount given be Rs 4y

Loss incurred= Rs y

3x − y = 5x − 4y

3y = 2x

Marked price=Rs 15/2 y

Required discount % = 4y*2/15y × 100 = 53(1/3)% - A train travelling at 72 km/hr. classes a platform of 160 m in 18 second and another train travelling at 90 km/hr crosses the same platform in 15 second. Find the length of another train?
205 m250 m215 m220 m200 mOption C

Speed of 1st train = 72 × 5 18 = 20 m/s

Distance travelled by 1st train = 20 × 18 = 360 m

Length of train (1st) = 360 – 160 = 200 m

Speed of 2nd train = 90 × 5 18 = 25 m/s

Distance travelled = 25 × 15 = 375 m

Length of 2nd train = 375 − 160 = 215 m - If A start from P with speed 60 km/hr at 8:00 am and B starts with speed 70 km/hr. at 8 : 30 am from Q and total distance between P and Q is 680 km, find at what time they will cross each other?
1 : 00 pm2 : 10 pm3 : 15 pm1 : 30 pm2 : 30 pmOption D

Dist travelled by A in 1 2 hr = 30 km

Remaining distance to be covered = 680 – 30 = 650 km

Relative Speed = 60 + 70 = 130

Time taken = 650 130 = 5 hr

Time = 8 : 30 + 5 hr = 1 : 30 pm - If a person invested 6000 at T% S.I for 3 year and same amount at (T + 5)% CI for 2 year and difference between both interest is 60 Rs. then find T (in %)?
13%15%18%12%10%Option B

By going with the options Interest received at SI = 6000 × 3 × 15 100 = Rs.2700

T + 5 = 20%

Interest received after 2 yrs at CI = 6000 × 44/100 = 2640

Difference = 2700 – 2640 = Rs.60

T = 15% - 623898 × 99 = ? × 60,000
12001000110010301350Option D

623898 × 99 = ? × 60,000

? = (623898 × 99)/60000

= 624000 × 100/600000 == 1030 - √𝟔𝟐𝟒. 𝟗1 + (𝟒. 8)^1/𝟐 =? ÷ 𝟏𝟒.𝟗
10571214Option A

√𝟔𝟐𝟒. 𝟗1 + (𝟒. 8)^1/𝟐 =? ÷ 𝟏𝟒.𝟗

√625 + 5^2 =?÷ 15

⇒ 25 + 25 =?× 5

=> ? = 50/5 = 10 - 564.666 + 82.5091 × 44.581 – 34.111 = ?
42254210440041414000Option B

564.666 + 82.5091 × 44.581 – 34.111 = ?

= 565 + 82 × 45 – 34 = 4250 = 4210 - (47% of 1442 – 36% of 1412) ÷ 63 = ?
45367Option C

(47% of 1442 – 36% of 1412) ÷ 63 = ?

(47% × 1442 − 36% × 1412)/63

= [(1440 × 45)/100 – (35 × 1410)/100]/60

= (648 − 493.5)/60 = 3 - (341789 + 265108) ÷ (8936 – 3578) = ?
100113110125120Option B

(341789 + 265108) ÷ (8936 – 3578) = ?

= (341789 + 265108)/(8936 – 3578) = 606897/5358

= 606900/5360 = 113

**Directions(6-10):** What will come in place of question mark “?” in the following questions.