# Mixed Quantitative Aptitude Questions Set 160

1. When a person sold an article, his profit percent is 60% of the selling price. If the cost price is increased by 75% and the selling price remains the same, then find decrement in the profit is what percent of the selling price of the article?
50%
40%
10%
30%
20%
Option D
Let the selling price be 250x
Profit = 150x CP=250x − 150x = 100x
Now, new C.P. = 100x × 175 100 = 175x
New S.P. = 250x
New profit = 250x – 175x = 75x
Required % = [(150x−75x)/250x] × 100 = 30%

2. An article is marked 6(2/3)% above the cost price and loss incurred on selling that article is 25% of the discount given on it. Then, find the discount % given?
50(1/3)%
52(1/5)%
51(1/4)%
53(1/3)%
50(1/2)%
Option D
Let the cost price be Rs 3x Then the marked price= Rs 5x
And let the discount given be Rs 4y
Loss incurred= Rs y
3x − y = 5x − 4y
3y = 2x
Marked price=Rs 15/2 y
Required discount % = 4y*2/15y × 100 = 53(1/3)%

3. A train travelling at 72 km/hr. classes a platform of 160 m in 18 second and another train travelling at 90 km/hr crosses the same platform in 15 second. Find the length of another train?
205 m
250 m
215 m
220 m
200 m
Option C
Speed of 1st train = 72 × 5 18 = 20 m/s
Distance travelled by 1st train = 20 × 18 = 360 m
Length of train (1st) = 360 – 160 = 200 m
Speed of 2nd train = 90 × 5 18 = 25 m/s
Distance travelled = 25 × 15 = 375 m
Length of 2nd train = 375 − 160 = 215 m

4. If A start from P with speed 60 km/hr at 8:00 am and B starts with speed 70 km/hr. at 8 : 30 am from Q and total distance between P and Q is 680 km, find at what time they will cross each other?
1 : 00 pm
2 : 10 pm
3 : 15 pm
1 : 30 pm
2 : 30 pm
Option D
Dist travelled by A in 1 2 hr = 30 km
Remaining distance to be covered = 680 – 30 = 650 km
Relative Speed = 60 + 70 = 130
Time taken = 650 130 = 5 hr
Time = 8 : 30 + 5 hr = 1 : 30 pm

5. If a person invested 6000 at T% S.I for 3 year and same amount at (T + 5)% CI for 2 year and difference between both interest is 60 Rs. then find T (in %)?
13%
15%
18%
12%
10%
Option B
By going with the options Interest received at SI = 6000 × 3 × 15 100 = Rs.2700
T + 5 = 20%
Interest received after 2 yrs at CI = 6000 × 44/100 = 2640
Difference = 2700 – 2640 = Rs.60
T = 15%

6. Directions(6-10): What will come in place of question mark “?” in the following questions.

7. 623898 × 99 = ? × 60,000
1200
1000
1100
1030
1350
Option D
623898 × 99 = ? × 60,000
? = (623898 × 99)/60000
= 624000 × 100/600000 == 1030

8. √𝟔𝟐𝟒. 𝟗1 + (𝟒. 8)^1/𝟐 =? ÷ 𝟏𝟒.𝟗
10
5
7
12
14
Option A
√𝟔𝟐𝟒. 𝟗1 + (𝟒. 8)^1/𝟐 =? ÷ 𝟏𝟒.𝟗
√625 + 5^2 =?÷ 15
⇒ 25 + 25 =?× 5
=> ? = 50/5 = 10

9. 564.666 + 82.5091 × 44.581 – 34.111 = ?
4225
4210
4400
4141
4000
Option B
564.666 + 82.5091 × 44.581 – 34.111 = ?
= 565 + 82 × 45 – 34 = 4250 = 4210

10. (47% of 1442 – 36% of 1412) ÷ 63 = ?
4
5
3
6
7
Option C
(47% of 1442 – 36% of 1412) ÷ 63 = ?
(47% × 1442 − 36% × 1412)/63
= [(1440 × 45)/100 – (35 × 1410)/100]/60
= (648 − 493.5)/60 = 3

11. (341789 + 265108) ÷ (8936 – 3578) = ?
100
113
110
125
120
Option B
(341789 + 265108) ÷ (8936 – 3578) = ?
= (341789 + 265108)/(8936 – 3578) = 606897/5358
= 606900/5360 = 113