# Mixed Quantitative Aptitude Questions Set 163

1. A material is purchased for Rs. 600.Rs. 600. If one fourth of the material is sold at a loss of 20% and the remaining at a gain of 10%, find out the overall gain or loss percentage?
4(1/5)%
5(1/3)%
3(1/2)%
2(1/2)%
2(1/3)%
Option D
Price received by selling one fourth at 20% loss
=14×600×80100=120=14×600×80100=120
Price received by selling remaining at 10% gain
=3/4×600×110/100=495
Total selling price =120+495=615=120+495=615
Overall gain =615−600=15
Overall gain percentage
= 15×100/600 = 5/2% = 2(1/2)%

2. A and B started a partnership business investing some amount in the ratio of 3 : 5. C joined them after six months with an amount equal to that of B. In what proportion should the profit at the end of one year be distributed amount A, B and C.
6:13:8
6:11:9
6:10:5
3:10:5
6:10:11
Option C
A:B:C =(3x*12):(5x*12):(5x*6)
= 36:60:30
= 6:10:5

3. A is twice as good as workman as B and together they finish a piece of work in 18 days. In how many days will B alone finish the work.
58 Days
50 Days
46 Days
43 Days
54 Days
Option E
A:B = 2:1
Also (A+B) one day work = 1/18
=(1/18∗1/3)=1/54
54 Days

4. A train covers a distance in 50 minutes, if it runs at a speed of 48kmph on an average. Find the speed at which the train must run to reduce the time of journey to 40 minutes.
65kmph
60kmph
56kmph
40kmph
62kmph
Option B
Time = 50/60 hr = 5/6 hr
Speed = 48 mph
Distance = S*T = 48 * 5/6 = 40 km
Time = 40/60 hr = 2/3 hr
Speed = Distance/Time
New speed = 40*3/2 kmph = 60kmph

5. Sound is said to travel in air at about 1100 feet per second. A man hears the axe striking the tree, 11/5 seconds after he sees it strike the tree. How far is the man from the wood chopper?
2420 ft
2330 ft
2150 ft
2400 ft
2020 ft
Option A
Speed of sound =1100 ft/s
Time =1/15 second
Distance =1100×11/5=220×11= 2420 ft

6. A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?
45(6/17)%
40(4/11)%
45(5/11)%
41(5/13)%
45(5/10)%
Option C
Total runs scored from boundaries and sixes
=3×4+8×6=60
Total runs scored by running between the wickets
=110−60=50
Required percent
=(50/110)×100=500/11= 45(5/11)%

7. A container contains 40 litres of milk. From this container 4 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?
22.04
25.52
20.20
29.16
22.11
Option D
Amount of milk in the container
=40(1−4/40)^3 = 40(1−1/10)^3 = 40×9/10×9/10×9/10
=(4×9×9×9)/100 = 29.16

8. Raj’s age after six years will be three-seventh of his father’s age. Ten years ago the ratio of their ages was 1:51:5. What is Raj’s father’s age at present?
10 years
20 years
40 years
50 years
30 years
Option D
x+16=3/7(5x+16)
⇒7x+112=15x+48
⇒8x=64
⇒x=8
Raj’s father’s present age
=5x+10 = 5×8+10 = 50 years

9. A rectangular plot measuring 90 metres by 50 metres needs to be enclosed by wire fencing such that poles of the fence will be kept 5 metres apart. How many poles will be needed?
40
62
67
56
58
Option D
Length of the wire fencing
= 2(90+50)=280m
Number of poles required
=280/5 = 56

10. A box contains 4 red, 3 white and 2 blue balls. Three balls are drawn at random. Find out the number of ways of selecting the balls of different colours.
20
17
10
15
24
Option E
Total number of ways
= 4C1 x 3C1 x 2C1
= 4 x 3 x 2
= 24