- A material is purchased for Rs. 600.Rs. 600. If one fourth of the material is sold at a loss of 20% and the remaining at a gain of 10%, find out the overall gain or loss percentage?
4(1/5)%5(1/3)%3(1/2)%2(1/2)%2(1/3)%Option D

Price received by selling one fourth at 20% loss

=14×600×80100=120=14×600×80100=120

Price received by selling remaining at 10% gain

=3/4×600×110/100=495

Total selling price =120+495=615=120+495=615

Overall gain =615−600=15

Overall gain percentage

= 15×100/600 = 5/2% = 2(1/2)% - A and B started a partnership business investing some amount in the ratio of 3 : 5. C joined them after six months with an amount equal to that of B. In what proportion should the profit at the end of one year be distributed amount A, B and C.
6:13:86:11:96:10:53:10:56:10:11Option C

A:B:C =(3x*12):(5x*12):(5x*6)

= 36:60:30

= 6:10:5 - A is twice as good as workman as B and together they finish a piece of work in 18 days. In how many days will B alone finish the work.
58 Days50 Days46 Days43 Days54 DaysOption E

A:B = 2:1

Also (A+B) one day work = 1/18

=(1/18∗1/3)=1/54

54 Days - A train covers a distance in 50 minutes, if it runs at a speed of 48kmph on an average. Find the speed at which the train must run to reduce the time of journey to 40 minutes.
65kmph60kmph56kmph40kmph62kmphOption B

Time = 50/60 hr = 5/6 hr

Speed = 48 mph

Distance = S*T = 48 * 5/6 = 40 km

Time = 40/60 hr = 2/3 hr

Speed = Distance/Time

New speed = 40*3/2 kmph = 60kmph - Sound is said to travel in air at about 1100 feet per second. A man hears the axe striking the tree, 11/5 seconds after he sees it strike the tree. How far is the man from the wood chopper?
2420 ft2330 ft2150 ft2400 ft2020 ftOption A

Speed of sound =1100 ft/s

Time =1/15 second

Distance =1100×11/5=220×11= 2420 ft - A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?
45(6/17)%40(4/11)%45(5/11)%41(5/13)%45(5/10)%Option C

Total runs scored from boundaries and sixes

=3×4+8×6=60

Total runs scored by running between the wickets

=110−60=50

Required percent

=(50/110)×100=500/11= 45(5/11)% - A container contains 40 litres of milk. From this container 4 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?
22.0425.5220.2029.1622.11Option D

Amount of milk in the container

=40(1−4/40)^3 = 40(1−1/10)^3 = 40×9/10×9/10×9/10

=(4×9×9×9)/100 = 29.16 - Raj’s age after six years will be three-seventh of his father’s age. Ten years ago the ratio of their ages was 1:51:5. What is Raj’s father’s age at present?
10 years20 years40 years50 years30 yearsOption D

x+16=3/7(5x+16)

⇒7x+112=15x+48

⇒8x=64

⇒x=8

Raj’s father’s present age

=5x+10 = 5×8+10 = 50 years - A rectangular plot measuring 90 metres by 50 metres needs to be enclosed by wire fencing such that poles of the fence will be kept 5 metres apart. How many poles will be needed?
4062675658Option D

Length of the wire fencing

= 2(90+50)=280m

Number of poles required

=280/5 = 56 - A box contains 4 red, 3 white and 2 blue balls. Three balls are drawn at random. Find out the number of ways of selecting the balls of different colours.
2017101524Option E

Total number of ways

= 4C1 x 3C1 x 2C1

= 4 x 3 x 2

= 24