# Mixed Quantitative Aptitude Questions Set 187

1. Three numbers in the ratio of 1: 2: 3 and their L.C.M is 120. Find their H.C.F?
10
15
20
25
30
Option C
Let the number be x, 2x,3x. So H.C.F is x. L.C.M of x, 2x, 3x= 6x.
6x =120 => x= 20.

2. The ratio between two number is 6:5 if their HCF is 10. Then the numbers are.
10,20
60,50
20,60
20,50
40,50
Option B
Let the number be 6x, 5x
HCF of 6x,5x=x
ie) x=10(given)
Then the numbers are 6x,5x=60,50

3. Find the average of first 14 natural number.
100
105
200
205
300
Option B
average of first n natural number=n(n+1)/2
here n=14
average=14(14+1)/2=7×15=105

4. The sum of ages of three sister born of the intervals of 2 years each is 42 years. What is the age of the youngest sister ?
10
11
12
13
14
Option C
x+(x+2)+(x+4)=42 (given the intervals are 2 years)
3x+6=42  x =36/2=12
 Age of the youngest sister=12 years

5. Cost of a mobile is Rs .5000 and selling price is Rs. 7000.What is the profit percent?
20
30
40
50
60
Option C
Profit % = p/c.p x 100
=2000/5000 x 100
P%=40

6. Ganesh can do a task in 4days . Prem can do a task in 3 days. How long if will take if both Ganesh & Prem work together?
1 d 5 hr
2 d 5 hr
5 d 2 hr
4d 6hr
2 d 6 hr
Option A
Ganesh 1day work=1/4
Prem 1day work =1/3
(Ganesh+Prem) =1/4+1/3=7/12
So Ganesh& Prem will complete in 12/7=1 5/7=1day 5hrs together.

7. If a boat travels with a speed 25km/hr in still water and the speed of stream is 5km/hrs . What would be the time taken by boat to go 40 km upstream?
2
3
4
5
6
Option A
Upstream speed = x-y km/hr
=25-5=20 km/hr
T=distance/speed
T=40/20=2hrs

8. What is the simple interest on Rs 60000 at 5 ½% per annum for 2 years?
4300
5500
6600
4400
5500
Option C
S.I = P X R X T/100=60000 x 5 ½ x 2/ 100
S.I=Rs 6600

9. Ram deposits Rs .20,000 for 2years with 5% compound interest. What amount will be get at last?
Rs .22050
Rs .32050
Rs .52050
Rs .20050
Rs .12050
Option A
Amount= P x (1+r/100)n
=20000 X (1+5/100)2
=20000 x 105/100)2
=20000x 105×105/10000
=Rs .22050

10. A florist choose one rose at random from the basket which have rainbow colors of roses. what is the probability of choosing yellow color rose?
1/7
1/5
1/4
1/3
1/2
Option A
S=(rainbow color roses)
S=(V,I,B,G,Y,O,R)=N(S)=7
P(Yellow rose)=P(S)/N(S)=1/7 (Only one yellow rose)