- Train A leaves kolkata at 8am and is travelling at a speed of 70 km/hr, 4 hours later another train B leaves kolkata and is travelling in same direction as train A in how many time (in minutes) train B will be 25 km ahead train A, if speed of train B is 100 km/hr ?
475 minutes610 minutes340 minutes620 minutes368 minutesOption B

Distance covered by train A in 4 hours = 70 * 4 = 280 km

total distance should be covered by train B from kolkata for ahead 25 km to train A

required time = 280 + 25/100-70 = 305/30 * 60 = 610 minutes - In a box there are 3 red balls, 7 white balls and 5 orange balls. If one bottle is drawn at random from the cartoon what is the probability that it is either red balls or white balls ?
2/78/93/45/72/3Option E

probability = (3C1) + (7C1)/15C1 = (3 + 7)/15 = 2/3 - Two persons A and B alone can do a piece of work in 10 days and 12 days respectively. A and B together worked for 4 days and remaining worked by C alone. If efficiency of C is 20% less than the efficiency of B then find in how many days total work will be completed ?
5 days8 days7 days12 days6 daysOption B

LCM of 10 and 12 = 60

efficiency of A = 60/10 = 6

efficiency of B = 60/12 = 5

work completed by A and B together in 4 days = (6 + 5)* 4 = 44 work

remaining work = 60 – 44 = 16 work

efficiency of C = 5 * 80/100 = 4

time required to complete the work = 16/4 = 4 work

total time to complete the work = 4 + 4 = 8 days - a and B invested rs.2500 and rs.3100 in a business respectively. After 6 months A left the business and C joined with a capital of rs.2200. At the end of 1.5 years the profit received by A and B together is how much percent more or less than that by C ?
125 3/8%140 10/11%48 3/5%152 3/7%215 3/8%Option B

Profit sharing ratio of A , B and C = (2500 * 1.5) : (3100 * .5) : (2200 * 1) = 75 : 31 : 44

more % = (75 + 31) – 44/44 * 100 = 140 10/11% - Sudha is travelling from point A to B which is 560 km apart with a certain speed. While returning he covers half the distance with 30% less speed than the usual speed and cover the remaining distance with a speed of 140 km/hr. If time taken in both cases is equal, then find the speed of Sudha while going from point A to B ?
75 km/hr80 km/hr72 km/hr84 km/hr108 km/hrOption B

Let speed of Sudha while travelling from point A to point B = 10x km/hr

time taken by Sudha while travelling from A to B = 560/10x

time taken by Sudha while returning = 280/7x + 280/140

560/10x = 280/7x + 2

56/x – 40/x = 2

x = 8

speed of Sudha = 10 * 8 = 80 km/hr - Directions : What will come in place of questions (?) marks in the following questions below ?

(15)^2 – (18)^2 + 312 = ? + 47319120184133166Option E

225 – 324 + 312 = ? + 47

– 99 + 312 = ? + 47

? = 166 - ∛1331 + 38% of 1200 – ? = 98.20

421.50213.40368.80254.20281.20Option C

11 + 456 – ? = 98.20

? = 368.80 - 1/14 + 2/7 – 1/42 = ?
2/71/34/53/54/7Option B

(3 + 12 – 1) /42 = ?

? = 1/3 - 42.30 – (11)^2 + 520 – ? = 218.40
240.80312.90422.90222.90128.46Option D

562.30 – 121 – ? = 218.40

? = 222.90 - 3/4 of 420 + 320 – 4/5 of 215 = ? + 85
420422540325378Option E

315 + 320 – 172 = ? + 85

? = 378