- A shopkeeper X sold an article for rs.850 at a profit of 25%. Another shopkeeper Y sold the another article and earned 30% more profit than the profit earned by X. If the selling price of article Y is three-fifth of selling price of article X, then find the profit percent of article Y ?
64 2/17%76 8/17%52 3/34%52 3/8%78%Option B

SP of article X = 850

CP of article X = 850 * 100/125 = 680

profit = 170

profit of article Y = 170*130/100 = 221

SP of article Y = 850 * 3/5 = 510

CP = 510 – 221 = 289

profit percent = 221/289* 100 = 76 8/17% - Mixture A contains milk and water in the ratio of 3 : 2 respectively, while mixture B contains water and milk in the ratio of 4 : 3 respectively. If the quantity of water in mixture B is twice the quantity of water in mixture A, then find the quantity of milk in mixture A is what percent quantity of water in mixture B ?
68%60%82%75%56%Option D

Quantity of milk and water in mixture A = 3x and 2x

according to questions,

quantity of water in mixture B = 2*2x = 4x

quantity of milk in mixture B = 4x/4 *3 = 3x

required percentage = 3x/4x*100 = 75% - 340 liters of mixture of milk and water is contained in a container having milk and water mixed in the ratio of 3 : 1 respectively. 76 liters of this mixture is taken out from the container and replaced with (x + 7) liters of milk so that the ratio of water to milk is 6 : 11. What is the value of ‘x’ ?
4248383552Option D

Quantity of milk in the container = 340 * 3/4 = 255

quantity of water in the container = 340*1/4 = 85

76 liters of mixture is taken out and (x + 7) liter of water is added.

(255 – 57) / 85 – 19 + (x + 7) = 11/6

198/(73 + x) = 11/6

11x = 385

x = 35 - A can do a piece of work in 30days while B and C together can complete the work in 20 days and A and C together can complete the work in 24 days. If B is worked in two-fifth of his efficiency, then in how many days A and B together complete half of the work ?
8 days6 days8 1/3 days5 days10 daysOption E

LCM of 30 , 20 and 24 = 120

efficiency of A = 120/30 = 4

efficiency of B and C = 120/20 = 6

efficiency of A and C together = 120/24 = 5

efficiency of C = 5- 4 = 1

efficiency of B 6- 1 = 5

two-fifth of efficiency B = 5 * 2/5 = 2

time required to complete half of the work = 60/2 + 4 = 10 days - Rohan and Sivan started a business together with initial investments of rs. 1500 and rs.1800 respectively. If after 2.5 years profit share of Rohan and Sivan are rs(x + 80) and (x + 120) respectively, then find the difference between profit of Rohan and Sivan ?
180120320130340Option B

Profit sharing ratio of Rohan and Sivan = (1500 * 2.5) : (1800 * 2.5) = 5 : 6

x + 80/x + 120 = 5/6

6x + 480 = 5x + 600

x = 120 - Directions : In each of these questions given below two equations. You have to solve both the equations and give answer.

I. x^2 – 7√3 + 36 = 0

II. y^2 – 6√2 + 16 = 0X > YX < YX ≤ YX ≥ YX = Y or no relation.Option E

I. x^2 – 4√3 – 3√3 + 36 = 0

x = 4√3 , 3√3

II. y^2 – 4√2 – 2√2 + 16 = 0

y = 4√2, 2√2 - I. x^2 + √2x – 12 = 0

II. y^2 – 8√3 + 48 = 0X > YX < YX ≤ YX ≥ YX = Y or no relation.Option B

I. x^2 + 3√2 – 2√2 – 12 = 0

x = -3√2, 2√2

II. y^2 – 4√3 – 4√3 + 48 = 0

y = 4√3, 4√3 - I. x^2 – 36 = 0

II. y^2 – 15y + 36 = 0

X > YX < YX ≤ YX ≥ YX = Y or no relation.Option E

I. x^2 = 36

x = 6, -6

II. y^2 – 12y – 3y + 36 = 0

y = 12, 3 - I. y^2 = 144

II. 2x^2 – 12x + 16 = 0X > YX < YX ≤ YX ≥ YX = Y or no relation.Option E

I. y^2 = 144

y = 12, -12

II. 2x^2 – 8x – 4x + 16 = 0

2x = 8, 4

x = 4, 2 - I. x^2 – 2x – 195 = 0

II. y^2 – 24y + 128 = 0X > YX < YX ≤ YX ≥ YX = Y or no relation.Option E

I. x^2 – 15x + 13x – 195 = 0

x = 15, -13

II. y^2 – 16y – 8y + 128 = 0

y = 16, 8