# Mixed Quantitative Aptitude Questions Set 33

1. A man takes 1(7/9) times as long to row a distance upstream as to row the same distance downstream. What is the speed of the boat in still water if it takes 3 hours to travel 38.4 downstream (in km/hr)?
A) 11
B) 22
C) 15
D) 10
E) 17
Option D
Solution:
Let speed of boat in still water = x kmph
speed of current = y kmph
4/(x+y) = 3
=> x+y = 38.4/3 = 12.8kmph
Again,
38.4/(x-y) = (16/9)*3 = 16/3
=> x – y = 7.2 kmph
Therefore ,
speed of boat in still water = (12.8+7.2)/2 = 10 kmph
2. The average monthly salary of employees , consisting of officers and workers of an organization is Rs. 3000. The average salary of an officer  is Rs. 10,000 while that of a worker Rs. 2000/ month . If there are total 400 employees in the organization . Calculate the number of workers and officers separately.
A) 470,50
B) 200,70
C) 350,50
D) 240,65
E) 300,60
Option C
Solution:
Let the no. of officers be x
and no. of workers be (400 – x)
=> 3000*400  = 10000x + 2000(400 – x)
=>x = 50
Therefore ,
No. of workers = 350
No. of officers = 50
3. Rohit ate in a coffee shop  and got a membership discount of 30%  on the original bill amount  but he had to pay 10% as service tax and 8% service  charge on the discounted bill amount. If Rohit paid Rs.4,743 ,which included a tip of Rs. 200, how much money did he give as service charge?
A) 350
B) 308
C) 210
D) 478
E) 316
Option B
Solution:
Let  the bill after 30% discount be Rs. x
(x*118)/100 = 4743 – 200
=> (x*118)/100 = 4543
=> x= Rs. 3850
Therefore ,
service charge = (3850*8)/100 = Rs.308
4. There is a one type of liquid contains 25% of milk ,the other contains 30% of milk .A  milk container is filled with 6 parts of the first liquid and 4 parts of the second liquid  .Find what is the percentage of milk in the mixture ?
A) 27%
B) 20%
C) 34%
D) 37%
E) 12%
Option A
Solution:
Formula : (nx + my) /(n + m) %
Required % = (6*25 + 4*30)/ (6+4) = 27%
5. Ishita invested in 3 schemes P,Q and R the amounts in the ratio 2 : 3 : 4  resp. If the schemes offered interest at 20 p.c.p.a , 16 p.c.p.a and 15 p.c.p.a resp. Calculate respective ratio of amount after one year.
A) 12:75:63
B) 54:71:110
C) 78:45:94
D) 60:87:115
E) 44:54:73
Option D
Solution:
Required ratio = 2x*(120/100) : 3x*(116/100) : 4x*(115/100)
60 : 87 : 115
6. The number of copies circulated for a first – rank newspaper is 25,42,745 in the world. If the number of copies circulated for the second rank newspaper is less by 6,15,430 of the first – rank newspaper, how many copies of second rank newspaper are circulated in the world?
A) 20,10,100
B) 19,27,315
C) 18,50,000
D) 10,12,785
E) 11,24,578
Option B
Solution:
Required answer = 25,42,745 –  6,15,430
7. A bag contains 4 green and 6 red balls. Another bag B contains 3 green and 4 red balls. If one ball is drawn from each bag. Find the probability that both are green.
A) 7/48
B) 4/33
C) 7/45
D) 6/35
E) 2/35
Option D
Solution:
Total balls in bag A =  4 + 6 = 10
Total balls in bag B = 7
Probability of green balls in bag A = 4/10
Probability  of green balls in bag B = 3/7
Therefore ,
Total probability = (4/10)*(3/7) = 6/35
8. In a rectangular tank there are two garbage tanks ,  X and Y with lengths 12m and 15m resp. in a square field . If the total area of the square field excluding the rectangular tanks is 360 sq. m and the breadth of both the rectangular tanks is (1/3) of the side of the square  field , what is the perimeter of the square field (in m)?
A) 63
B) 87
C) 75
D) 84
E)  96
Option E
Solution:
Let length of square be x m.
Breadth of each tank = (x/3) m
Area of square field – Area of both tanks = 360
x^2 – {[(12*x)/3] +[(15*x)/3]} = 360
=> x =24
Therefore ,
Perimeter of the square field = 4*24 = 96m
9. The ratio between the rates of travelling of  P and Q is 3 : 4 and then P takes 10 min. more than the time taken by Q to reach a destination . If P had walked at double the speed , at what time he would have covered the distance ?
A) 20
B) 35
C) 10
D) 24
E) 15
Option A
Solution:
Time taken by P = (x+10) min.
Time taken by Q = x min.
Therefore ,
=> 3 / 4 =  x/ (x+10)
=> x = 30 min.
Time taken by P = 40min.
If P doubles his speed ,then time taken by P = 20min.
10. In how many different ways can the letters of the word “CANDIDATE” be arranged in such a way that the vowels always come together ?
A) 4578
B) 5100
C) 4320
D) 3245
E) 1245
Option C
Solution:
Vowels  = A ,I ,A , E
Consonants = C,N,D,D,T
Here ,D and A comes twice.
No. of arrangements = (6! * 4!)/ (2! *2!) = 4320

## 24 Thoughts to “Mixed Quantitative Aptitude Questions Set 33”

1. .-•~¹°” Ambi the akdduu ˆ”°¹~•

Q. 4th seems incomplete @Banya mam

1. Banya

now check dear 🙂

1. .-•~¹°” Ambi the akdduu ˆ”°¹~•

yess thankyou mam :))

1. Banya

:))

2. Mera bhi din ayega :)))

Mam pls explain 4th??

1. .-•~¹°” Ambi the akdduu ˆ”°¹~•

25……………30
………x……….
6………………4
or
3……………….2 so x will be 27

2. Banya

go through the direct formula ..

3. Jellyfish

3/2+6/5=27/10
27/10/10=27/100*100=27℅

4. \$~\$PrAdeEP\$K\$~\$~\$

alt method
milk in first part =25% of 6 =1.5l
milk in second part =30% of 4 =1.2l
so tot.milk =1.5+1.2=2.7l
tot.mix =10l => % =2.7/10 *100 =27%

3. Di Ghosh

6 part of 1st liquid- should be mam

1. Banya

yes .. ty 🙂
now it is updated ..

2. Di Ghosh

thanks

3. Mera bhi din ayega :)))

Ty az 🙂
Good qus

4. Jellyfish

8/10 ty banya mam

5. _/_

ty

6. _/_

A bag contains 4 green and 6 red balls. Another bag B contains 3 green and 4 red balls. If one ball is drawn from each bag. Find the probability that both are green.
A) 7/48
B) 4/33
C) 7/45
D) 6/35
E) 2/35
Option D
Solution:
Total balls in bag A = 4 + 6 = 10
Total balls in bag B = 7
Probability of green balls in bag A = 4/10
Probability of green balls in bag B = 3/7
Therefore ,
Total probability = (4/10)*(3/7) = 6/35
……………..
esme ye ku ni hau
let me know
1/2*4/10+1/2*3/7.

1. Jellyfish

Each bags 1 green out kiya na

1. _/_

bag ki probabilty o1/2 hogi na

1. Banya

dono bag se nikala ja raha h green ball ko .isiliye dono baag ko consider karenge .. 1/2 se kisi ek hi bag ka probability niklega .

2. .-•~¹°” Ambi the akdduu ˆ”°¹~•

we use …no of favourable outcomes / total possible outcomes
so in first bag there are 4 green , we need green only so it will be 4 / 10 and in second one it is 3 / 7
multiply both we ll get 12 / 70 = 6/35

3. asdf

We multiply by 1/2 when we have to choose one bag out of two bags. But here we are choosing a green ball from both bags so we will not multiply by 1/2.

7. sonali

TY AZ

8. jaga

thank u

9. kumkum ahuja

nice quiz ty az:)