Quantitative Aptitude Questions for IBPS RRB/PO/Clerk, SBI PO, NIACL, NICL, RBI Grade B/Assistant, BOI, Bank of Baroda and other competitive exams

- A man gets simple interest of 1,000 on a certain principal at the rate of 5 percent p.a. in 4 years . What compound interest will the man get on twice the principal in two years at the same rate ?

A) 1025

B) 1550

C) 2050

D) 1475

E) 1010

- Train A crosses a pole and platform in 18 seconds and 39 seconds respectively. The length of platform is 157.5 metre . What will be the length of train B if it is equal to the sum of half of the length train A and twice the length of the platform?

A) 225.4m

B) 400.5m

C) 382.5m

D) 425.7m

E) 325.5m

- Minal have borrowed some money from her friend at the rate of 5% p.a. for the first three years, 15% p.a. for the next five years and 15% p.a. for the beyond 10years . If the total interest paid by him at the end of 18 years is Rs. 90,000, how much money did she borrow?

A) Rs.45,000

B) Rs.50,000

C) Rs.40,500

D) Rs.37,500

E) Rs.22,500

- Tarun got 30% of the maximum marks in the examination and failed by 10marks. However, Vimal who took the same examination got 40% of the total marks and got 15 more than the passing marks in the examination. What were the passing marks in the examination?

A) 75

B) 65

C)72

D) 90

E) 85

- A person crosses a stationary bus in 18 seconds. The same bus crosses a pole in 4 seconds. What is the respective ratio between the speed of the bus and the speed of the man?

A) 9:2

B) 8:5

C) 7:3

D) 5:8

E) 8:7

- 16 children are to be divided into two groups A and B consisting of 10 and 6 children. The average percent marks obtained by the children of group A is 75 and the average percent marks of all the 16 children is 76. What is the average percent marks of children of group B?

A) 65(1/4)

B) 77(2/3)

C) 77(1/5)

D) 67(1/2)

E) 71(1/2)

- The difference between the simple interest received from two different sources on Rs. 1500 for 3 years in Rs. 13.50. What is the difference between their rates of interest?

A) 0.5%

B) 0.6%

C) 0.3%

D) 0.8%

E) 0.7%

- The area of a circular field is equal to the area of a rectangular field. The ratio of the length and the breadth of the rectangular field is 14:11 respectively and perimeter is 100metres . What is the diameter of the circular field?

A) 18m

B) 22m

C) 30m

D) 28m

E) 33m

- From a well – shuffled pack of 52 playing cards , one card is drawn at random. What is the probability that the card drawn will be a black king?

A) 1/26

B) 2/13

C)1/13

D) 3/26

E) 3/13

- The number of ways in which 6 men and 5 women can dine at a round table, if no two women are to sit together . Find the number of arrangements.

A) 8!*5!

B) 4!*3!

C) 6!*8!

D) 6!*5!

E) 5!*4!

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pls start timer quiz ?

plz start timer quiz……….. nd thanks ASP

ho gye ques bro?

im not getting.. hindi nahi athaa…

questions are completed

okk:))

9/10 Ty AZ

thks

mam in 10 ) ques….we subtract 1 i.e. (6-1)=5..in boys …why not from girls like this 6! for boys & (5-1)=4! for girls

in ques 3rd…….

Let the sum be Rs.x

(x*5*3)/100 + (x*5*15)/100 + (x*15*10)/100 = 90,000

=>x = 37500

2nd part (x*5*15)/100 …….=====>> x*5*10 hoga na?

yes ques me hi problem h

ques 10

no. of ways for men = 6!

and for women = 6P5 = 6!

is this method is wrong?

it shoud b 5p5 as womens r 5 so 5p5 => 5factorial..:)

but places for women is 6

typo mistk

??

means i want to say that use combination tactics

not get it

Start from man ,the sequence will be –

M,W,M,W,M,W,M,W,M,W,Mso no. of men can be arranged by 6!

& no. of women can be arranged by 5!

Required ways = 6!*5!

please post ur solution

see here..:)

no of men arranged in circular table =(6-1)! =5!

now no of women arranged in 6 places =6c5 =6

now women aranged themselves =5!

=> t =6*5!*5! =6!*5!=86400 = option d

ok thanku

🙂

this is also ryt but if u use combination instead of permutation then there is a std in combination for circular arrangement u can have easiness other wise for permutation u have to assume it as linear arrangemnt and solve in both case same ans u will get..:)

explain 6th ques last 2steps plz

by alligation

75————x

——–76—–

x-76———1

now

(x-76)/1 =5/3 => x =77(2/3) =77.667

tanq:)

..:)

10,6 group A&B resp

16*76=10*75+6*x

466/6=233/3=77*2/3

9/10 ty az

ty

Thnku 🙂

Thanks Banya mam 🙂

9/10

ty

Plz koi solve kro.2pipes can half the tank in 1.2hours.the tank was initially empty.Pipe B was kept open for half the time required by pipe A to fill the tank by itself. Then pipe A was kept open for as much time as was required by pipe B to fill 1/3 of the tank by itself.The least time in which any of the pipe can fill the bank.

4 hrs?

Answer is correct but ye first equation me 5/12 kahan se aaya ye smjh Ni aaya.

1/a + 1/b == (1/2)*(1/1.2)

1/a + 1/b == 5/12……1

.

a/2b + b/3a == 5/6

3a^2 + 2b^2 – 5ab == 0

a==b , a== 2b/3

.

For a==b we get b == 4.8 hrs

for a==2b/3 we get b == 4hrs

A can fill the tank in 4 hours and B can fill 6 hours while C can outlet in 6 hours.A man open 2pipes to fill the tank and set a alarm to open third outlet tank when tank will half be filled.but he mistakely set alarm when tank will filled 3/4. What will be the difference between two times to fill the tank

1.2 hrs?

Iska answer 54 minutes h….ye bhi solve Ni hua

let total work == 12 lit

…………………….A………..B………..C

work done/hr….3…………2………..-2

Case 1

6L filled by A & B in 6/5 == 1.2 hrs

remaining 6L in 6/(3+2-2)==2hrs……total time == 3.2hrs

.

Case 2

9 L filled by A&B in 9/5==1.8hrs

remaining 3 lit in 3/3==1hrs…..total == 2.8

Difference== 0.4hrs or 24mins

Thanks smjh as gye.

tq ,mam