# Mixed Quantitative Aptitude Questions Set 38

Quantitative Aptitude Questions for IBPS RRB/PO/Clerk, SBI PO, NIACL, NICL, RBI Grade B/Assistant, BOI, Bank of Baroda and other competitive exams

1. A man gets simple interest of 1,000 on a certain principal at the rate of 5 percent p.a. in 4 years . What compound interest will the man get on twice the principal in two years at the same rate ?
A) 1025
B) 1550
C) 2050
D) 1475
E) 1010
Option  A
Solution:
Principal(P) = (SI *100)/(Time *Rate ) = (1000*100)/(4*5)
= 5000
Now, P= 10000
Therefore ,
CI = P[(105/100)^2 – 1 ] = Rs.1025
2. Train A crosses a pole and platform in 18 seconds and 39 seconds respectively. The length of platform is 157.5 metre . What will be the length of train B if it is equal to the sum of half of the length train A and twice the length of the platform?
A) 225.4m
B) 400.5m
C) 382.5m
D) 425.7m
E) 325.5m
Option C
Solution:
Let the length of train A = x metre
Therefore,
(x/18) = (x+157.5)/39
=> x= 135 metre
Length of train B = [(135/2) + 2*157.5] m = 382.5 m
3. Minal have borrowed some money from her friend at the rate of  5% p.a. for the first three years, 15% p.a.  for the next five years and 15% p.a. for the beyond 10years . If the total interest paid  by him at the end of  18 years is Rs. 90,000, how much money did she borrow?
A) Rs.45,000
B) Rs.50,000
C) Rs.40,500
D) Rs.37,500
E) Rs.22,500
Option D
Solution:
Let the sum be Rs.x
(x*5*3)/100 + (x*5*15)/100 + (x*15*10)/100 = 90,000
=>x = 37500
4. Tarun  got 30% of the maximum marks in the examination and failed by 10marks. However, Vimal who took the same examination got 40% of the total  marks and got 15 more than the passing marks in the examination. What were the passing marks in the examination?
A) 75
B) 65
C)72
D) 90
E) 85
Option E
Solution:
Let the maximum marks be x .
Therefore,
x*30% + 10 = x*40% – 15
=> x = 250
Passing marks = 250*(30/100) + 10 = 85
5. A person crosses a stationary bus in 18 seconds. The same bus crosses a pole in 4 seconds. What is the respective ratio between the speed of the bus and the speed of the man?
A) 9:2
B) 8:5
C) 7:3
D) 5:8
E) 8:7
Option A
Solution:
Let length be x.
Then ,
(x/4):(x/18) = 9:2
6. 16 children are to be divided  into two groups A and B consisting of 10 and 6 children. The average percent marks obtained by the children of group A is 75 and the average percent marks of all the 16 children  is 76. What is the average percent marks of children of group B?
A) 65(1/4)
B) 77(2/3)
C) 77(1/5)
D) 67(1/2)
E) 71(1/2)
Option B
Solution:
A————B
75———-y
——76
(10/6)—-(6/6)
Therefore,
y = 76+(10/6) = 77(2/3)
7. The difference between the simple interest received from two different sources on Rs. 1500 for 3 years in Rs. 13.50. What is the difference between their rates of interest?
A) 0.5%
B) 0.6%
C) 0.3%
D) 0.8%
E) 0.7%
Option C
Solution:
Here, the principal and time are same but rates are different.
Hence, we get difference in simple interest due to difference in the rates.
Diff. in 3 yrs. = 13.50
Diff. in 1 yr. = (13.50/3) = Rs.4.50
Diff. between rates = (4.50/1500)*100 = 0.3%
8. The  area of a circular field is equal to the area of a rectangular field. The ratio of the length and the breadth of the rectangular field is 14:11 respectively and perimeter is 100metres . What is the diameter of the circular field?
A) 18m
B) 22m
C) 30m
D) 28m
E) 33m
Option D
Solution:
Let the length and breadth of the rectangular field be 14x and 11x metres resp.
Therefore,
2(14x + 11x) = 100
=> 50x 100
=> x = 2
Area of rectangular field = 28*22 = 616m^2
Area of circular field = 616 m^2
pi*r*r = 616
=> r = sq. root(616/pi)
=> r = 14m
Diameter = 28m
9. From a well – shuffled pack of 52 playing cards , one card is drawn at random. What is the probability that the card drawn will be a black king?
A) 1/26
B) 2/13
C)1/13
D) 3/26
E) 3/13
Option A
Solution:
Required probability = (2C1)/52C1 = 2/52 = 1/26
10. The number of ways in which 6 men and 5 women can dine at a round table, if no two women are to sit together . Find the number of arrangements.
A) 8!*5!
B) 4!*3!
C) 6!*8!
D) 6!*5!
E) 5!*4!
Option D
Solution:
No. of ways to fix the men in alternate positions = (6-1)! = 5!
In out of six positions 5 women can be seated in 6P5 = 6!
Required ways = 6!*5!

## 45 Thoughts to “Mixed Quantitative Aptitude Questions Set 38”

1. M@nish...

pls start timer quiz ?

2. karthik

plz start timer quiz……….. nd thanks ASP

1. M@nish...

ho gye ques bro?

1. karthik

im not getting.. hindi nahi athaa…

2. karthik

questions are completed

1. M@nish...

okk:))

3. !!! m@umit@ !!!

9/10 Ty AZ

4. PREDICTION -baba

thks

5. %%%

mam in 10 ) ques….we subtract 1 i.e. (6-1)=5..in boys …why not from girls like this 6! for boys & (5-1)=4! for girls

6. Diya

in ques 3rd…….
Let the sum be Rs.x

(x*5*3)/100 + (x*5*15)/100 + (x*15*10)/100 = 90,000

=>x = 37500
2nd part (x*5*15)/100 …….=====>> x*5*10 hoga na?

1. %%%

yes ques me hi problem h

7. Diya

ques 10
no. of ways for men = 6!
and for women = 6P5 = 6!
is this method is wrong?

1. \$קгค๔єєק\$

it shoud b 5p5 as womens r 5 so 5p5 => 5factorial..:)

1. Diya

but places for women is 6

1. \$קгค๔єєק\$

typo mistk

1. Diya

??

2. \$קгค๔єєק\$

means i want to say that use combination tactics

3. Diya

not get it

4. ครђ

Start from man ,the sequence will be –

M,W,M,W,M,W,M,W,M,W,M

so no. of men can be arranged by 6!
& no. of women can be arranged by 5!
Required ways = 6!*5!

5. Diya

please post ur solution

6. \$קгค๔єєק\$

see here..:)
no of men arranged in circular table =(6-1)! =5!
now no of women arranged in 6 places =6c5 =6
now women aranged themselves =5!
=> t =6*5!*5! =6!*5!=86400 = option d

7. Diya

ok thanku

8. \$קгค๔єєק\$

🙂

2. \$קгค๔єєק\$

this is also ryt but if u use combination instead of permutation then there is a std in combination for circular arrangement u can have easiness other wise for permutation u have to assume it as linear arrangemnt and solve in both case same ans u will get..:)

8. Jahnavi

explain 6th ques last 2steps plz

1. \$קгค๔єєק\$

by alligation
75————x

——–76—–
x-76———1
now
(x-76)/1 =5/3 => x =77(2/3) =77.667

1. Jahnavi

tanq:)

1. \$קгค๔єєק\$

..:)

2. Jellyfish

10,6 group A&B resp
16*76=10*75+6*x
466/6=233/3=77*2/3

9. Jellyfish

9/10 ty az

10. Sachin shukla( Banker 2018)

ty

11. Vasudha ⭐

Thnku 🙂

12. ครђ

Thanks Banya mam 🙂
9/10

13. _/_

ty

14. think tank

Plz koi solve kro.2pipes can half the tank in 1.2hours.the tank was initially empty.Pipe B was kept open for half the time required by pipe A to fill the tank by itself. Then pipe A was kept open for as much time as was required by pipe B to fill 1/3 of the tank by itself.The least time in which any of the pipe can fill the bank.

1. ADK

4 hrs?

1. think tank

Answer is correct but ye first equation me 5/12 kahan se aaya ye smjh Ni aaya.

1. ADK

1/a + 1/b == (1/2)*(1/1.2)

2. ADK

1/a + 1/b == 5/12……1
.
a/2b + b/3a == 5/6
3a^2 + 2b^2 – 5ab == 0
a==b , a== 2b/3
.
For a==b we get b == 4.8 hrs
for a==2b/3 we get b == 4hrs

15. think tank

A can fill the tank in 4 hours and B can fill 6 hours while C can outlet in 6 hours.A man open 2pipes to fill the tank and set a alarm to open third outlet tank when tank will half be filled.but he mistakely set alarm when tank will filled 3/4. What will be the difference between two times to fill the tank

1. ADK

1.2 hrs?

1. think tank

Iska answer 54 minutes h….ye bhi solve Ni hua

2. ADK

let total work == 12 lit
…………………….A………..B………..C
work done/hr….3…………2………..-2
Case 1
6L filled by A & B in 6/5 == 1.2 hrs
remaining 6L in 6/(3+2-2)==2hrs……total time == 3.2hrs
.
Case 2
9 L filled by A&B in 9/5==1.8hrs
remaining 3 lit in 3/3==1hrs…..total == 2.8
Difference== 0.4hrs or 24mins

1. think tank

Thanks smjh as gye.

16. ~CASIMIRO~ NITROUS~ OXIDE~

tq ,mam