- Find the sum of the last three positive consecutive odd numbers.
I).If the sum of the first positive and last positive odd number is 112.
II).The average of four consecutive odd number is 30.
II).The difference between the highest positive odd number and the lowest positive odd number is 4.Statement III and Statement I independently.Neither Statement I nor Statement II.Statement II only.All the three statements are required together.None of the above statements.Option C
sum of the first and last positive odd number is given but this is not enough to find the sum of last three positive consecutive odd numbers.
From II. Let the first odd number x.
Four consecutive number =27,29,31,33 The sum of the last three consecutive numbers = 27 +29+31=87
We can’t find the answer.
Therefore, statement II alone is sufficient to answer the questions
- What is the monthly income of Mr. Shaan?
I). Monthly expenditure of Mr. Shaan is Rs.17000.
II).From his monthly income, if some amount is spend on food and remaining on education and transportation. III).Mr. Shaan saves 15% from his monthly salary for future purpose.None of the above statements.Statement II only.All the three statement are together required to answer.From Statement I and Statement III together are required to answer.Either Statement I or Statement III .Option
From I and III. 85% (Expense) = 17000
100% = 17000/85*100 = 20,000
Monthly income = Rs. 20,000
From II. We cannot get any information.
- The compound interest on a sum of Rs.1500 is Rs.620. Find the rate of interest.
I).The compound interests is compounded annually.
II). The amount triples itself in 6 years at the rate of 4%.
III). The simple interest on Rs.1500 at the same rate of interest.Statement I only.Either Statement I and Statement III or Statement II .None of the above statements.Neither Statement I nor Statement III.Statement II and Statement III independently.Option C
Since, time is not given.So,all the above three statements are redundant.
- A sum of money Rs.2000 is to be distributed among Komal, Bimal and Shital. What will be the share of Bimal?
I). Komal’s share is twice Bimal’s share.
II). Shital’s share is double the share of Komal and Bimal together.
III). The share of Komal is Rs.120 more than Bimal.All the three statements are together necessary to answer.Either Statement I and Statement II or Statement I and Statement III.Statement I and Statement III both are required to answer.None of the above statements.Statement II and Statement III both are required to answer.Option B
From I). Komal : Bimal = 1:2
From II). Shital : (Komal + Bimal) = 6: (1+2) Shital : Komal : Bimal = 6: 1: 2
From III). Komal = Bimal + 120
Either From I). and From II). or From I). and From III). Statements.
- Find the total students (boys and girls) of a college participated in a blood donation camp?
I). Boys participated in the camp double of the girls.
II). Half of the girls participated in the camp.
III). The difference between the two participation groups is 20% of the no. of boys who participated in the camp, the total girls in the college is 212.Statement III only.Statement I and Statement II both together are required to answer.Statement II and Statement III are required to answer.All the three statements are together necessary to answer.Either Statement I or Statement II or Statement III is required to answer.Option D
All the three statements are necessary to find out students who are participated in blood donation camp.
- In Village B 40% are male. From that 20% of male are literate and 30% of male literates are degree holders. There are 840 male literates are non-degree holders .Find the total population in village B.
Let us consider x is total number of literates
70x/100 = 840
y be the total number of male
20y /100 = 1200
z be the total number of population
40z/ 100 = 6000
- Four years ago the ratio of father’s age to son’s age was 8:1 and ratio of present age of mother and son is 4:1. If the sum of present ages of mother and son is 4 years more than the father’s present age, find father’s present age.
36 years44 years48 years42 years30 yearsOption A
Let present age of father, mother and son be x, y and z. ( x – 4)/ (Z – 4) = 8/ 1
=> 𝑥 − 8𝑧 = −28 − − − −(1)
y /z = 4/ 1 => 𝑦 = 4𝑧 − − − −(2)
y + z = 4 + x y + z − x = 4 − − − −(3)
Solve the above three equation,
x=36 years, y=32 years, z=8 years
Father’s age=36 years
- A water tank is filled by a pipe P alone in 30 minutes and by pipe Q alone in 40 minutes. Pipe R can empty the same tank in 25 minutes. If all the three pipes are opened together, how long will they take to fill the tank ?
48( 6/ 17) minutes42( 7/ 12) minutes55( 3/ 8) minutes45( 1/ 10) minutes54( 6/ 11) minutesOption E
Part of tank filled by P in 1 minute = 1 /30
Part of tank filled by Q in 1 minute = 1/ 40
Part emptied by R in 1 minute = 1 /25
Tank filled by (P + Q + R) in 1 minute = 1/ 30 + 1 /40 – 1 /25
= [20 + 15 – 24]/ 600
= 11 /600
11 /600 part is filled in = 1 minute
Full tank is filled in = 600 /11
= 54( 6/ 11) minutes
- Lawrence invests Rs.12000 as fixed deposit in a bank at the rate of SI 8% per annum. But due to some needs he has to withdraw the entire money after 4 years, for which the bank allowed him a lower rate of interest. If he gets Rs. 2500 less than what he would have got at the end of 6 years, the rate of interest allowed by the bank is
(12000 × 8 × 6)/ 100 − (12000 × 4 × R) /100 = 2500
=>R=6.79 == 7%
- Mr. Varun invests 15% of her monthly salary, i.e., Rs. 3420 in Mutual Funds. Later he invests 18% of his monthly salary on Pension Policies also he invests another 9% of his salary on Insurance Policies. What is the total monthly amount invested by Mr. Varun?
15% == 3420
1% == 3420/15
15+18+9 = 42%
=3420/15×42 = Rs.9576