- 3,4,7.5,19,45,138
37.519445Option C

3*1 + 1 = 4

4 * 1.5 + 1.5 = 7.5

7.5 * 2 + 2 = 17

17 * 2.5 + 2.5 = 45 - -2 , +5 , -1 , 12, 29, 166, 981
166+5-229981Option A

– 2 * 1 + 7 = 5

5*2 – 11 = -1

-1 *3 + 15 = 12

12*4 – 19 = 29

29 *5 + 23 = 168

168 * 6 – 27 = 981 - 5,6,15,41,105,230
10541615230Option D

5 + 1^3 = 6

6 + 2^3 = 14

14 + 3^3 = 41

41 + 5^3 = 105 - 6,91,584,2935,11756,35277
293558491117566Option B

6*7 + 49 = 91

91*6 + 36 = 582

582*5 + 25 = 2935

2935 *4 + 16 = 11756 - 1,4,25,256,3125,46656
4312512546656Option D

1 = 1^1

4 = 2^2

27 = 3^3

256 = 4^4

so on.. - If the sum of circumference of a circle and the circumference of a semi- circle of same radius R is 240 cm. Then find the radius of another circle whose radius is 200% more than R.
52 cm63 cm50 cm33 cm44 cmOption B

2*pi*R + pi*R + 2R = 240

=> R = 21

Radius is 200% more than R = R + 200% of R = 63 cm - There are two vessels X and Y having quantities milk and water. The ratio of quantity in vessel is 3:4 and both of them having equal quantity of water . The quantity of pure milk in both the vessels X and Y having 50 L and 70 L respectively. Now these two vessels X and Y quantities put in another vessel Z . Find the ratio of milk and water in vessel Z.
7:311:86:17:25:3Option C

Quantity of pure milk and water in both the vessels.

Let x be the quantity of water. 50 + x/70+x = ¾

=> x = 10

Ratio of milk and water in vessel Z = 120:20 = 6:1 - Q is 400% more efficient than P and has 25% of more efficient than R. If all of them can complete the work in 4 days, then find the number of days required by P for completion of the whole work.
10 days30 days50 days70 days40 daysOption E

Q = P + 400% of P = 5P —–(1)

Q = R + 25% of R = 5/4R —–(2)

Equate (1) and (2), we get

(P+Q+R)*4 = Px

=> P + 5P + 4P = Px

=> x = 40 days - Butler borrows Rs 60,000 from a bank at 6% p.a. simple interest and clears the debt in five years. If the installments paid at the end of the first, second, third and fourth years to clear the debt are Rs 6,000, Rs 12,000, Rs 18,000 and Rs 24,000 respectively, what amount should be paid at the end of the fifth year to clear the debt?
1345010150108001526012003Option C

In the case of simple interest, instalment amount will always be reduced from principal and the interest will be calculated on the remaining principal.

Simple interest for 1st yr=𝑝𝑛𝑟 /100 = 60000×1×6/100 = 3600

Amount after 1st instalment=60000 – 6000 = 54000

Simple interest for 2nd yr= 𝑝𝑛𝑟/ 100 = 54000×1×6/ 100 = 3240

Amount after 2nd instalment=54000- 12000 = 42000

Simple interest for 3rd yr=𝑝𝑛𝑟 /100 = 42000×1×6/ 100 = 2520

Amount after 3rd instalment=42000- 18000 = 24000

Simple interest for 4th yr=𝑝𝑛𝑟 /100 = 24000×1×6 /100 = 1440

Amount after 4th instalment = 24000- 24000 = 0

Balance of debt for the fifth year = 3600 + 3240 + 2520 + 1440 = 10800 - There are 4 Quantitative books and 3 Reasoning books on the bookshelf. Quantitative books should be placed on the left side of the bookshelf and Reasoning books on the right side of the bookshelf. How many ways are there to arrange the books?
144 ways115 ways123 ways105 ways150 waysOption A

Arranging Quantitative books: P(4) = 4! = 24

Arranging Reasoning books: P(3) = 3! = 6

No. of ways = P(4).P(3) = 24*6 = 144 ways.