# Mixed Quantitative Aptitude Questions Set 82

1. 3,4,7.5,19,45,138
3
7.5
19
4
45
Option C
3*1 + 1 = 4
4 * 1.5 + 1.5 = 7.5
7.5 * 2 + 2 = 17
17 * 2.5 + 2.5 = 45

2. -2 , +5 , -1 , 12, 29, 166, 981
166
+5
-2
29
981
Option A
– 2 * 1 + 7 = 5
5*2 – 11 = -1
-1 *3 + 15 = 12
12*4 – 19 = 29
29 *5 + 23 = 168
168 * 6 – 27 = 981

3. 5,6,15,41,105,230
105
41
6
15
230
Option D
5 + 1^3 = 6
6 + 2^3 = 14
14 + 3^3 = 41
41 + 5^3 = 105

4. 6,91,584,2935,11756,35277
2935
584
91
11756
6
Option B
6*7 + 49 = 91
91*6 + 36 = 582
582*5 + 25 = 2935
2935 *4 + 16 = 11756

5. 1,4,25,256,3125,46656
4
3125
1
25
46656
Option D
1 = 1^1
4 = 2^2
27 = 3^3
256 = 4^4
so on..

6. If the sum of circumference of a circle and the circumference of a semi- circle of same radius R is 240 cm. Then find the radius of another circle whose radius is 200% more than R.
52 cm
63 cm
50 cm
33 cm
44 cm
Option B
2*pi*R + pi*R + 2R = 240
=> R = 21
Radius is 200% more than R = R + 200% of R = 63 cm

7. There are two vessels X and Y having quantities milk and water. The ratio of quantity in vessel is 3:4 and both of them having equal quantity of water . The quantity of pure milk in both the vessels X and Y having 50 L and 70 L respectively. Now these two vessels X and Y quantities put in another vessel Z . Find the ratio of milk and water in vessel Z.
7:3
11:8
6:1
7:2
5:3
Option C
Quantity of pure milk and water in both the vessels.
Let x be the quantity of water. 50 + x/70+x = ¾
=> x = 10
Ratio of milk and water in vessel Z = 120:20 = 6:1

8. Q is 400% more efficient than P and has 25% of more efficient than R. If all of them can complete the work in 4 days, then find the number of days required by P for completion of the whole work.
10 days
30 days
50 days
70 days
40 days
Option E
Q = P + 400% of P = 5P —–(1)
Q = R + 25% of R = 5/4R —–(2)
Equate (1) and (2), we get
(P+Q+R)*4 = Px
=> P + 5P + 4P = Px
=> x = 40 days

9. Butler borrows Rs 60,000 from a bank at 6% p.a. simple interest and clears the debt in five years. If the installments paid at the end of the first, second, third and fourth years to clear the debt are Rs 6,000, Rs 12,000, Rs 18,000 and Rs 24,000 respectively, what amount should be paid at the end of the fifth year to clear the debt?
13450
10150
10800
15260
12003
Option C
In the case of simple interest, instalment amount will always be reduced from principal and the interest will be calculated on the remaining principal.
Simple interest for 1st yr=𝑝𝑛𝑟 /100 = 60000×1×6/100 = 3600
Amount after 1st instalment=60000 – 6000 = 54000
Simple interest for 2nd yr= 𝑝𝑛𝑟/ 100 = 54000×1×6/ 100 = 3240
Amount after 2nd instalment=54000- 12000 = 42000
Simple interest for 3rd yr=𝑝𝑛𝑟 /100 = 42000×1×6/ 100 = 2520
Amount after 3rd instalment=42000- 18000 = 24000
Simple interest for 4th yr=𝑝𝑛𝑟 /100 = 24000×1×6 /100 = 1440
Amount after 4th instalment = 24000- 24000 = 0
Balance of debt for the fifth year = 3600 + 3240 + 2520 + 1440 = 10800

10. There are 4 Quantitative books and 3 Reasoning books on the bookshelf. Quantitative books should be placed on the left side of the bookshelf and Reasoning books on the right side of the bookshelf. How many ways are there to arrange the books?
144 ways
115 ways
123 ways
105 ways
150 ways
Option A
Arranging Quantitative books: P(4) = 4! = 24
Arranging Reasoning books: P(3) = 3! = 6
No. of ways = P(4).P(3) = 24*6 = 144 ways.