Mixed Quantitative Aptitude Questions Set 84

Directions(1-5): Find the missing term of the series.

  1. 3,20,88,273,?,559
    551
    500
    554
    505
    517
    Option C
    (3+1)*5 = 20
    (20+2)*4 = 88
    (88+3)*3 = 273
    (273+4)*2 = 554
    (554+5)*1 = 559

     

  2. 27,54,86,?,187,272
    128
    153
    122
    110
    111
    Option A
    —27—–32—–42—–59—–85—–
    —5—–10—–17—–26–
    5 == 4^2+1
    10 == 3^2+1
    17== 4^2+1
    26== 5^2+1
    ? == 128

     

  3. 21,?,77,150,295,584
    42
    36
    50
    38
    40
    Option E
    21*2-2 = 40
    40*3-3 = 77
    77*4 – 4 = 150
    150*5 – 5 = 295
    295*6 – 6 = 584

     

  4. 1,2,6,?,49,174
    20
    27
    30
    33
    35
    Option D
    1+1^3 = 2
    2 + 2^2 = 6
    6 + 3^3 = 33
    33+4^2 = 49
    49 + 5^3 = 174

     

  5. 105,121,146,182,?,295
    231
    222
    252
    202
    220
    Option A
    —4^2—–5^2—-6^2—–7^2—-

     

  6. If machine X can produce 1,000 bolts in 8 hours and machine Y can produce 1,000 bolts in 24 hours. In how many hours can machines X and Y, working together at these constant rates, produce 1,000 bolts?
    5 hours
    3 hours
    4 hours
    6 hours
    8 hours
    Option D
    1/8 + 1/24 = 1/h => 4/24 = 1/6.
    Working together, machines X and Y can produce 1,000 bolts in 6 hours.

     

  7. A, B and C can do a piece of work in 72, 48 and 36 days respectively. For first p/2 days, A & B work together and for next ((p+6))/3days all three worked together. Remaining 125/3% of work is completed by D in 10 days. If C & D worked together for p day then, what portion of work will be remained?
    1/3
    1/5
    1/8
    1/6
    1/4
    Option D
    Total work is given by L.C.M of 72, 48, 36
    Total work = 144 units
    Efficieny of A = 144/72 = 2 units/day
    Efficieny of B = 144/48 = 3 units/day
    Efficieny of C = 144/36 = 4 units/day
    Now,
    2 x p/2 + 3 x p/2 + 2 x (p+6)/3 + 3 x (p+6)/3 + 4 x (p+6)/3 = 144 x (100 – 125/3) x 1/100
    3p + 4.5p + 2p + 3p + 4p = 84 x 3 – 54
    p = 198/16.5
    p = 12 days.
    Now, efficency of D = (144 x 125/3 x 1/100)/10 = 6 unit/day
    (C+D) in p days = (4 + 6) x 12 = 120 unit
    Remaining part of work = (144-120)/144 = 1/6

     

  8. A, B, C started a business with their investments in the ratio 1:3 :5. After 4 months, A invested the same amount as before and B as well as C withdrew half of their investments. Find the ratio of their profits at the end of the year .
    3 : 6 : 10
    2 : 6 : 9
    5 : 6 : 10
    7 : 6 : 8
    3 : 5 : 11
    Option C
    Let their initial investments be x, 3x and 5x respectively.
    Then, A:B:C = (x*4+2x*8) : (3x*4+(3x/2)*8) : (5x*4+(5x/2)*8)
    = 20x : 24x : 40x = 5 : 6 : 10

     

  9. The difference between compound interest and simple interest on a sum for two years at 8% per annum, where the interest is compounded annually is Rs.16. if the interest were compounded half yearly , what is the difference between in two interests .
    Rs.22.52
    Rs.24.64
    Rs.18.35
    Rs.17.15
    Rs.20.25
    Option B
    For 1st year S.I = C.I.
    Thus, Rs.16 is the S.I. on S.I. for 1 year, which at 8% is Rs.200
    i.e S.I on the principal for 1 year is Rs.200
    Principle = Rs.(100*200)/(8*1) = Rs.2500
    Amount for 2 years, compounded half-yearly Rs.[2500*(1+4/100)^4] = Rs.2924.4
    C.I = Rs.424.64
    Also, S.I = Rs.(2500*8*2/100) = Rs.400
    S.I. = Rs.2500*8*2/100 = Rs.400
    Required Difference = C.I – S.I = Rs. (424.64 – 400) = Rs.24.64

     

  10. A letter is takenout at random from ‘ASSISTANT’ and another is taken out from ‘STATISTICS’. Find the probability that they are the same letter.
    17/88
    19/90
    11/86
    15/87
    19/100
    Option B
    ASSISTANT == AAINSSSTT
    STATISTICS == ACIISSSTTT
    Here, N and C are not common and same letters can be A, I, S, T.
    Therefore Probability of choosing A = 2C1/9C1×1C1/10C1 = 1/45
    Probability of choosing I = 1/9C1×2C1/10C1 = 1/45
    Probability of choosing S = 3C1/9C1×3C1/10C1 = 1/10
    Probability of choosing T = 2C1/9C1×3C1/10C1 = 1/15
    Hence, Required probability = 1/45+1/45+1/10+1/15 = 19/90

     


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