**Directions(1-5)**: In each of these questions a number series is given. Below the series one

number is given followed by (a), (b), (c), (d) and (e) You have to complete this series following the

same logic as in the original series and answer the question that follows.

- 5, 9, 25, 91, 414, 2282.5

3, (a), (b), (c), (d), (e)

What will come in place of (c) ?55.4243.2554.1260.1564.75Option E

(a) 3 × 1.5 + 1.5 = 4.5 + 1.5 = 6

(b) 6 × 2.5 + 2.5 = 15 + 2.5 = 17.5

(c) 17.5 × 3.5 + 3.5 = 61.25 + 3.5 = 64.75 - 7, 6, 10, 27, 104, 515

9, (a), (b), (c), (d), (e)

What will come in place of (d) ?152131111117105Option A

(a) 9 × 1 – 1 = 8

(b) 8 × 2 – 2 = 14

(c) 14 × 3 – 3 = 39

(d) 39 × 4 – 4 = 152 - 6, 16, 57, 244, 1245, 7506

4, (a), (b), (c), (d), (e)

What will come in place of (d) ?11511005145312311147Option B

(a) 4 × 2 + 22 = 8 + 4 = 12

(b) 12 × 3 + 32 = 36 + 9 = 45

(c) 45 × 4 + 42 = 180 + 16 = 196

(d) 196 × 5 + 52 = 980 + 25 = 1005 - 15, 9, 8, 12, 36, 170

19, (a), (b), (c), (d), (e)

What will come in place of (b) ?1617131021Option A

(a) 19 × 1 – 1 × 6 = 19 – 6 = 13

(b) 13 × 2 – 2 × 5 = 26 – 10 = 16 - 8, 9, 20, 63, 256, 1285

5, (a), (b), (c),(d), (e)

What will come in place of (e) ?845919925909898Option C

(a) 5 × 1 + 1 = 6

(b) 6 × 2 + 2 = 14

(c) 14 × 3 + 3 = 45

(d) 45 × 4 + 4 = 184

(e) 184 × 5 + 5 = 925 - A, B, C are partners. A receives 2/7 of the profit and B & C share the remaining profit equally. A’s income is increased by Rs. 240 when the profit rises from 10% to 15%. Find the capital invested by A, B and C respectively?
Rs. 2100, Rs. 6000, Rs. 8000Rs. 3800, Rs. 4000, Rs. 6000Rs. 3100, Rs. 6000, Rs. 5000Rs. 4800, Rs. 6000, Rs. 6000Rs. 1500, Rs. 9000, Rs. 6000Option D

A’s share = 2/7

B’s share = 5/14 = c′𝑠 share A’s share in total profit

when profit is 10% = 2/7*10 = 20/7%

A’s share in total profit when profit is 15% = 30/7%

Difference = 30/7% – 20/7% = 240

profit = 24*7*100 = 16,800

Capital investment by A = 16,800 *2/7 = 4,800

Capital investment by B = (16,800 – 4,800)/2 = 6,000

Capital invested by A, B & C = Rs. 4800, Rs. 6000, Rs. 6000 - Profit on selling 10 candles equals selling price of 3 bulbs. While loss on selling 10 bulbs equals selling price of 4 candles. Also profit percent-age equals to the loss percentage and cost of a candle is half of the cost of a bulb. What is the ratio of selling price of candle to the sellings price of a bulb?
3:25:34:15:23:1Option A

Let CP of one candle = 𝑥

C.P. of one bulb = 2𝑥

Let SP of one candle = c & SP of one Bulb = b

According to question

3b/10𝑥 × 100 = 4c/(10 × 2𝑥)

=> c/b = 3/2 - Three men A, B and C working together 8 hours per day can print 960 pages in 20 days. In a day B prints as many pages more than A as C prints as many pages more than B. The number of pages printed by A in 4 hours equal to the number of pages printed by C in 1 hours. How many pages C prints in each hour?
42536Option B

(A + B + C)per hour = 960/20×8 = 6 … (i)

Let C prints 4𝑥 pages per hour.

All print 𝑥 pages per hour.

According to question,

C – B = B – A

=> 2B = A + C

=> B = 5𝑥/2

From (i) 𝑥 + 5𝑥/2 + 4𝑥 = 6

=> 𝑥 = 4/5

No. of pages print by B per hour = 5/2 × 4/5 = 2 - A square floor of the dimensions 72 cm × 72 cm has to be laid with rectangular tiles whose length and breadth are in the ratio 3 : 2. What is the difference between the maximum number of tiles and minimum numbers of tiles, given that the length and the breath are integers ?
858890845800987Option A

Let length and breadth of tiles are 3𝑥 and 2𝑥.

No. of tiles = 72×72/6𝑥^2 = 864/𝑥^2

Maximum no. of tiles is when 𝑥 = 1

And no. of tiles = 864

Minimum no. of tiles is when 𝑥^2 = 144

=> 𝑥 = 12 then no. of tiles = 864/144 = 6

Required difference = 864 − 6 = 858 - A box contains 6 bottles of variety1 drink, 3 bottles of variety 2 drink and 4 bottles of variety 3 drink. Three bottles of them are drawn at random, what is the probability that the three are not of the same variety?
837/872871/892842/877800/793833/858Option E

Total number of drink bottles = 6 + 3 + 4 = 13.

Let S be the sample space.

Then, n(S) = number of ways of taking 3 drink bottles out of 13.

Therefore, n(S) = 13C3

= (13 x 12 x 11)/(1 x 2 x 3)

= 66 x 13 = 858.

Let E be the event of taking 3 bottles of the same variety.

Then, E = event of taking (3 bottles out of 6) or (3 bottles out of 3) or (3 bottles out of 4)

n(E) = 6C3 + 3C3 + 4C3

= 6 x 5 x 4 / 1 x 2 x 3 + 1 + 4 x 3 x 2 / 1 x 2 x 3

= 20 + 1 + 4 = 25.

The probability of taking 3 bottles of the same variety = n(E)/n(S) = 25/858.

Then, the probability of taking 3 bottles are not of the same variety

= 1 – 25/858 = 833/858.