**Directions(1-5):** Find the missing number of the following series.

- 5,12,24,36,52,?
7460558168Option E

+3

+7

+13

+19

+29

+37 - 3,8,27,124,?
725715656700818Option A

+2!

+3!

+4!

+5!

+6! - 16,15,24,-1,48,?
-18-24-33-15-11Option C

-1^2

+3^2

-5^2

+7^2

-9^2 - 356,352,368,332,396,?
Option

-2^2 +4^2 -6^2 +8^2 -10^2 - 62,31,?,62,248,1984
4035283120Option D

62*0.5 =31

31*1=31

31*2= 62

62*4=248

248*8 = 1984 - Ram invested a sum of money “P” in a scheme X and received Rs. 250 as interest after a year. He then added Rs. 750 to it, and invested the total amount in the same scheme X for one more year and received Rs. 6300 as total amount. Find the interest obtained if amount P is invested in the scheme Y offering 12% interest rate compounded annually for 2 years.
Rs. 1272Rs. 1700Rs. 1550Rs. 1000Rs. 1525Option A

Let r be the rate of interest.

P*r%*t = 250 —-(1)

{(P+250)+750}*r%*1 = 6300 *{(P+250)+750} —-(2)

P = 5000 or 50

Take P = 5000

Required Interest

= 5000{(1+12/100)^2-1}

= Rs. 1272 - A started a business with an investment of Rs. 5500. After 6 months, B joined the business with an investment of Rs.8000. After one year of commencement of business, A received Rs. 71000 as profit. 40% of profit was given to A as incentive for handling the business single handedly and the rest was divided between A and B on the basis of their equivalent investment. Find the total profit of the business.
Rs. 72000Rs. 88000Rs. 90000Rs. 100000Rs. 95000Option E

Let the total profit be x.

Profit sharing between A and B = [5500*11]/[8000*6] = 11/8

Now, 40% of x + 11/[11+8]*(100-40)% of x = 7100

=> x = Rs. 95000 - A vessel contains mixture of milk and water mixed in the ratio 12:5 resp. 85 litres of mixture is taken out of the vessel and replaced with “x” litres of milk such that the ratio of the milk to water in the vessel becomes 19:7.Find the value of “x”, if the difference between the initial quantities of milk and water in the vessel is 84 litres.
71181012Option B

Let the initial quatities 12y and 5y of milk and water resp.

12y-5y = 84 y = 12

Initial quantities of milk and water are 144 l and 60 l resp.

Now , [144 – 60 + x]/[60-25] = 19/7

=> x = 11 - A shopkeeper bought a packet of soap (4 soaps in a packet) with the scheme of “Buy 3 get 1 free” for Rs. 180. If he sells the soap without offer and sells three soaps at the cost price of a packet of soap,find his profit percentage.
30.13%26.34%33.33%25.52%27.27%Option C

Cost price of a soap = 180/4 = 45

Selling price of a soap = 180/3 = 60

Profit% = (60-45)/45*100 = 33.33% - A train is running at a speed of 56 kmhr. After continuous running for 2 hours 40 minutes, the train stops at a station for 15 minutes. If the train starts from its source point at 8:45 am and reaches the destination point at 1:00 pm with only one stoppage, then find the total distance covered by the train.
250 km177 km185km224 km200 kmOption D

Total time taken to reach the destination

= 4 hour 15 minutes

Total running time of the train = 4 hours

Total distance covered by the train = 4*56 = 224 km