Mixed Quantitative Aptitude Questions Set 98

Directions(1-5): Find the relationship between x and y and choose a correct option.

  1. I.9x^2 – 94.5x + 243 = 0
    II.4.5y^2 – 13.5y – 486 = 0

    y>=x
    y>x
    x>y
    x>=y
    No relationship established.
    Option E
    I.9x^2 – 94.5x + 243 = 0
    =>9x^2 – (54+40.5)x + 243 = 0
    => x = 6,4.5
    II.4.5y^2 – 13.5y – 486 = 0
    =>4.5y^2 – 54y + 40.5y – 486 =0
    =>y = 12,-9
    No relation.

     

  2. I. 55x^2 – 495x + 1100 = 0
    II.5y^2 + 10y – 120 = 0

    y>x
    y>=x
    x>=y
    x>y
    No relationship established.
    Option C
    55x^2 – (220+275)x + 1100 = 0
    => x = 4,5
    5y^2 + 30y – 20y – 120 = 0
    => y = -6,4
    x>=y

     

  3. I.2x^2 – x – 241 = 0
    II. 2y^2 + 43y + 241 = 0

    No relationship established.
    x>y
    y>x
    x>=y
    y>=x
    Option D
    2x^2 – 22x + 21x – 241 = 0
    => x = 11, -10.5
    2y^2 + 21y + 22y + 241 = 0
    => y = -10.5, -11
    x>=y

     

  4. I.x^2 – 15x + 56 = 0
    II.y^2 – 23y + 132 = 0

    x>y
    x>=y
    No relationship established.
    y>=x
    y>x
    Option E
    =>x^2 – 8x – 7x + 56 =0 => x(x-8)- 7(x-8) = 0
    =>x = 7,8
    y^2 – 12y – 11y +132 = 0
    =>y(y-12) – 11(y-12) = 0
    =>y = 11,12
    y>x

     

  5. I.X^2 – 22x + 120 = 0
    II.y^2 – 26y + 168 = 0

    No relationship established.
    y>=x
    y>x
    x>=y
    x>y
    Option B
    x^2 – 10x – 12x +20 = 0
    => x(x-10) – 12(x-10) = 0
    => x = 10,12
    y^2 – 14y – 12y + 168 = 0
    => y(y-14)- 12(y-14) =0
    => y = 12,14
    y>=x

     


  6. Directions(6-10):
    Study the following charts and answer the following questions.

  7. The expenditure for the 7 years together forms what per cent of the revenues during the same period(approx)?
    55.5%
    66.3%
    75.5%
    60.8%
    80.8%
    Option C
    Required answer = 877/1165 =75.5%

     

  8. Which year showed the greatest percentage increase in profit as compared to the previous year?
    2003
    2005
    2004
    2002
    2001
    Option A
    To find the answer we have to find the profit in each year.
    In 2001 = 5/20*100=25%
    In 2002 = 5/25*100=20%
    In 2003 = 10/30*100=33.33%
    In 2004 = 10/40*100=25%
    In 2005 = 10/50*100=20%
    In 2006 = 10/60*100 = 16.66% From the above table, In 2003 the profit is maximum.

     

  9. In which year was the growth in expenditure maximum as compared to the previous year?
    2001
    2000
    2003
    2005
    2004
    Option C
    To find the answer we have to find the profit in each year.
    In 2001=8/102*100=7.8%
    In 2002=5/110*100=4.5%
    In 2003=10/115*100=8.7%
    In 2004=10/125*100=8%
    In 2005=5/135*100=3.7%
    In 2006=10/140*100=7.14%
    From the above table, In 2003 the expenditure is maximum.

     

  10. If the profit in 2007 shows the annual rate of growth as it had shown in 2006 Over the previous year, then what approximately will be the profit in 2007?
    75
    82
    70
    91
    66
    Option B
    Profit in 2005 = 60.
    Profit in 2006 = 70.
    Growth percentage in profit in 2006 over 2005 = (10/60) x 100 = 16.66%
    Profit in 2007 will be (16.66% of 70) + 70 = Rs. 82 lakh

     

  11. The average revenue collected in the given 7 years is approximately.
    178
    156
    112
    194
    167
    Option E
    Average = (120 +130 +145+ 165 +185 +200 +220)/7
    = 166.42 = Rs. 167 lakh

     


Related posts

Leave a Comment