# Quantitative Aptitude: Inequalities Set 5 (New Pattern)

New Pattern Inequalities Questions IBPS PO, SBI PO Mains 2017, NIACL, NICL, LIC, Dena Bank PO PGDBF, BOI, Bank of Baroda and other competitive exams. New Pattern Inequality Questions Quant SBI PO

Directions: Each question below contains a statement followed by Quantity I and Quantity II. Find both to find the relationship among them. Mark your answer accordingly.

1. If the quantity of milk in mixture is 10 litre then find the quantity of water if
Quantity I: After selling it at CP, milkman saves 25%
Quantity II: If the ratio of Milk and water is 5:1
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥ Quantity I
E) Quantity I = Quantity II or Relation cannot be established
Option A
Explanation
:
Quantity I.
Milk : Water
100    :   25
10=4  : 1=2.5
In Quantity 2:
5=10 ; 1=2
Quantity 1> Quantity 2

2. Find the original consumption if
Quantity I: After increasing price by 20% a family now gets 5 kg less on that price.
Quantity II: After increasing price by 25%, a family increases its expenditure by 10% and gets 6 kg less than original consumption
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥  Quantity I
E) Quantity I = Quantity II or Relation cannot be established
Option C
Explanation
:
Quantity I: 20% Increase= 1/5
1/(1+5) * T=5
T=30 Kg
Quantity II:
100
110                        125
125-110=15
15/125 *T=6
T=50 Kg
II > I
3. Find the present age of A
Quantity I: Three years before, the ratio of ages of A and B was 5:6. Three years hence this ratio will become 6:7
Quantity II: Eleven years before the ratio of ages of A and B was 1:3 and eleven years hence the ratio will become 1:2
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥ Quantity I
E) Quantity I = Quantity II or Relation cannot be established
Option E
Explanation
:
Quantity I:                   A                B
3 years before             5                6
3 years after                6                7
Difference in both case 6-5=1 and 7-6=1
1=6
6=30
Present age =30+3=33
Quantity II:                   A                B
11 years before             1                3
11 years after                1                2
Difference A=1-1=0 ; B= -1
To make the difference same; multiply equation 2 by 2; we get
Quantity II:                   A                B
11 years before             1                3
11 years after                2                4
Difference A=2-1=1; B=4-3=1
1=2
11=22
Present age= 22+11=33
4. Find the sum
Quantity I: If the Compound Interest for 2 years at 20% rate of interest is Rs 1,320.
Quantity II: If the amount on a sum for 2 years in which rate of interest for 3 years makes a sum of 125 to amount 216 is Rs 2880.
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥ Quantity I
E) Quantity I = Quantity II or Relation cannot be established
Option A
Explanation
: CI for 2 years on 20%=1/5
5             6
5             6
5*5=25   6*6=36
CI=36-25=11 =1320
Sum=25=3000
Quantity II: Find Rate
Cube root(125): Cube root (216)
5:6
rate= (6-5)/5*100=20% =1/5
5             6
5             6
5*5=25   6*6=36
36=2880; hence 25=2000
I > II

5. Find the distance if
Quantity I: A man covers a distance in 15 hours. He covers first half at 12 kmph and second half at 15 kmph.
Quantity II: Two buses moves towards each other at a speed of 30 kmph and 40 kmph respectively. When they meet it is found that faster bus covers 30 km more than slower one.
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥ Quantity I
E) Quantity I = Quantity II or Relation cannot be established
Option C
Explanation
:
Average Speed=2*12*15/(12+15)
D=S*T = 2*12*15/27 * 15 = 200 KM
Quantity II: Speed difference for 1 hour =40-30=10 Kmph; means in 1 hour faster bus will cover 10 km more than slower one; hence to cover 30 km more it will take 3 hours.
Distance= Relative Speed * Time
D= 3* (30+40)
=210 KM
II > I
6. Quantity I: Selling price, if cost price is Rs 24,000 and profit is 20%
Quantity II: Selling price, if cost price is Rs 24,000 and shopkeeper gained 16 2/3% after giving discount of 25%
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥  Quantity I
E) Quantity I = Quantity II or Relation cannot be established
Option A
Explanation
: SP = 120/100 * 24000 = 28800
Discount = 25% = 1/4 ( MP = 4, SP = 4-1 =3)
Gain = 16 2/3% = 1/6 (CP = 6, SP = 6+1 = 7)
Make SP same
CP…………SP…………..MP
18………….21………….28
18 == 24000
So 21 == 28000
7. Quantity I: No. of days in which A will work alone, given A and B can complete work in 8 days, B and C can complete work in 12 days, C and A can complete work in 8 days.
Quantity II: No. of days in which A will work alone, given A and B can complete work in 18 days, they started work together and after working for 6 days A left and B completed remaining work in 24 days.
A) Quantity I > Quantity II
B) Quantity I ≥  Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥  Quantity I
E) Quantity I = Quantity II or Relation cannot be established
Option C
Explanation
: LCM = 24
So
A + B = 24/8 = 3
B + C = 24/12 = 2
C + A = 24/8 = 3
2 ( A+B+C) = 3+2+3 = 8
A+B+C = 4
(A+B+C) – (B+C) = 4 – 2 = 2
So A = 24/2 = 12 days
A = 36 days
8. Quantity I: Volume, if diameter of sphere is 14 cm
Quantity II: Volume, if side of cube is 8 cm
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥ Quantity I
E) Quantity I = Quantity II or Relation cannot be established
Option A
Explanation
:
Quantity I. Volume of sphere = (4/3)* Pie* R3
R=7 ; Volume= 1437.33
Quantity II: V=a^3 = 8^3 = 512
I > II
9. Quantity I: x where: 3x2 + 2x – 8=0
Quantity II: y: where: 3y2 + 5y -12 =0
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥  Quantity I
E) Quantity I = Quantity II or Relation cannot be established
Option E
Explanation
: x= -2 and 4/3 ; y= -3 and 4/3 ; So no relation
10. Quantity I: x where: 4x2 – 16x + 15 = 0
Quantity II: y where: 2y2 + y -6 = 0
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥ Quantity I
E) Quantity I = Quantity II or Relation cannot be established
Option B
Explanation
: x = 3/2 and 5/2
y= -2 and 3/2

## 8 Thoughts to “Quantitative Aptitude: Inequalities Set 5 (New Pattern)”

1. K.K

Sir/mam of possible please post as many banking awareness ques as possible..much needed for sbi po mains
Last 3-4 days h..please posts more of ga section

1. Suraj

yes we are trying to cover as much as possible.. started giving important and expected banking abbreviation from yesterday.. and every day we post 20 ga questions at night..

1. K.K

I know that..nd they are gud ques..thats y i was saying if u could post more of that..it would be helpful

2. Oliver Queen

que-4 mein sum 3000 kaise aa rhi?

1. Shubhra

11 =1320
so 1 = 120
so 25 = 3000

3. AVI™ (Sinchen loveR)

ThnXXXX

4. jaga

If the amount on a sum for 2 years in which rate of interest for 3 years makes a sum of 125 to amount 216 is Rs 2880???
ye kese hoga?

5. jaga

q 1 and q 2 samjh mai nahi arah