Quant Test for IBPS Clerk 2018 Main Exam Set – 9

Directions(1-5): Find the odd number of the following series.

1. 26,32,45,64,94,136,192
   26
   45
   192
   64
   32
   Option B
   +(3*2), +(4*3), +(5*4),+(6*5), +(7*6), +(8*7)
   44 should be in place of 45.

    

2. 214,106,104,153,304,750
   214
   104
   153
   750
   304
   Option E
   *0.5-1, *1-2, *1.5-3, *2-4, *2.5-5
   302 should be in place of 304.

    

3. 35,48,76,111,161,224
   111
   35
   161
   48
   224
   Option D
   +(4^2-1), +(5^2+1), +(6^2-1), +(7^2+1), +(8^2-1)
   50 should be in place of 48.

    

4. 32,57,282,910,2132,4157
   2132
   282
   910
   57
   32
   Option C
   +5^2, +15^2, +25^2, +35^2, +45^2
   907 should be in place of 910.

    

5. 500,496,487,469,446,410
   500
   487
   410
   469
   496
   Option D
   -2^2,-3^2,-4^2,-5^2,-6^2
   471 should be in place of 469.

    

6. The cost price of an article A is 30% more than the selling price of article B and selling price of article A is 80% more than the cost price of article B. If selling price of article A is 50% more than the selling price of article B then the cost price of article A is what percentage more/less than cost price of article B?
   63%
   60%
   52%
   40%
   56%
   Option E
   Let the CP of article B be Rs.x
   SP of article A be Rs. 9x/5
   Let SP of article B be Rs.y
   CP of article A be Rs. 13y/10
   Therefore, 9x/5 = 150% of y
   => y = 6x/5
   CP of article A = 39x/25
   Ratio of CP of article B to article A = x : 39x/25 = 25:39
   Required% = 14/25*100 = 56%

    

7. Raju deposited an amount of Rs. 12500 at 10% per annum compound interest while amount of Rs. 16900 at 7% per annum simple interest at the same time for 2 years. What will be the difference in the total interest earned in the first year and the total interest earned in the second year ?
   Rs. 130
   Rs. 120
   Rs. 115
   Rs. 125
   Rs. 100
   Option D
   Total interest earned in the first year
   = (12500*100*1)/100 + (16900*7*1)/100
   = Rs. 2433
   Total interest earned in the second year = [12500*{(1.1)^2 – 1} + (16900*7*2)/100] – 2433
   = (2625 + 2366 ) – 2433 = Rs. 2558
   Required Difference = 2558 – 2433 = Rs. 125

    

8. A vessel contains mixture of Kerosene and Petrol and petrol mixed in the ratio of 7:5 resp. 84 liters of the mixture is taken out of the vessel and replaced with 32 litres of petrol so that the ratio of the Petrol to Kerosene in the vessel becomes 11:9 resp. Find the initial quantity of Petrol in the vessel.
   77 litres
   70 litres
   85 litres
   74 litres
   80 litres
   Option E
   Let the initial quantities of Kerosene and Petrol be 7x and 5x resp.
   Now, (7x-49)/(5x-35+32) = 9/11
   => x= 16
   So, the initial quantity of Petrol in the vessel = 16*5 = 80 litres

    

9. Mr. Sharma distributed a certain amount of money among his wife, daughter and son. Amount received by the son and the daughter are in the ratio is 6:7 resp. And the amount received by the son and the wife are in the ratio 3:4 resp. Find the amount received by wife if the daughter received Rs. 28000.
   Rs. 32000
   Rs. 22000
   Rs. 25000
   Rs. 30000
   Rs. 28000
   Option A
   Amount received by Son and wife resp. = 28000*6/7
   = Rs. 24000 and 24000*4/3 = Rs. 32000

    

10. Monthly salaries of Puja and Nisha are in the ratio of 3:4 resp. Monthly savings of Puja and Nisha are in the ratio of 7:8 resp. Monthly expenditure of Puja is twice her monthly savings. Find the monthly salary of Nisha if her monthly expenditure is Rs. 6000 more than the monthly expenditure of Puja.
    Rs. 15000
    Rs. 25000
    Rs. 22000
    Rs. 28000
    Rs. 20000
    Option D
    Let the monthly savings of Puja and Nisha are Rs. 7x and 8x resp.
    Monthly expenditure of Puja = 2*7x = Rs. 14x
    Monthly expenditure of Nisha = Rs. 14x + 6000
    Now, (7x+14x)/(8x+14x+6000) = ¾
    =>x = 1000
    Monthly salary of Nisha = 22*1000 + 6000
    = Rs. 28000