**Directions(1-5):** Find the odd number of the following series.

- 26,32,45,64,94,136,192
26451926432Option B

+(3*2), +(4*3), +(5*4),+(6*5), +(7*6), +(8*7)

44 should be in place of 45. - 214,106,104,153,304,750
214104153750304Option E

*0.5-1, *1-2, *1.5-3, *2-4, *2.5-5

302 should be in place of 304. - 35,48,76,111,161,224
1113516148224Option D

+(4^2-1), +(5^2+1), +(6^2-1), +(7^2+1), +(8^2-1)

50 should be in place of 48. - 32,57,282,910,2132,4157
21322829105732Option C

+5^2, +15^2, +25^2, +35^2, +45^2

907 should be in place of 910. - 500,496,487,469,446,410
500487410469496Option D

-2^2,-3^2,-4^2,-5^2,-6^2

471 should be in place of 469. - The cost price of an article A is 30% more than the selling price of article B and selling price of article A is 80% more than the cost price of article B. If selling price of article A is 50% more than the selling price of article B then the cost price of article A is what percentage more/less than cost price of article B?
63%60%52%40%56%Option E

Let the CP of article B be Rs.x

SP of article A be Rs. 9x/5

Let SP of article B be Rs.y

CP of article A be Rs. 13y/10

Therefore, 9x/5 = 150% of y

=> y = 6x/5

CP of article A = 39x/25

Ratio of CP of article B to article A = x : 39x/25 = 25:39

Required% = 14/25*100 = 56% - Raju deposited an amount of Rs. 12500 at 10% per annum compound interest while amount of Rs. 16900 at 7% per annum simple interest at the same time for 2 years. What will be the difference in the total interest earned in the first year and the total interest earned in the second year ?
Rs. 130Rs. 120Rs. 115Rs. 125Rs. 100Option D

Total interest earned in the first year

= (12500*100*1)/100 + (16900*7*1)/100

= Rs. 2433

Total interest earned in the second year = [12500*{(1.1)^2 – 1} + (16900*7*2)/100] – 2433

= (2625 + 2366 ) – 2433 = Rs. 2558

Required Difference = 2558 – 2433 = Rs. 125 - A vessel contains mixture of Kerosene and Petrol and petrol mixed in the ratio of 7:5 resp. 84 liters of the mixture is taken out of the vessel and replaced with 32 litres of petrol so that the ratio of the Petrol to Kerosene in the vessel becomes 11:9 resp. Find the initial quantity of Petrol in the vessel.
77 litres70 litres85 litres74 litres80 litresOption E

Let the initial quantities of Kerosene and Petrol be 7x and 5x resp.

Now, (7x-49)/(5x-35+32) = 9/11

=> x= 16

So, the initial quantity of Petrol in the vessel = 16*5 = 80 litres - Mr. Sharma distributed a certain amount of money among his wife, daughter and son. Amount received by the son and the daughter are in the ratio is 6:7 resp. And the amount received by the son and the wife are in the ratio 3:4 resp. Find the amount received by wife if the daughter received Rs. 28000.
Rs. 32000Rs. 22000Rs. 25000Rs. 30000Rs. 28000Option A

Amount received by Son and wife resp. = 28000*6/7

= Rs. 24000 and 24000*4/3 = Rs. 32000 - Monthly salaries of Puja and Nisha are in the ratio of 3:4 resp. Monthly savings of Puja and Nisha are in the ratio of 7:8 resp. Monthly expenditure of Puja is twice her monthly savings. Find the monthly salary of Nisha if her monthly expenditure is Rs. 6000 more than the monthly expenditure of Puja.
Rs. 15000Rs. 25000Rs. 22000Rs. 28000Rs. 20000Option D

Let the monthly savings of Puja and Nisha are Rs. 7x and 8x resp.

Monthly expenditure of Puja = 2*7x = Rs. 14x

Monthly expenditure of Nisha = Rs. 14x + 6000

Now, (7x+14x)/(8x+14x+6000) = ¾

=>x = 1000

Monthly salary of Nisha = 22*1000 + 6000

= Rs. 28000