# Mixed Quantitative Aptitude Questions Set 202

1. An amount A is invested in scheme 1 for 2 years at 10% p.a compounded annually and an amount B is invested in scheme 2 for 3 years at 16% p.a simple interest. If the interest earned by scheme 1 is 87.5% of interest earned by scheme 2 and the total sum of amount invested in both scheme is Rs 9000. Then find the amount invested in scheme 1.

6000
5000
4000
7000
8000
Option A
A+ B = 9000 ——– i

In scheme 1,

Net effective rate = 10 + 10 + (10 * 10)/100 = 21%

Interest = 21x/100

Net effective rate = 3 * 16 = 48%

Interest = 48y/100

According to question,

48y/100 * 87.5/100 = 21x/100

48y/100 * 87.5 = 21x

4200y/100 = 21x

2y = x —— ii

Putting (ii) in (i)

x + y = 9000

2y + y = 9000

y = 3000

x = 9000 – 3000 = 6000

2. Lallu alone can do a piece of work in 25 days and Mallu is 16.66% inefficient less than Lallu. Mallu and Lallu started working together for 6 days then Shalu alone completed the rest work in 21 days. In how many days Shalu alone can complete the whole work?

41.5 days.
40.5 days.
36.5 days.
35.5 days.
37.5 days.
Option E
Time taken by Lallu alone = 25 days

Ratio of efficiency of Mallu and Lallu = 5 : 6

Ratio of time taken by Mallu and Lallu = 6 : 5

Therefore, time taken by Mallu alone = 30 days

Total work = LCM of 30 and 25 = 150 units

1 day work of Mallu = 150/30 = 5 units

1 day work of Lallu = 150/25 = 6 units

1 day work of (Lallu+ Mallu) = 5 + 6 = 11 units

6 days work of (A + B) = 7 * 11 = 66 units

Left work = 150 – 66 = 84 units

Now, Shalu can complete 84 units = 21 days

150 units = 21 * 150/84 = 37.5 days.

3. A box contains x green marbles, 4 red marbles and 5 white marbles 3 marbles are picked up randomly one after the another without replacement from the box. Find the value of x if probability of 3 marbles being green is 1/16.

9
8
7
6
5
Option C
Probability of getting 1st green marble = x/(x + 4 + 5) = x/x + 9

Probability of getting 2nd green marble without replacement = (x – 1)/(x + 8)

Probability of getting 3rd green marble without replacement = (x – 2)/(x + 7)

By question,

[x/x + 9] * [(x – 1)/(x + 8)] * [(x – 2)/(x + 7)] = 1/16
Now we will check through option and hence, option A = 7 satisfied the equation

So, value of x = 7

4. Kiran purchased an old car for Rs 30000 and spent 3500 in servicing, 1500 in engine repair. If he wants to earn 20% profit then at what price he must have to sell the car?

Rs 12000
Rs 52000
Rs 32000
Rs 42000
Rs 40000
Option D
Total C.P of car = (30000 + 3500 + 1500) = Rs 35000

Required Profit = 20%

So, required S.P = 120/100 * 35000 = Rs 42000

5. Man 1 and 2 started a business by investing Rs 2500 and Rs 2200 respectively. After 7 months they had invested 500 and 800 more amounts respectively. If the difference between the share of 1 and 2 is Rs 3486, find the total share earned after 1 year.

Rs 103314
Rs 204414
Rs 104414
Rs 103489
Rs 105000
Option C
Ratio of shares of 1 and 2 = (2500 * 7 + 3000 * 5) + (2200 * 7 + 3000 * 5)

= 325: 304

Let the total profit earned after 1 year = x

So, (325 – 304)/(325 + 304) * x = 3486

21x/629 = 3486

x = Rs 104414

6. 8 years ago the average ages of Lalith and Brijesh is 31 years and the present age of Lalith is 12 years less than the average of the ages of Brijesh and Simon 6 years hence. If Brijesh is 24 years elder than Simon, then find Simon’s age after 2 years?

26
27
21
22
25
Option A
Lalith + Brijesh = 31 * 2 + 16 = 78———-(1)

(Brijesh + 6 + lalith + 6)/2 – A = 12

Brijesh + Simon – 2Lalith = 12——–(2)

Brijesh – Simon = 24———–(3)

(2) + (3)

2Brijesh – 2Lalith = 36

Brijesh – Lalith = 18——-(4)

(4) + (1)

2Brijesh = 96

Brijesh = 48 years

Simon= 48 – 24 = 24 years

Simon’s age after 2 years = 24 + 2 = 26 years

7. If the ratio of the radius to slanting height of the conical vessele is 3:5 and volume of the cylindrical vessele is equal to the volume of the conical vessele. If the radius of the cylinder is 4 cm and the height of the cylindrical vessele is equal to the side of the square whose perimeter is 192 cm, then what is the curved surface area of the conical vessele?

200∏
140∏
210∏
240∏
540∏
Option D
Height of the conical vessele = √(5×2 – 3×2) = 4x

Volume of the conical vessele = 1/3 * 22/7 * r2 * h

Volume of the cylindrical vessele = 22/7 * r2 * h

Side of the square = 192/4 = 48

Height of the cylindrical vessele = 12

1/3 * 22/7 * 3x * 3x * 4x = 22/7 * 4 * 4 * 48

x = 4 cm

Radius of the conical vessele = 3 * 4 = 12 cm

Slating height of the conical vessele = 5 * 4 = 20 cm

CSA of the conical vessele = 22/7 * r * l

= 22/7 * 12 * 20 = 240∏

8. Mayur and Suraj started the business with the investment in the ratio of 5:2 and after 6 months Suraj withdrew half of his initial investment. At the end of one year Mayur and Suraj gets Rs.4000 and Rs.1500 from the total profit obtained for managing the business and the profit ratio of Mayur and Suraj is 3:1. What is the total profit obtained at the end of year?

14500
16000
14500
13000
12000
Option E
Profit ratio of Mayur and Suraj = 5x * 12:(2x * 6 + x * 6)

= 10:3

Total profit = (13x + 4000 + 1500) = 13x + 5500

(10x + 4000)/(3x + 1500) = 3/1

9x + 4500 = 10x + 4000

x = 500

Total profit = 13 * 500 + 5500 = 12000

9. The ratio of the monthly salary of person 1 to 2 is 4:3 and the ratio of the monthly salary of 2 to 3 is 2:1. If the difference between the 3’s monthly income and his savings is Rs.12000 and the saving’s of 3 is half of his expenditure, then what is the average of the income of person 1, 2 and 3?

24000
14000
34000
30000
20000
Option C
person 3’s salary = x

Expenditure = y

Savings = s

x = y + s

y + s – s = 12000

y = 12000

Savings = 12000 * ½ = 6000

x = 12000 + 6000 = 18000

person 2’s income = 2/1 * 18000 = 36000

person 1’s income = 4/3 * 36000 = 48000

Average income of 1, 2 and 3 = (48000 + 36000 + 18000)/3 = 34000

10. If the marked price of the chair is Rs.6000 more than the money Kunal had but the merchant offers two successive discounts 10% and 5% respectively. Now he left with him Rs.9370. What is the marked price of the chair?

116000
105000
106000
100000
105550
Option C
Kunal have = x

MP of the mobile = x + 6000

(x + 6000) * 90/100 * 95/100 + 9370 = x

0.855x + 5130 + 9370 = x

x = 100000

MP of chair = 100000 + 6000 = 106000

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