Directions (1-5): What will come in place of question mark (?) in the following number series?
4, 10, 22, 46, 94, ?
Correct
*2 + 2, *2 + 2, *2 + 2, *2 + 2, *2 + 2.
Incorrect
*2 + 2, *2 + 2, *2 + 2, *2 + 2, *2 + 2.
Unattempted
*2 + 2, *2 + 2, *2 + 2, *2 + 2, *2 + 2.
Question 6 of 35
6. Question
1 points
Directions (6- 10): What approximate value should come in place of the question mark (?) in the following questions?
(Note: You are not expected to calculate the exact value.)
2/9 × 1136 + 19.99 × 17.09 – √290 = ?
Correct
2/9 × 1134 + 20 × 17 – √289
252 + 340 – 17 = 575
Incorrect
2/9 × 1134 + 20 × 17 – √289
252 + 340 – 17 = 575
Unattempted
2/9 × 1134 + 20 × 17 – √289
252 + 340 – 17 = 575
Question 7 of 35
7. Question
1 points
Directions (6- 10): What approximate value should come in place of the question mark (?) in the following questions?
(Note: You are not expected to calculate the exact value.)
19.96% of 239.9 – 15.01% of 179.89 = ?% of 299.9
Correct
Incorrect
Unattempted
Question 8 of 35
8. Question
1 points
Directions (6- 10): What approximate value should come in place of the question mark (?) in the following questions?
(Note: You are not expected to calculate the exact value.)
√1935 + 13.03 × 24.98 = ? + 10.9% of 2239.9
Correct
Incorrect
Unattempted
Question 9 of 35
9. Question
1 points
Directions (6- 10): What approximate value should come in place of the question mark (?) in the following questions?
(Note: You are not expected to calculate the exact value.)
2434.07 – 846.89 + 27.04 × 15.92 = ? + 1567.9
Correct
Incorrect
Unattempted
Question 10 of 35
10. Question
1 points
Directions (6- 10): What approximate value should come in place of the question mark (?) in the following questions?
(Note: You are not expected to calculate the exact value.)
23.99% of 149.78 + 45.79% of 250.07 = (?)^{2} – 1700 ÷ 23
Correct
Incorrect
Unattempted
Question 11 of 35
11. Question
1 points
Directions (11-15): Study the following charts carefully and answer the questions that follow:
What is the number of males in department C?
Correct
6/13 * 26/100 * 1450 = 174
Incorrect
6/13 * 26/100 * 1450 = 174
Unattempted
6/13 * 26/100 * 1450 = 174
Question 12 of 35
12. Question
1 points
Directions (11-15): Study the following charts carefully and answer the questions that follow:
Females in department D is what percent less than the males in department B?
Correct
Females in D = 5/8 * 16/100 * 1450 = 145
Males in B = 7/12 * 24/100 * 1450 = 203
So required % = (203-145)/203 * 100 = 28.57%
Incorrect
Females in D = 5/8 * 16/100 * 1450 = 145
Males in B = 7/12 * 24/100 * 1450 = 203
So required % = (203-145)/203 * 100 = 28.57%
Unattempted
Females in D = 5/8 * 16/100 * 1450 = 145
Males in B = 7/12 * 24/100 * 1450 = 203
So required % = (203-145)/203 * 100 = 28.57%
Question 13 of 35
13. Question
1 points
Directions (11-15): Study the following charts carefully and answer the questions that follow:
In department E, if 50% of males and 60% of females are married, then what is the number of unmarried employees in department E?
Correct
Unmarried Males in E = 50% of 6/11 * 22/100 * 1450 = 87
Unmarried Females in E = 40% of 5/11 * 22/100 * 1450 = 58
So unmarried employees = 87 + 58 = 145
Incorrect
Unmarried Males in E = 50% of 6/11 * 22/100 * 1450 = 87
Unmarried Females in E = 40% of 5/11 * 22/100 * 1450 = 58
So unmarried employees = 87 + 58 = 145
Unattempted
Unmarried Males in E = 50% of 6/11 * 22/100 * 1450 = 87
Unmarried Females in E = 40% of 5/11 * 22/100 * 1450 = 58
So unmarried employees = 87 + 58 = 145
Question 14 of 35
14. Question
1 points
Directions (11-15): Study the following charts carefully and answer the questions that follow:
Total number of female employees is what percent of total number of male employees in the company?
Correct
Employees in
A = 174, Male employees = 2/3 * 174 = 116, Female employees = 58
B = 348, Male employees = 7/12 * 348 = 203, Female employees = 145
C = 377, Male employees = 6/13 * 377 = 174, Female employees = 203
D = 232, Male employees = 3/8 * 232 = 87, Female employees = 145
E = 319¸ Male employees = 6/11 * 319 = 174, Female employees = 145
Total male employees = 754
Total female employees = 696
So required % = 696/754 * 100 = 92.3%
Incorrect
Employees in
A = 174, Male employees = 2/3 * 174 = 116, Female employees = 58
B = 348, Male employees = 7/12 * 348 = 203, Female employees = 145
C = 377, Male employees = 6/13 * 377 = 174, Female employees = 203
D = 232, Male employees = 3/8 * 232 = 87, Female employees = 145
E = 319¸ Male employees = 6/11 * 319 = 174, Female employees = 145
Total male employees = 754
Total female employees = 696
So required % = 696/754 * 100 = 92.3%
Unattempted
Employees in
A = 174, Male employees = 2/3 * 174 = 116, Female employees = 58
B = 348, Male employees = 7/12 * 348 = 203, Female employees = 145
C = 377, Male employees = 6/13 * 377 = 174, Female employees = 203
D = 232, Male employees = 3/8 * 232 = 87, Female employees = 145
E = 319¸ Male employees = 6/11 * 319 = 174, Female employees = 145
Total male employees = 754
Total female employees = 696
So required % = 696/754 * 100 = 92.3%
Question 15 of 35
15. Question
1 points
Directions (11-15): Study the following charts carefully and answer the questions that follow:
If after a year the percentage of employees in each department remain same, and the total employees increase by 1000, then which of the following is true?
Correct
New number of employees = 1000 + 1450 = 1550
Old number of employees in department B = 348
and New number of employees in department D = 16/100 * 1550 = 248
So C option is true
Incorrect
New number of employees = 1000 + 1450 = 1550
Old number of employees in department B = 348
and New number of employees in department D = 16/100 * 1550 = 248
So C option is true
Unattempted
New number of employees = 1000 + 1450 = 1550
Old number of employees in department B = 348
and New number of employees in department D = 16/100 * 1550 = 248
So C option is true
Question 16 of 35
16. Question
1 points
Directions (16-20): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
I. 3x^{2} + 19x + 28 = 0,
II. 2y^{2} + 7y + 6 = 0
Correct
Explanation:
3x^{2} + 19x + 28 = 0
3x^{2} + 12x + 7x + 28 = 0
Gives x = -4, -7/3
2y^{2} + 7y + 6 = 0
2y^{2} + 4y + 3y + 6 = 0
Gives y = -2, -3/2
Put on number line
-4…. -7/3…. -2…. -3/2
Incorrect
Explanation:
3x^{2} + 19x + 28 = 0
3x^{2} + 12x + 7x + 28 = 0
Gives x = -4, -7/3
2y^{2} + 7y + 6 = 0
2y^{2} + 4y + 3y + 6 = 0
Gives y = -2, -3/2
Put on number line
-4…. -7/3…. -2…. -3/2
Unattempted
Explanation:
3x^{2} + 19x + 28 = 0
3x^{2} + 12x + 7x + 28 = 0
Gives x = -4, -7/3
2y^{2} + 7y + 6 = 0
2y^{2} + 4y + 3y + 6 = 0
Gives y = -2, -3/2
Put on number line
-4…. -7/3…. -2…. -3/2
Question 17 of 35
17. Question
1 points
Directions (16-20): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
I. 4x^{2} – 9x – 9 = 0,
II. 2y^{2} + 3y – 35 = 0
Correct
Explanation:
4x^{2} – 9x – 9 = 0
4x^{2} – 12x + 3x – 9 = 0
Gives x = -3/4, 3
2y^{2} + 3y – 35 = 0
2y^{2} + 10y – 7y – 35 = 0
Gives y = -5, 7/2
Put on number line
-5….. -3/4….. 3…. 7/2
Incorrect
Explanation:
4x^{2} – 9x – 9 = 0
4x^{2} – 12x + 3x – 9 = 0
Gives x = -3/4, 3
2y^{2} + 3y – 35 = 0
2y^{2} + 10y – 7y – 35 = 0
Gives y = -5, 7/2
Put on number line
-5….. -3/4….. 3…. 7/2
Unattempted
Explanation:
4x^{2} – 9x – 9 = 0
4x^{2} – 12x + 3x – 9 = 0
Gives x = -3/4, 3
2y^{2} + 3y – 35 = 0
2y^{2} + 10y – 7y – 35 = 0
Gives y = -5, 7/2
Put on number line
-5….. -3/4….. 3…. 7/2
Question 18 of 35
18. Question
1 points
Directions (16-20): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
I. 6x^{2} + 22x + 15 = 0,
II. 6y^{2} – 7y – 10 = 0
Correct
Explanation:
6x^{2} + 22x + 15 = 0
6x^{2} + 18x + 5x + 15 = 0
Gives x = -3, -5/6
6y^{2} – 7y – 10 = 0
6y^{2} – 12y + 5y – 10 = 0
Gives y = -5/6, 2
Put on number line
-3…. -5/6….. 2
Incorrect
Explanation:
6x^{2} + 22x + 15 = 0
6x^{2} + 18x + 5x + 15 = 0
Gives x = -3, -5/6
6y^{2} – 7y – 10 = 0
6y^{2} – 12y + 5y – 10 = 0
Gives y = -5/6, 2
Put on number line
-3…. -5/6….. 2
Unattempted
Explanation:
6x^{2} + 22x + 15 = 0
6x^{2} + 18x + 5x + 15 = 0
Gives x = -3, -5/6
6y^{2} – 7y – 10 = 0
6y^{2} – 12y + 5y – 10 = 0
Gives y = -5/6, 2
Put on number line
-3…. -5/6….. 2
Question 19 of 35
19. Question
1 points
Directions (16-20): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
I. 4x^{2} – 5x – 6 = 0,
II. 4y^{2} – 9y – 9 = 0
Correct
Explanation:
4x^{2} – 5x – 6 = 0
4x^{2} – 8x + 3x – 6 = 0
Gives x = -3/4, 2
4y^{2} – 9y – 9 = 0
4y^{2} – 12y + 3y – 9 = 0
Gives y = -3/4, 3
Put on number line
-3/4….. 2…. 3
Incorrect
Explanation:
4x^{2} – 5x – 6 = 0
4x^{2} – 8x + 3x – 6 = 0
Gives x = -3/4, 2
4y^{2} – 9y – 9 = 0
4y^{2} – 12y + 3y – 9 = 0
Gives y = -3/4, 3
Put on number line
-3/4….. 2…. 3
Unattempted
Explanation:
4x^{2} – 5x – 6 = 0
4x^{2} – 8x + 3x – 6 = 0
Gives x = -3/4, 2
4y^{2} – 9y – 9 = 0
4y^{2} – 12y + 3y – 9 = 0
Gives y = -3/4, 3
Put on number line
-3/4….. 2…. 3
Question 20 of 35
20. Question
1 points
Directions (16-20): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
I. 2x^{2} – 19x + 45 = 0,
II. y^{2} – 6y + 8 = 0
Correct
Explanation:
2x^{2} – 19x + 45 = 0
2x^{2} – 10x – 9x + 45 = 0
Gives x = 9/2, 5
y^{2} – 6y + 8 = 0
y^{2} – 2y – 4y + 8 = 0
Gives y = 2, 4
Put on number line
2…. 4…. 9/2…. 5
Incorrect
Explanation:
2x^{2} – 19x + 45 = 0
2x^{2} – 10x – 9x + 45 = 0
Gives x = 9/2, 5
y^{2} – 6y + 8 = 0
y^{2} – 2y – 4y + 8 = 0
Gives y = 2, 4
Put on number line
2…. 4…. 9/2…. 5
Unattempted
Explanation:
2x^{2} – 19x + 45 = 0
2x^{2} – 10x – 9x + 45 = 0
Gives x = 9/2, 5
y^{2} – 6y + 8 = 0
y^{2} – 2y – 4y + 8 = 0
Gives y = 2, 4
Put on number line
2…. 4…. 9/2…. 5
Question 21 of 35
21. Question
1 points
Perimeter of a rectangle is 120 m more than the circumference of a circle . If the length and breadth of the rectangle are in the ratio 5 : 4 and the length of rectangle and radius of circle are in ratio 10 : 3, find the area of the rectangle.
Correct
Explanation:
b/l = 4/5 and l/r = 10/3
So
b : l : r is
4*10 : 5*10 : 5*3
8 : 10 : 3
So perimeter of rectangle is 2(8x+10x) = 36x
and circumference of circle = 2 * 22/7 * 3x = 132x/7
So
36x = 120 + 132x/7
Solve, x = 7
So area of rectangle = 8x*10x = 3920 m^{2}
Incorrect
Explanation:
b/l = 4/5 and l/r = 10/3
So
b : l : r is
4*10 : 5*10 : 5*3
8 : 10 : 3
So perimeter of rectangle is 2(8x+10x) = 36x
and circumference of circle = 2 * 22/7 * 3x = 132x/7
So
36x = 120 + 132x/7
Solve, x = 7
So area of rectangle = 8x*10x = 3920 m^{2}
Unattempted
Explanation:
b/l = 4/5 and l/r = 10/3
So
b : l : r is
4*10 : 5*10 : 5*3
8 : 10 : 3
So perimeter of rectangle is 2(8x+10x) = 36x
and circumference of circle = 2 * 22/7 * 3x = 132x/7
So
36x = 120 + 132x/7
Solve, x = 7
So area of rectangle = 8x*10x = 3920 m^{2}
Question 22 of 35
22. Question
1 points
Ratio of age of A seven years hence to C five years ago is 6 : 5. Present ratio of ages of B and C is 9 : 10. If the present age of B is 4 more than the present age of A, find the age if B.
Correct
(A+7)/(C-5) = 6/5
B/C = 9/10
B = 4 + A
Solve
A = 23, B = 27, C = 30
Incorrect
(A+7)/(C-5) = 6/5
B/C = 9/10
B = 4 + A
Solve
A = 23, B = 27, C = 30
Unattempted
(A+7)/(C-5) = 6/5
B/C = 9/10
B = 4 + A
Solve
A = 23, B = 27, C = 30
Question 23 of 35
23. Question
1 points
The average age of 19 men in a group is 56 years. When 3 men from the group are excluded the average becomes 54 years. Find the total age of the 3 men excluded.
Correct
19…. 56
16…. 54
So total age of men excluded = 19*(56-54) + 54*(19-16) = 38 + 162 = 200 years
Incorrect
19…. 56
16…. 54
So total age of men excluded = 19*(56-54) + 54*(19-16) = 38 + 162 = 200 years
Unattempted
19…. 56
16…. 54
So total age of men excluded = 19*(56-54) + 54*(19-16) = 38 + 162 = 200 years
Question 24 of 35
24. Question
1 points
Thirty-two men can complete a work in 18 days and thirty-four women can complete the same work in 21 days. Twelve men and fourteen women started the work and continued for 16 days. If men now leave the work, how many days will be required by women to complete the remaining work?
Correct
32m in 18 days, so 12 in 32*18/12 = 48 days
34m in 21 days, so 14 in 34*21/14 = 51 days
They worked for 16 days, so in 16 they completed (1/48 + 1/51)*16 = 11/17 of work
So remaining work = 1 – 11/17 = 6/17
which is to be completed by 14 women
Now
34 w complete 1 work in 21 days, so 14 w complete 6/17 work in x days
So
34 * 21 * 6/17 = 14 * x * 1
Solve, x = 18 days
Incorrect
32m in 18 days, so 12 in 32*18/12 = 48 days
34m in 21 days, so 14 in 34*21/14 = 51 days
They worked for 16 days, so in 16 they completed (1/48 + 1/51)*16 = 11/17 of work
So remaining work = 1 – 11/17 = 6/17
which is to be completed by 14 women
Now
34 w complete 1 work in 21 days, so 14 w complete 6/17 work in x days
So
34 * 21 * 6/17 = 14 * x * 1
Solve, x = 18 days
Unattempted
32m in 18 days, so 12 in 32*18/12 = 48 days
34m in 21 days, so 14 in 34*21/14 = 51 days
They worked for 16 days, so in 16 they completed (1/48 + 1/51)*16 = 11/17 of work
So remaining work = 1 – 11/17 = 6/17
which is to be completed by 14 women
Now
34 w complete 1 work in 21 days, so 14 w complete 6/17 work in x days
So
34 * 21 * 6/17 = 14 * x * 1
Solve, x = 18 days
Question 25 of 35
25. Question
1 points
A box contains 320 tickets (numbered 1 to 320). Find the probability of drawing a ticket containing a multiple of 3 or 8.
Correct
Multiple of 3 up to 320 = 320/3 = 106
Multiple of 8 up to 320 = 320/8 = 40
Multiples of 3*8 = 24 up to 320 = 320/24 = 13
SO favorable events = 106 + 40 – 13 = 133
So required probability = 133/320
Incorrect
Multiple of 3 up to 320 = 320/3 = 106
Multiple of 8 up to 320 = 320/8 = 40
Multiples of 3*8 = 24 up to 320 = 320/24 = 13
SO favorable events = 106 + 40 – 13 = 133
So required probability = 133/320
Unattempted
Multiple of 3 up to 320 = 320/3 = 106
Multiple of 8 up to 320 = 320/8 = 40
Multiples of 3*8 = 24 up to 320 = 320/24 = 13
SO favorable events = 106 + 40 – 13 = 133
So required probability = 133/320
Question 26 of 35
26. Question
1 points
Directions (26-30): Study the table and answer the questions that follow.
Find the approximate average number of valid votes polled in village B over the given years.
Correct
Explanation:
(3200 +2600+3300)/3
Incorrect
Explanation:
(3200 +2600+3300)/3
Unattempted
Explanation:
(3200 +2600+3300)/3
Question 27 of 35
27. Question
1 points
Directions (26-30): Study the table and answer the questions that follow.
If in city A, the percentage increase in total votes polled in 2015 over 2010 is same as the percentage increase in total votes polled in 2010 over 2005, then find the number of total votes polled in 2015?
Correct
Explanation:
% increase in 2010 = (3840-3200)/3200 * 100 = 20%
So in 2015 = 120/100 * 3840
Incorrect
Explanation:
% increase in 2010 = (3840-3200)/3200 * 100 = 20%
So in 2015 = 120/100 * 3840
Unattempted
Explanation:
% increase in 2010 = (3840-3200)/3200 * 100 = 20%
So in 2015 = 120/100 * 3840
Question 28 of 35
28. Question
1 points
Directions (26-30): Study the table and answer the questions that follow.
If 25% of total votes polled in village A in 2005 are from females and total valid voted by females is 865, then find the number of valid votes from males in village A in same year.
Correct
Explanation:
Total valid votes are 2800 and by females is 865 so remaining by males.
2800 – 865 = 1935
Incorrect
Explanation:
Total valid votes are 2800 and by females is 865 so remaining by males.
2800 – 865 = 1935
Unattempted
Explanation:
Total valid votes are 2800 and by females is 865 so remaining by males.
2800 – 865 = 1935
Question 29 of 35
29. Question
1 points
Directions (26-30): Study the table and answer the questions that follow.
What is the approximate average number of invalid votes polled in 2000?
Directions (26-30): Study the table and answer the questions that follow.
Total invalid votes polled in village B in 2005 is what percent greater than total invalid votes in village C in 2005?
Correct
Explanation:
Invalid in B in 2005 = 3600-3300 = 300
Invalid in C in 2005 = 3600-3450 = 150
So required % = (300-150)/150 * 100 = 100%
Incorrect
Explanation:
Invalid in B in 2005 = 3600-3300 = 300
Invalid in C in 2005 = 3600-3450 = 150
So required % = (300-150)/150 * 100 = 100%
Unattempted
Explanation:
Invalid in B in 2005 = 3600-3300 = 300
Invalid in C in 2005 = 3600-3450 = 150
So required % = (300-150)/150 * 100 = 100%
Question 31 of 35
31. Question
1 points
A sum of Rs 6000 is invested in parts in two schemes for 3 years and 2 years respectively. Scheme A offers 11% rate of interest per annum and scheme B offers 10% rate of interest compounded annually. If amount obtained from first part is Rs 2520 less than twice the amount obtained from second part, find the amount invested in Scheme A.
Correct
x + x*11*3/100 = 2[(6000-x)*(1 + 10/100)^{2}] – 2520
133x/100 = 120*121 – 242x/100 – 2520
375x/100 = 12000
So x = Rs 3200
Incorrect
x + x*11*3/100 = 2[(6000-x)*(1 + 10/100)^{2}] – 2520
133x/100 = 120*121 – 242x/100 – 2520
375x/100 = 12000
So x = Rs 3200
Unattempted
x + x*11*3/100 = 2[(6000-x)*(1 + 10/100)^{2}] – 2520
133x/100 = 120*121 – 242x/100 – 2520
375x/100 = 12000
So x = Rs 3200
Question 32 of 35
32. Question
1 points
An article is marked 30% above the cost price. While selling the shopkeeper gives a discount of 10%. What is the profit percent o the shopkeeper if he also uses false weights of 1000 gm instead of 1200 gm?
Correct
Profit % when false weights are used = (1200-1000)/1000 * 100 = 20%
Now let CP = 100
So MP = 130 (30% above the cost price)
So SP after discount = 90/100 * 130 = 117
Now seller selling 20% less in weight so CP = Rs 80
Now CP = 80, SP = 117
So profit % = 37/80 * 100
Incorrect
Profit % when false weights are used = (1200-1000)/1000 * 100 = 20%
Now let CP = 100
So MP = 130 (30% above the cost price)
So SP after discount = 90/100 * 130 = 117
Now seller selling 20% less in weight so CP = Rs 80
Now CP = 80, SP = 117
So profit % = 37/80 * 100
Unattempted
Profit % when false weights are used = (1200-1000)/1000 * 100 = 20%
Now let CP = 100
So MP = 130 (30% above the cost price)
So SP after discount = 90/100 * 130 = 117
Now seller selling 20% less in weight so CP = Rs 80
Now CP = 80, SP = 117
So profit % = 37/80 * 100
Question 33 of 35
33. Question
1 points
A solution contains alcohol and water in the ratio 3 : 1. 16 litres of the solution is drawn and 12 litres of water is added. Now 11 litres of the mixture is replaced by 11 litres of the water. If the final ratio of alcohol to water in the solution is 9 : 13, find the initial quantity of the solution.
Correct
Solving with options will help.
initial ratio is 3 : 1
So total is 4. So total quantity must be a multiple of 4, so discard option C) 50
Next check with other options:
16 litres withdrawn, so alcohol withdrawn is 3/4 * 16 = 12 l, and water withdrawn is 1/4 * 16 = 4 l
A) 48 in the ratio 3 : 1 is 36 and 12. Now
So alcohol now is 36-12 = 24 and water = 12 – 4 = 8
Now 12 l water added so water becomes = 8 + 12 = 20
See now alcohol + water is 24+20 = 44 which is a multiple of 11 (since 11 litres withdrawn next)
So this can be the answer
Proceed further to find out that if this is the answer
In other options we do not get a multiple of 11 in that step.
Incorrect
Solving with options will help.
initial ratio is 3 : 1
So total is 4. So total quantity must be a multiple of 4, so discard option C) 50
Next check with other options:
16 litres withdrawn, so alcohol withdrawn is 3/4 * 16 = 12 l, and water withdrawn is 1/4 * 16 = 4 l
A) 48 in the ratio 3 : 1 is 36 and 12. Now
So alcohol now is 36-12 = 24 and water = 12 – 4 = 8
Now 12 l water added so water becomes = 8 + 12 = 20
See now alcohol + water is 24+20 = 44 which is a multiple of 11 (since 11 litres withdrawn next)
So this can be the answer
Proceed further to find out that if this is the answer
In other options we do not get a multiple of 11 in that step.
Unattempted
Solving with options will help.
initial ratio is 3 : 1
So total is 4. So total quantity must be a multiple of 4, so discard option C) 50
Next check with other options:
16 litres withdrawn, so alcohol withdrawn is 3/4 * 16 = 12 l, and water withdrawn is 1/4 * 16 = 4 l
A) 48 in the ratio 3 : 1 is 36 and 12. Now
So alcohol now is 36-12 = 24 and water = 12 – 4 = 8
Now 12 l water added so water becomes = 8 + 12 = 20
See now alcohol + water is 24+20 = 44 which is a multiple of 11 (since 11 litres withdrawn next)
So this can be the answer
Proceed further to find out that if this is the answer
In other options we do not get a multiple of 11 in that step.
Question 34 of 35
34. Question
1 points
A and B started a business by investing Rs10,000 and Rs 11,000 respectively. After 4 months they both withdrew Rs 1000. After a further of half year, A invested Rs 1000 more and B invested Rs 2000 more. If a total profit received after a year is Rs 54,450, what is the difference in the shares of A and B?
10 man can do a work in 50 days. While 20 women can do the same work in 40 days. Three teams A,B and C formed having different number of men and women. Team A contains 20 men and 10 women. Team B contains 25 men and 8 women. Team C contains 5 men and 40 women. If the team that completes the work in minimum time wins the game, which team will emerge as the winner?
Correct
10 men => 50 days ; 20 women => 40 days
Team A (20 men->25 days ; 10 women->80 days)=(25*80)/(25+80)= 19.04 days
Team B(25 men->20 days ; 8 women->100 days)=(20*100)/(120)=16.66 days
Team C(5 men->100 days ; 40 women->20 days)=16.66 days
Incorrect
10 men => 50 days ; 20 women => 40 days
Team A (20 men->25 days ; 10 women->80 days)=(25*80)/(25+80)= 19.04 days
Team B(25 men->20 days ; 8 women->100 days)=(20*100)/(120)=16.66 days
Team C(5 men->100 days ; 40 women->20 days)=16.66 days
Unattempted
10 men => 50 days ; 20 women => 40 days
Team A (20 men->25 days ; 10 women->80 days)=(25*80)/(25+80)= 19.04 days
Team B(25 men->20 days ; 8 women->100 days)=(20*100)/(120)=16.66 days
Team C(5 men->100 days ; 40 women->20 days)=16.66 days
Results
24 of 35 questions answered correctly
Your time: 00:25:00
good initiative please upload it on daily basis if possible
18 of 35 questions answered correctly
Your time: 00:23:18
You have reached 18 of 35 points, (51.43%)
Wah 🙂
Practice more sets 🙂
Ok mam