# Quant Sectional Test 3 for LIC AAO 2019 Prelim Exam

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We have come up with Sectional Tests for upcoming LIC AAO 2019 Prelim Exam. Practice the questions to ace the exam.

Directions(1-10): What approximate value will come in place of question mark ‘?’ in the following questions.

1. 32% of 250 + 18% of 350 + (8*9) = ?
220
195
200
222
215
Option E
32% of 250 + 18% of 350 + (8*9) = ?
=>80+ 63 + 72 = ?
=> ? = 215

2. 427 + ? – 732 = 29^2 – 456
622
690
740
800
770
Option B
427 + ? – 732 = 29^2 – 456
=>? – 305 = 841 – 456
=>? -305 =385
=>? = 690

3. 84^2 – 79^2 + (1936)^1/2 – 20% of 980 = ?
693
555
663
744
721
Option C
84^2 – 79^2 + (1936)^1/2 – 20% of 980 = ?
=>(84+79)(84 -79) + (1936)^1/2 – 20% of 980 = ?
=>815 + 44 – 196 = ?
=>? = 663

4. 3.2% of 500 * 2.4 % of ? = 288
815
700
666
750
781
Option D
3.2% of 500 * 2.4 % of ? = 288
=>16*2.4/100 * ? =288
=> ? = 750

5. 3024 / 12 + 14^2 – 25% of 820 = ? – 20% of 650
320
373
400
410
375
Option B 3024 / 12 + 14^2 – 25% of 820 = ? – 20% of 650
=>? – 0.20 * 650 = 252 + 196 -0.25* 820
=>? – 130 =448 – 205
=>? = 373

6. 32*15 + ? – 25*16 = 45 * 20
740
815
820
723
700
Option C
32*15 + ? – 25*16 = 45 * 20
=>480 + ? – 400 = 900
=>? = 820

7. 25*13 + 148 – 28 – 42 = ? – 224
715
620
600
627
750
Option D
25*13 + 148 – 28 – 42 = ? – 224
=> ? = 325 + 148 – 70 + 224
=>? = 627

8. (784)^1/2 * 29 – ?^3 =180 + 17^2
5
9
8
7
6
Option D
(784)^1/2 * 29 – ?^3 =180 + 17^2
=>28*29 – ?^3 = 180 + 289
=>?^3 = 343
=> ? = 7

9. (300/11)% of 4620 – 840 = ? * 7
60
55
42
65
50
Option A
(300/11)% of 4620 – 840 = ? * 7
=>(3/11) of 4620 – 840 = ? * 7
=>1260 – 840 = ? * 7
=>? = 60

10. 2620% of 40 + 40% of 825 = ?
1220
1424
1378
1300
1175
Option C
2620% of 40 + 40% of 825 = ?
=> ? = 40% of 2620 + 40% of 825
=>? = 1048 + 330
=>? = 1378

11. Directions(11-15): Following the graph shows the percentage profit gained by two companies A and B over the year 2007 to 2012. 12. In which of the following years is the percentage of expenditure with respect to income is 80% for Company A?
90%
60%
80%
50%
70%
Option C
Let the expenditure be x.
Income = x*(100+25)/100 = 1.25x
% = x/1.25x*100 = 80%

13. The income of Company A in the year 2012 and the expenditure of Company B in the year 2009 was the same, that is Rs.90 lakh. What will be the ratio of the income of Company B in 2009 to the expenditure of Company A in the year 2012?
6:7
2:3
7:6
9:5
8:7
Option D
% PA = 20%
ExpenditureA = I/1.2 = 90/1.2 = 75 lakhs
% PB = 35%
IncomeB = 90 × 1.35 = 135 lakhs
Ratio = 135/75 = 9/5

14. If the expenditure of Company B in the year 2010 was Rs.40 lakh, what was its income (in Rs) in the year 2013?
70,000
80,000
50,000
60,000
Option E

15. If the expenditure of Company A in the year 2011 and 2012 was in the ratio 6 : 5, what was the ratio of its incomes?
15 : 14
13 : 10
8 : 9
15 : 11
17 : 12
Option B
E1 = 6
E2 = 5
Now,I1 = E1 *(100+30)/100 = E1 * 1.3
I1/I2 = (E1/E2) * (1.3/1.2) = 78/6
I1 : I2 = 13 : 10

16. If the income of Company B in year 2009 was Rs91.8 lakh, what was its expenditure (in Rs) in that year?
Rs. 80 lakh
Rs. 74 lakh
Rs. 55 lakh
Rs. 68 lakh
Rs. 60 lakh
Option D
% profit = 35%
Expenditure = Income × 100/(100 %P)
91.8*(100/135) = Rs. 68 lakh

17. I. 4x^2 – 13x + 10 = 0
II.4y^2 + 11y – 3 = 0

y >= x
y > x
No relation
x > y
x >= y
Option D
I. 4x^2 – 13x + 10 = 0
=>4x^2 – 8x – 5x + 10 = 0
=>(x-2)(4x- 5) = 0
=>x = 2,5/4
II.4y^2 + 11y – 3 = 0
=>4y^2 + 12y – y – 3 = 0
=>(y+3)(4y – 1) = 0
=>y = -3,1/4
x > y

18. I. 2x^2 – 15x + 25 = 0
II. 3y^2 = 4y + 15
y > x
x > y
x >= y
y >= x
No relation
Option E
I. 2x^2 – 15x + 25 = 0
=>2x^2 – 10x – 5x + 25 = 0
=>(2x-5)(x-5) = 0
=>x = 5,5/2
II. 3y^2 = 4y + 15
=>3y^2 – 4y – 15 = 0
=>3y^2 – 9y + 5y – 15 = 0
=>(3y + 5)(y – 3) = 0
=>y = 3, – 5/3
No relation

19. I.x^2 + 20x + 96 = 0
II.y^2 + 25y + 156 = 0
y > x
No relation
x >= y
y >= x
x > y
Option C
I.x^2 + 20x + 96 = 0
=>x^2 + 12x + 8x + 96 = 0
=>(x+8)(x+12) = 0
=>x= -8, – 12
II.y^2 + 25y + 156 = 0
=>y^2 + 13y + 12y + 156 = 0
=>(y+13)(y+12) = 0
=>y = -13,-12
x >= y

20. I. 2x + 5y = 51
II.9x – 4y = 44
x > y
No relation
y >= x
y > x
x >= y
Option A
On solving both the equations, we get
x = 8
y = 7
x > y

21. I.3x^2 – 29x + 66 = 0
II. 4y^2 – 57y + 198 = 0
x >= y
No relation
x > y
y >= x
y > x
Option D
I.3x^2 – 29x + 66 = 0
=>3x^2 – 18x – 11x + 66 = 0
=>(x – 6)(3x – 11) = 0
=>x = 6,11/3
II. 4y^2 – 57y + 198 = 0
=>4y^2 – 24y – 33y + 198 = 0
=>(y-6)(4y – 33) = 0
=>y = 6, 33/4
y >= x

22. 8, 11, 17, 47, 128, 371, 1100
11
8
17
47
371
Option C
8 + 3 =11
11 + 3^2 = 11 + 9 = 20 == 17
20 + 3^3 = 20 + 27 = 47
47 + 3^4 = 47 + 81 = 128
128 + 3^5 = 128 + 243 = 371

23. 1, 5, 13, 31, 61, 125, 253
31
13
5
1
61
Option A
1 + 2^2 = 1 + 4 = 5
5 + 2^3 = 5 + 8 = 13
13 + 2^4 = 13 + 16 = 29 == 31
29 + 2^5 = 29 + 32 = 61
61 + 2^6 = 61 + 64 = 125

24. 150, 290, 560, 1120, 2140, 4230
150
1120
290
2140
4230
Option B
150 × 2 – 1 × 10
= 300 – 10 = 290
290 × 2 – 2 × 10
= 580 – 20 = 560
560 × 2 – 3 × 10 = 1120 – 30
= 1090 == 1120
1090 × 2 – 4 × 10 = 2180 – 40 = 2140
2140 × 2 – 5 × 10 = 4280 – 50 = 4230

25. 10, 8, 13, 35, 135, 671, 4007
135
35
10
671
8
Option D
10 × 1 – 2 = 8
8 × 2 – 3 = 13
13 × 3 – 4 = 35
35 × 4 – 5 = 135
135 × 5 – 6 = 675 – 6
= 669 == 671
669 × 6 – 7 = 4014 – 7 = 4007

26. 29, 37, 21, 43, 13, 53, 5
29
37
21
53
43
Option E
29 + 1 × 8 = 37
37 – 2 × 8 = 37 – 16 = 21
21 + 3 × 8 = 21 + 24 = 45 == 43
45 – 4 × 8 = 45 – 32 = 13
13 + 5 × 8 = 13 + 40 = 53
53 – 6 × 8 = 53 – 48 = 5

27. C is 40% more efficient than B who is 25% more efficient than A. If A,B and C together can complete a work in 35 days. How many days B alone can complete 75% of the work?
80 days
77 days
60 days
74 days
84 days
Option E
Let the workdone by A in one day = x units
workdone by B in one day = 1.25x units
workdone by C in one day = 1.25x *1.40 = 1.75x units
Total work = 35(x + 1.25x + 1.75x) = 140x units
Time taken by B alone to complete 75% work = (0.75*140x)/1.25x = 84 days

28. The ratio of speed of Anil and Sunil is 4:3. Ravi can travel a distance of 840 km in 14 hours. If the speed of Sunil is 20% less than the speed of Ravi. What will be the time taken by Anil to travel to a distance of 512 km?
6 hours
7 hours
5 hours
8 hours
9 hours
Option D
Speed of Ravi = 840/14 = 60 km/hr.
Speed of Sunil = 0.8*60 = 48 km/hr.
Speed of Anil = (4/3)*48 = 64 km/hr.
Required time = 512/64 = 8 hours

29. Varun deposited Rs.12000 in a bank for 2 years at 15% simple interest per annum. After 2 years, the total amount was transferred to a scheme for 2 years at a compound interest of 10% per annum. Find the compound interest earned from the scheme.
Rs.4124
Rs.3276
Rs.2850
Rs.2152
Rs.3200
Option B
Amount deposited in the scheme = 12000+(12000*15*2)/100 = Rs.15600
Required compound interest earned from the scheme = 15600*{(1.1)^2 -1} = Rs.3276

30. The length and breadth of a rectangular plot are in the ratio of 3:2 resp. If the cost incurred for fencing the plot at the rate of Rs.12.5/m is Rs.1000. Find the area of the equilateral triangle whose side is equal to the breadth of the reactangle.
50(3)^1/2 m^2
48(3)^1/2 m^2
64(3)^1/2 m^2
55(3)^1/2 m^2
60(3)^1/2 m^2
Option C
2(3x+2x) = 1000/12.5
=>x = 8
Length =24 m
Breadth = 16 m
Area of equilateral triangle = (3)^1/2 /4 * 16*16 = 64(3)^1/2 m^2

31. A boatman can cover 192 km upstream and 260 km downstream in 12.5 hours. If the ratio of upstream speed to downstream speed is 4:5 resp. Find the length of the train which takes 24 seconds to cross the tree at the speed equal to the speed of boat in still water.
280 m
240 m
250 m
180 m
200 m
Option B
Let the upstream and downstream speed be 4x and 5x km/hr resp.
192/4x + 260/5x = 12.5
=>x = 8
Speed in still water =( 4x+5x )/2 = 9x/2 = 36 km/hr = 10 m/s
Length of train = 10*24 = 240 m

32. A man sold two books, one at a loss of 10% and other at a gain of 25%. If the cost price of each book is same , find the overall profit or loss percentage in this transaction.
5.8%
7.5%
8.1%
6.6%
4.5%
Option B
Let the CP of each book be Rs.x.
SP of both books = 0.9x + 1.25x = Rs.2.15x
CP of both books = Rs.2x
Required profit% = (0.15x/2x)*100 = 7.5%

33. A and B together started a business with investment of Rs.580 and Rs.x resp. If the profit share of B is 75% more than that of A. Find the value of x.
1000
1015
880
928
950
Option B
Let the profit share of A be Rs.x
Profit share of B = Rs.1.75y
Ratio = y:1.75y = 4:7
Now,
580/x = 4/7
=>x = 1015

34. Pipe A and Pipe B can fill a tank together in (60/7) minutes. If pipe A is 33.33% more efficient than pipe B. Find the time taken by pipe A alone to fill the tank.
18 minutes
15 minutes
8 minutes
5 minutes
10 minutes
Option B
Let the efficiency of pipe B be 3x.
Efficiency of pipe A = 4x
Now,
1/3x + 1/4x = 7/60
=>x = 5
Time taken by pipe A alone to fill the tank = 3x = 15 minutes

35. A solution contains 48 ml of acid and 52 ml of water is completely mixed with some quantity of 25% acid solution. If the ratio of acid to water in the final mixture is 3:5. Find the quantity of 25% acid solution mixed to the initial solution.
84
70
74
81
68
Option A
Let the quantity of second solution be x ml.
Amount of acid in final mixture = (48+0.25x) ml
Amount of water in final mixture = (52+0.75x) ml
(48+0.25x)/ (52+0.75x) = 3/5
=>x= 84

36. A bag contains 8 red balls and 3 orange balls. Three balls are randomly selected. Find the number of ways in which atleast 2 orange balls are selected.
22 ways
10 ways
25 ways
18 ways
20 ways
Option C
Required number of ways = 3C2*8C1 + 3C3 = 25 ways