Quant Sectional Test 3 for SBI PO 2019 Prelim Exam

Directions(1-10): What approximate value will come in place of question mark “?” in the following questions.

  1. 15.5% of 849 + 24.8% of 651 = ?
    300
    325
    295
    414
    221
    Option C
    15.5% of 849 + 24.8% of 651 = ?
    =>?= 131.75+ 161.2 = 292.95 == 295

     

  2. 4376 + 3209 – 1784 + 97 = 3125 + ?
    2660
    2552
    2120
    2773
    2250
    Option D
    4376 + 3209 – 1784 + 97 = 3125 + ?
    =>?= 7682 – 4909 = 2773

     

  3. 85% of 420 + ?% of 1080 = 735
    35
    44
    33
    28
    30
    Option A
    85% of 420 + ?% of 1080 = 735
    => ? = 35

     

  4. 30% of 1225 – 64% of 555 = ?
    10
    9
    8
    6
    12
    Option E
    30% of 1225 – 64% of 555 = ?
    ? = 367.5 – 355.2 = 12.3 == 12

     

  5. 39.95% of 265 + 35.2% of 178 = 50% of ? + ?% of 80
    140
    130
    120
    100
    110
    Option B
    39.95% of 265 + 35.2% of 178 = 50% of ? + ?% of 80
    =>106 + 63 = 0.5 ×?+ ?/ 100 × 80
    => 16900 = 130 ×?
    => ?= 130

     

  6. 16.217 × 23.88 + ? = 18.98 × 32.12
    218
    230
    250
    224
    212
    Option D
    16.217 × 23.88 + ? = 18.98 × 32.12
    =>16 × 24 + ? = 19 × 32
    => ? = 608 – 384 = 224

     

  7. 27.897 × 16.21 = ? × 13.98 + 69.87
    25
    20
    22
    23
    27
    Option E
    27.897 × 16.21 = ? × 13.98 + 69.87
    =>28 × 16 = ? × 14 + 70
    =>448 = ? × 14 + 70
    => ? = 378/14 = 27

     

  8. 272.112 + 189.98 + 84.101 = ? × 12.89 × 6.11
    5
    7
    3
    2
    9
    Option B
    272.112 + 189.98 + 84.101 = ? × 12.89 × 6.11
    =>272 + 190 + 84 = ? × 13 × 6
    => ? = 546/13×6 = 7

     

  9. (421.98 + 478.21) ÷ ? = 60.029
    12
    10
    15
    13
    19
    Option C
    (421.98 + 478.21) ÷ ? = 60.029
    =>(422 + 478) ÷ ? = 60
    => ? = 900/60 = 15

     

  10. √257 × 19.17 + 8.15 × 13.78 = ?
    333
    395
    420
    400
    416
    Option E
    √257 × 19.17 + 8.15 × 13.78 = ?
    ? = √256 × 19 + 8 × 14
    =>? = 16 × 19 + 8 × 14 = 416

     

  11. A boat travel 75 km downstream and take same time as it travels 60 km in upstream. Speed of boat in downstream is what percent of the speed of boat in still water.
    112(1/7)%
    117(1/5)%
    100(1/3)%
    111(1/9)%
    120(1/5)%
    Option D
    75/(𝑥 + 𝑦) = 60/( 𝑥 – 𝑦)
    => 75x – 75y = 60x + 60y
    =>15x = 135y
    =>x = 9y
    Required percentage = 10y /9y × 100 = 111(1/9)%

     

  12. 40 men, working 8 hours a day can do a piece of work in 15 days. Find the number of days in which second group of 60 men working 4 hrs a day can do twice the work. Assume that 3 men of the first group do as much work in 2 hour as 4 men of the second group do in 3 hrs.
    80
    50
    60
    70
    90
    Option A
    Let efficiency of men of first group is M1 and second group
    3M1 × 2 = 4M2 × 3
    M1 = 2M2
    work = 40M1 × 8 × 15
    According to question,
    40M1 × 8 × 15 × 2 = 60M2 × 4 × d
    d = 80 days

     

  13. If the volume and curved surface area of a cylinder 616 𝐦^𝟑 and 352m^2 respectively, what is the total surface area of the cylinder (in 𝐦^𝟐 )?
    420 m^2
    444 m^2
    450 m^2
    429 m^2
    414 m^2
    Option D
    Πr^ 2h/2πrh = 616/352
    r = 3.5 m
    𝜋𝑟 ^2ℎ = 616
    h = 616/(11 × 3.5) = 16 m
    Total S.A. = 2𝜋𝑟ℎ + 2𝜋𝑟^2
    = 2πr(h + r) = 2 × 22/7× 3.5(3.5 + 16) = 429 m^2

     

  14. 14 men can do a work in 18 days ,15 women can do a work in 24 days. If 14 men work for first three days and 10 women work after that for three days find the part of work left after that?
    2/13
    7/11
    2/5
    3/4
    1/6
    Option D
    Work done in first 3 days = 3 × 1/18 = 1/6
    Work done in next 3 days = 2/3 × 3 × 1/24 = 1/12
    Remaining work = 1 – (1/6 + 1/12) = ¾

     

  15. Perimeter of a rectangle is x and circumference of a circle is 8 more than the perimeter of the rectangle. Ratio of radius of circle and length of the rectangle is 1:2 and ratio of length and breadth of rectangle is 7:3. Find the length of the rectangle?
    29 cm
    28 cm
    30 cm
    25 cm
    21 cm
    Option B
    Let length and breadth are 7x, 3x
    Perimeter = 20x
    Circumference of circle = 20x + 8
    Radius of circle = 1/2 × 7x = 3.5x
    =>2x + 8 = 44/7 × 7x/2
    =>x = 4
    Length = 28 cm

     

  16. The average marks in Science subject of a class of 20 students is 68. If the marks of two students were misread as 48 and 65 of the actual marks 72 and 61 respectively, then what would be the correct average?
    92
    69
    71
    85
    60
    Option B
    Increase in average marks = [(72+61) – (48+65)]/20 = 133 – 113/ 20 = 20/20
    Correct average = 68 +1 = 69

     

  17. A is 2 years older than B while B is 3 year younger than C. The ratio of age of A 6 years hence and B 2 years ago is 5:3. What was age of C 6 years ago?
    18 years
    14 years
    16 years
    10 years
    12 years
    Option B
    A ==B ==C
    𝑥 + 2== 𝑥== 𝑥 + 3
    ( 𝑥 + 2 +6)/( 𝑥 − 2 ) = 5/3
    ( 𝑥 + 8)/(𝑥 – 2) = 5/2
    =>3𝑥 + 24 = 5𝑥 −10
    => 34 = 2𝑥
    => 𝑥 = 17
    Age of C, 6 year ago = 17 + 3 −6 = 14 years

     

  18. Two trains crosses each other in 14 sec when they are moving in opposite direction, and when they are moving in same direction they crosses each other in 3 minute2 sec. Find the speed of the faster train by what percent more than the speed of the slower train?
    14(1/7)%
    11(5/6)%
    16(2/3)%
    13(3/5)%
    10(1/4)%
    Option C
    Let sum of length of both trains = L And speed = 𝑥 & 𝑦
    𝐿/( 𝑥 –𝑦) = 182
    𝐿/( 𝑥 + 𝑦) = 14
    14( 𝑥 + 𝑦) = 182( 𝑥 –𝑦)
    ( 𝑥 – 𝑦)/(𝑥 + 𝑦) = 1/13
    12𝑥 = 14𝑦
    =>𝑥 = 7/6𝑦
    Required percentage = (7−6)/ 6 × 100 = 16(2/3)%

     

  19. Aman’s expense is 30% more than Vimal’s expense and vimal’s expense is 10% less than Raman’s expense. If the sum of their expenses is Rs. 6447, then what would be the Aman’s expense?
    Rs.2562
    Rs.2457
    Rs.2331
    Rs.2120
    Rs.2200
    Option B
    Aman== Vimal== Raman
    117==90==100
    307 – >6447
    1 – > 6447/307
    117 -> 6447/307*117 = Rs.2457

     

  20. In an examination, a student scores 4 marks for every correct answer and losses 1 mark for every wrong answer. A student attempted all the 200 questions and scored in all 200 marks. The number of questions, he answered correctly was:
    70
    90
    80
    60
    120
    Option C
    Let the number of corrected answer be ‘x’.
    Number of wrong answer be (200- x)
    4x – (200-x) = 200
    =>x = 80

     

  21. Directions(21-25): Find the values of x and y and then choose a correct option.

  22. (i) 2x² – 5x + 3 = 0
    (ii) 3y² – 4y + 1 = 0
    x >= y
    y > x
    y >= x
    y > x
    No relation can be established
    Option A
    (i) 2x² – 5x + 3 = 0
    => 2x² – 2x – 3x + 3 = 0
    2x (x – 1) – 3(x – 1) = 0
    (x – 1) (2x – 3) = 0
    x = 1, 3/2
    (ii) 3y² – 4y + 1 = 0
    3y² – 3y – y + 1 = 0
    3y(y – 1) –1 (y – 1) = 0
    (3y – 1) (y – 1) = 0
    y = 1/3 , 1
    x >= y

     

  23. (i) (x – 12)² = 0
    (ii) y² – 21y + 108 = 0
    y > x
    y >= x
    y > x
    No relation can be established
    x >= y
    Option E
    (i) (x – 12)² = 0
    x – 12 = 0
    x = 12
    (ii) y² – 21y + 108 = 0
    y² – 12y – 9y + 108 = 0
    y (y – 12) – 9 (y – 12) = 0
    (y – 9) (y – 12) = 0
    y = 9, 12
    x ≥ y

     

  24. (i) 2x² + 7x + 5 = 0
    (ii) 3y² + 12y + 9 = 0
    x >= y
    y > x
    y >= x
    y > x
    No relation can be established
    Option E
    (i) 2x² + 7x + 5 = 0
    2x² + 2x + 5x + 5 = 0
    2x (x + 1) + 5 (x + 1) = 0
    (2x + 5) (x + 1) = 0
    𝑥 = – 5/2 , – 1
    (ii) 3y² + 12y + 9 = 0
    3y² + 9y + 3y + 9 = 0
    3y (y + 3) +3 (y + 3) = 0
    (3y + 3) (y + 3) = 0
    y = –1, – 3
    No relation can be established.

     

  25. (i) x² + 2x – 35 = 0
    (ii) y² + 15y + 56 = 0
    y >= x
    y > x
    x >= y
    No relation can be established.
    y > x
    Option C
    (i) x² + 2x – 35 = 0
    x² + 7x – 5x – 35 = 0
    x (x + 7) – 5 (x + 7) = 0
    (x – 5) (x + 7) = 0
    x = 5, –7
    (ii) y² + 15y + 56 = 0
    y² + 7y + 8y + 56 = 0
    y (y + 7) + 6 (y + 7) = 0
    (y + 8) (y + 7) = 0
    y = – 8, – 7
    x ≥ y

     

  26. (i) x² – 17x + 72 = 0
    (ii) y² – 27y + 180 = 0
    y >= x
    x >= y
    y > x
    No relation can be established
    y > x
    Option E
    (i) x² – 17x + 72 = 0
    x² – 9x – 8x + 72 = 0
    x(x – 9) – 8 (x – 9) = 0
    (x – 8) (x – 9) = 0
    x = 8, 9
    (ii) y² – 27y + 180 = 0
    y² – 12y – 15y + 180 = 0
    y(y – 12) – 15 (y – 12) = 0
    (y – 15) (y – 12) = 0
    y = 15, 12
    y > x

     

  27. Directions(26-30): Study the table carefully to answer the questions that follow: Number of people(in thousands) staying in 6 different cities and the percentage of men,women and children in those cities.

  28. What is the average number of men from all the cities together?
    23200
    15880
    18950
    26100
    21280
    Option A
    Average = [18373+14472+25474+15547+35235+30104]/6 == 23200

     

  29. What is the ratio of the number of women from city R to that from city T?
    8001:9001
    8311:9250
    8125:9261
    8401:9135
    8413:9115
    Option D
    Ratio = 54200*31/100 : 65250*28/100
    = 8401:9135

     

  30. Which city has the lowest number of children?
    P
    Q
    R
    S
    T
    Option B
    Q
    P= 12571
    Q= 8040
    R =11924
    S =8884
    T =11745
    U= 12496

     

  31. Total number of people from city U form approximately what per cent of the total number of people from all cities together?
    12%
    10%
    17%
    19%
    13%
    Option D
    Required% = 56.8/301.8*100 == 19%

     

  32. The number of women from city S forms what per cent of that from city P?
    120%
    100%
    115%
    125%
    130%
    Option C
    Required% = 44.42*45%/48.35*36%*100 =114.84 == 115%

     

  33. Directions(31-35): Find the missing term ‘?’ of the following series.

  34. 11, 20, 38, 74,?
    120
    125
    146
    150
    113
    Option C
    +9, +18, +36, +72
    ? = 146

     

  35. 15, 21, 38, 65, 101, ?
    162
    155
    130
    120
    145
    Option E
    Double difference
    ? = 145

     

  36. 24, 28,19, 35, 10, ?
    44
    46
    35
    40
    38
    Option B
    +2^ 2 ,−3^ 2 ,+4^ 2 ,−5 ^2
    ? = 46

     

  37. 7, 16, 45, 184, 915, ?
    5496
    5000
    5125
    5500
    5210
    Option A
    × 2+ 2, × 3 − 3, × 4+ 4, × 5 – 5
    ? = 5496

     

  38. 12, 19, 35, 59, 90, ?
    120
    118
    127
    110
    114
    Option C
    Double difference
    ? = 127

     


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