# Quant Sectional Test 3 for SBI PO 2019 Prelim Exam

Directions(1-10): What approximate value will come in place of question mark “?” in the following questions.

1. 15.5% of 849 + 24.8% of 651 = ?
300
325
295
414
221
Option C
15.5% of 849 + 24.8% of 651 = ?
=>?= 131.75+ 161.2 = 292.95 == 295

2. 4376 + 3209 – 1784 + 97 = 3125 + ?
2660
2552
2120
2773
2250
Option D
4376 + 3209 – 1784 + 97 = 3125 + ?
=>?= 7682 – 4909 = 2773

3. 85% of 420 + ?% of 1080 = 735
35
44
33
28
30
Option A
85% of 420 + ?% of 1080 = 735
=> ? = 35

4. 30% of 1225 – 64% of 555 = ?
10
9
8
6
12
Option E
30% of 1225 – 64% of 555 = ?
? = 367.5 – 355.2 = 12.3 == 12

5. 39.95% of 265 + 35.2% of 178 = 50% of ? + ?% of 80
140
130
120
100
110
Option B
39.95% of 265 + 35.2% of 178 = 50% of ? + ?% of 80
=>106 + 63 = 0.5 ×?+ ?/ 100 × 80
=> 16900 = 130 ×?
=> ?= 130

6. 16.217 × 23.88 + ? = 18.98 × 32.12
218
230
250
224
212
Option D
16.217 × 23.88 + ? = 18.98 × 32.12
=>16 × 24 + ? = 19 × 32
=> ? = 608 – 384 = 224

7. 27.897 × 16.21 = ? × 13.98 + 69.87
25
20
22
23
27
Option E
27.897 × 16.21 = ? × 13.98 + 69.87
=>28 × 16 = ? × 14 + 70
=>448 = ? × 14 + 70
=> ? = 378/14 = 27

8. 272.112 + 189.98 + 84.101 = ? × 12.89 × 6.11
5
7
3
2
9
Option B
272.112 + 189.98 + 84.101 = ? × 12.89 × 6.11
=>272 + 190 + 84 = ? × 13 × 6
=> ? = 546/13×6 = 7

9. (421.98 + 478.21) ÷ ? = 60.029
12
10
15
13
19
Option C
(421.98 + 478.21) ÷ ? = 60.029
=>(422 + 478) ÷ ? = 60
=> ? = 900/60 = 15

10. √257 × 19.17 + 8.15 × 13.78 = ?
333
395
420
400
416
Option E
√257 × 19.17 + 8.15 × 13.78 = ?
? = √256 × 19 + 8 × 14
=>? = 16 × 19 + 8 × 14 = 416

11. A boat travel 75 km downstream and take same time as it travels 60 km in upstream. Speed of boat in downstream is what percent of the speed of boat in still water.
112(1/7)%
117(1/5)%
100(1/3)%
111(1/9)%
120(1/5)%
Option D
75/(𝑥 + 𝑦) = 60/( 𝑥 – 𝑦)
=> 75x – 75y = 60x + 60y
=>15x = 135y
=>x = 9y
Required percentage = 10y /9y × 100 = 111(1/9)%

12. 40 men, working 8 hours a day can do a piece of work in 15 days. Find the number of days in which second group of 60 men working 4 hrs a day can do twice the work. Assume that 3 men of the first group do as much work in 2 hour as 4 men of the second group do in 3 hrs.
80
50
60
70
90
Option A
Let efficiency of men of first group is M1 and second group
3M1 × 2 = 4M2 × 3
M1 = 2M2
work = 40M1 × 8 × 15
According to question,
40M1 × 8 × 15 × 2 = 60M2 × 4 × d
d = 80 days

13. If the volume and curved surface area of a cylinder 616 𝐦^𝟑 and 352m^2 respectively, what is the total surface area of the cylinder (in 𝐦^𝟐 )?
420 m^2
444 m^2
450 m^2
429 m^2
414 m^2
Option D
Πr^ 2h/2πrh = 616/352
r = 3.5 m
𝜋𝑟 ^2ℎ = 616
h = 616/(11 × 3.5) = 16 m
Total S.A. = 2𝜋𝑟ℎ + 2𝜋𝑟^2
= 2πr(h + r) = 2 × 22/7× 3.5(3.5 + 16) = 429 m^2

14. 14 men can do a work in 18 days ,15 women can do a work in 24 days. If 14 men work for first three days and 10 women work after that for three days find the part of work left after that?
2/13
7/11
2/5
3/4
1/6
Option D
Work done in first 3 days = 3 × 1/18 = 1/6
Work done in next 3 days = 2/3 × 3 × 1/24 = 1/12
Remaining work = 1 – (1/6 + 1/12) = ¾

15. Perimeter of a rectangle is x and circumference of a circle is 8 more than the perimeter of the rectangle. Ratio of radius of circle and length of the rectangle is 1:2 and ratio of length and breadth of rectangle is 7:3. Find the length of the rectangle?
29 cm
28 cm
30 cm
25 cm
21 cm
Option B
Let length and breadth are 7x, 3x
Perimeter = 20x
Circumference of circle = 20x + 8
Radius of circle = 1/2 × 7x = 3.5x
=>2x + 8 = 44/7 × 7x/2
=>x = 4
Length = 28 cm

16. The average marks in Science subject of a class of 20 students is 68. If the marks of two students were misread as 48 and 65 of the actual marks 72 and 61 respectively, then what would be the correct average?
92
69
71
85
60
Option B
Increase in average marks = [(72+61) – (48+65)]/20 = 133 – 113/ 20 = 20/20
Correct average = 68 +1 = 69

17. A is 2 years older than B while B is 3 year younger than C. The ratio of age of A 6 years hence and B 2 years ago is 5:3. What was age of C 6 years ago?
18 years
14 years
16 years
10 years
12 years
Option B
A ==B ==C
𝑥 + 2== 𝑥== 𝑥 + 3
( 𝑥 + 2 +6)/( 𝑥 − 2 ) = 5/3
( 𝑥 + 8)/(𝑥 – 2) = 5/2
=>3𝑥 + 24 = 5𝑥 −10
=> 34 = 2𝑥
=> 𝑥 = 17
Age of C, 6 year ago = 17 + 3 −6 = 14 years

18. Two trains crosses each other in 14 sec when they are moving in opposite direction, and when they are moving in same direction they crosses each other in 3 minute2 sec. Find the speed of the faster train by what percent more than the speed of the slower train?
14(1/7)%
11(5/6)%
16(2/3)%
13(3/5)%
10(1/4)%
Option C
Let sum of length of both trains = L And speed = 𝑥 & 𝑦
𝐿/( 𝑥 –𝑦) = 182
𝐿/( 𝑥 + 𝑦) = 14
14( 𝑥 + 𝑦) = 182( 𝑥 –𝑦)
( 𝑥 – 𝑦)/(𝑥 + 𝑦) = 1/13
12𝑥 = 14𝑦
=>𝑥 = 7/6𝑦
Required percentage = (7−6)/ 6 × 100 = 16(2/3)%

19. Aman’s expense is 30% more than Vimal’s expense and vimal’s expense is 10% less than Raman’s expense. If the sum of their expenses is Rs. 6447, then what would be the Aman’s expense?
Rs.2562
Rs.2457
Rs.2331
Rs.2120
Rs.2200
Option B
Aman== Vimal== Raman
117==90==100
307 – >6447
1 – > 6447/307
117 -> 6447/307*117 = Rs.2457

20. In an examination, a student scores 4 marks for every correct answer and losses 1 mark for every wrong answer. A student attempted all the 200 questions and scored in all 200 marks. The number of questions, he answered correctly was:
70
90
80
60
120
Option C
Let the number of corrected answer be ‘x’.
Number of wrong answer be (200- x)
4x – (200-x) = 200
=>x = 80

21. Directions(21-25): Find the values of x and y and then choose a correct option.

22. (i) 2x² – 5x + 3 = 0
(ii) 3y² – 4y + 1 = 0
x >= y
y > x
y >= x
y > x
No relation can be established
Option A
(i) 2x² – 5x + 3 = 0
=> 2x² – 2x – 3x + 3 = 0
2x (x – 1) – 3(x – 1) = 0
(x – 1) (2x – 3) = 0
x = 1, 3/2
(ii) 3y² – 4y + 1 = 0
3y² – 3y – y + 1 = 0
3y(y – 1) –1 (y – 1) = 0
(3y – 1) (y – 1) = 0
y = 1/3 , 1
x >= y

23. (i) (x – 12)² = 0
(ii) y² – 21y + 108 = 0
y > x
y >= x
y > x
No relation can be established
x >= y
Option E
(i) (x – 12)² = 0
x – 12 = 0
x = 12
(ii) y² – 21y + 108 = 0
y² – 12y – 9y + 108 = 0
y (y – 12) – 9 (y – 12) = 0
(y – 9) (y – 12) = 0
y = 9, 12
x ≥ y

24. (i) 2x² + 7x + 5 = 0
(ii) 3y² + 12y + 9 = 0
x >= y
y > x
y >= x
y > x
No relation can be established
Option E
(i) 2x² + 7x + 5 = 0
2x² + 2x + 5x + 5 = 0
2x (x + 1) + 5 (x + 1) = 0
(2x + 5) (x + 1) = 0
𝑥 = – 5/2 , – 1
(ii) 3y² + 12y + 9 = 0
3y² + 9y + 3y + 9 = 0
3y (y + 3) +3 (y + 3) = 0
(3y + 3) (y + 3) = 0
y = –1, – 3
No relation can be established.

25. (i) x² + 2x – 35 = 0
(ii) y² + 15y + 56 = 0
y >= x
y > x
x >= y
No relation can be established.
y > x
Option C
(i) x² + 2x – 35 = 0
x² + 7x – 5x – 35 = 0
x (x + 7) – 5 (x + 7) = 0
(x – 5) (x + 7) = 0
x = 5, –7
(ii) y² + 15y + 56 = 0
y² + 7y + 8y + 56 = 0
y (y + 7) + 6 (y + 7) = 0
(y + 8) (y + 7) = 0
y = – 8, – 7
x ≥ y

26. (i) x² – 17x + 72 = 0
(ii) y² – 27y + 180 = 0
y >= x
x >= y
y > x
No relation can be established
y > x
Option E
(i) x² – 17x + 72 = 0
x² – 9x – 8x + 72 = 0
x(x – 9) – 8 (x – 9) = 0
(x – 8) (x – 9) = 0
x = 8, 9
(ii) y² – 27y + 180 = 0
y² – 12y – 15y + 180 = 0
y(y – 12) – 15 (y – 12) = 0
(y – 15) (y – 12) = 0
y = 15, 12
y > x

27. Directions(26-30): Study the table carefully to answer the questions that follow: Number of people(in thousands) staying in 6 different cities and the percentage of men,women and children in those cities.

28. What is the average number of men from all the cities together?
23200
15880
18950
26100
21280
Option A
Average = [18373+14472+25474+15547+35235+30104]/6 == 23200

29. What is the ratio of the number of women from city R to that from city T?
8001:9001
8311:9250
8125:9261
8401:9135
8413:9115
Option D
Ratio = 54200*31/100 : 65250*28/100
= 8401:9135

30. Which city has the lowest number of children?
P
Q
R
S
T
Option B
Q
P= 12571
Q= 8040
R =11924
S =8884
T =11745
U= 12496

31. Total number of people from city U form approximately what per cent of the total number of people from all cities together?
12%
10%
17%
19%
13%
Option D
Required% = 56.8/301.8*100 == 19%

32. The number of women from city S forms what per cent of that from city P?
120%
100%
115%
125%
130%
Option C
Required% = 44.42*45%/48.35*36%*100 =114.84 == 115%

33. Directions(31-35): Find the missing term ‘?’ of the following series.

34. 11, 20, 38, 74,?
120
125
146
150
113
Option C
+9, +18, +36, +72
? = 146

35. 15, 21, 38, 65, 101, ?
162
155
130
120
145
Option E
Double difference
? = 145

36. 24, 28,19, 35, 10, ?
44
46
35
40
38
Option B
+2^ 2 ,−3^ 2 ,+4^ 2 ,−5 ^2
? = 46

37. 7, 16, 45, 184, 915, ?
5496
5000
5125
5500
5210
Option A
× 2+ 2, × 3 − 3, × 4+ 4, × 5 – 5
? = 5496

38. 12, 19, 35, 59, 90, ?
120
118
127
110
114
Option C
Double difference
? = 127