Quant Sectional Test 4 for LIC AAO 2019 Prelim Exam

Hello Aspirants
We have come up with Sectional Tests for upcoming LIC AAO 2019 Prelim Exam. Practice the questions to ace the exam.

  1. P and Q together started a business with investment of Rs.580 and Rs.x resp. If the profit share of Q is 75% more than that of P. Find the value of x.
    Rs.1525
    Rs.1440
    Rs.1330
    Rs.1015
    Rs.1210
    Option D
    Let the profit share of P be Rs.y.
    Profit share of Q = Rs.1.75y
    Ratio of profit share of P and Q = y:1.75y = 4:7
    Now,
    580/x = 4/7
    =>x = Rs.1015

     

  2. Pipe A and pipe B can fill a tank together in (60/7) minutes. If pipe A is 33.33% more efficient than pipe B. Find the time taken by pipe A alone to fill the tank.
    12 minutes
    15 minutes
    10 minutes
    17 minutes
    18 minutes
    Option B
    Let the efficiency of pipe B be 3x and pipe A be 4x.
    Now,
    1/3x+1/4x = 7/60
    =>x = 5
    Time taken by pipe A alone to fill the tank = 3x = 15 minutes

     

  3. Arun took a loan of Rs. 1400 with simple interest for as many years as the rate of interest. If he paid Rs.686 as interest at the end of the loan period, what was the rate of interest?
    7%
    8%
    6%
    9%
    5%
    Option A
    Let rate = R% Then, Time, T = R years

    P = Rs.1400
    SI = Rs.686
    SI= PRT/100
    ⇒686 = 1400 × R × R/100
    ⇒686=14 R^2
    ⇒R=7%

     

  4. A man sold two books, one at a loss of 10% and other at a gain of 25%. If the cost price of each book is same. Find the overall profit or loss percentage in this transaction.
    8.5%
    6.9%
    8.1%
    6.6%
    7.5%
    Option E
    Let the CP of each book be Rs.x.
    SP of both the books together = 0.9x+1.25x = Rs.2.15x
    CP of both books together Rs.2x
    Required profit % = (0.15x/2x)*100 = 7.5%

     

  5. A bag contains 8 pink balls and 3 white balls. Three balls are randomly selected. Find the number of ways in which atleast 2 white balls are selected.
    29 ways
    20 ways
    25 ways
    30 ways
    22 ways
    Option C
    Required number of ways = 3C2*8C1 + 3C3 = 25 ways

     

  6. Directions(6-10): Answer the following questions based on the given information.
    The table shows the percentage distribution of the number of people who like different fruits and one person like only one fruit.
    Total number of people who like different fruits = 7500

  7. The number of people who like Apples like only one out of Apple juice and Apple shakes. The number of people who like Apple juice and Apple shakes are in the ratio of 5:4 resp. Find the number of people who like Apple juice.
    2000
    1000
    5000
    3000
    6000
    Option B
    Required number of people who like Apple juice = (5/9)*1800 = 1000

     

  8. Find the ratio of the number of people who like Raspberry to the number of people who like Jackfruit.
    8:7
    3:4
    2:3
    7:5
    2:1
    Option C
    Required ratio = 900:1350 = 2:3

     

  9. Number of people who like Jackfruit is how much more than the number of people who like Raspberry ?
    545
    440
    320
    450
    400
    Option D
    Required Difference = (1350 – 900) = 450

     

  10. Number of people who like Apple is what percentage more or less than the number of people who like Banana?
    20%
    30%
    40%
    60%
    50%
    Option E
    Required% = [(1800-1200)]/1200*100 = 50%

     

  11. Find the average number of people who like Banana and Raspberry taken together.
    777
    800
    950
    1050
    1210
    Option D
    Average = (1200+900)/2 = 1050

     

  12. Directions(11-15): Answer the questions based on following given below.
    The graph given below shows the percentage distribution of the number of pencils manufactured by five different companies in 2010. If the cost of manufacturing a Camlin pencil is Rs.1.2. The total amount spent to manufacture Camlin pencils in 2010is Rs.1296.

  13. Number of pencils manufactured by Camlin and Pringle in 2011 is 30% and 20% resp. more than teh previous year resp. Find the difference between the number of pencils manufactured by Camlin in 2011 and number of pencils manufactured by Pringle in 2011.
    30
    40
    36
    28
    44
    Option C
    Number of camlin pencils manufactured in 2010 = 1296/1.20 = 1080
    Total number of pencils manufactured by all the five companies together in 2010 = 1080/0.18 = 6000
    Number of pencils manufactured by Camlin in 2011 = 1.30*1080 = 1404
    Number of pencils manufactured by Pringle in 2011 = 1.20*1140 = 1368
    Required Difference = 1404 – 1368 = 36

     

  14. What is the ratio of the number of pencils manufactured by Camlin and Apsara together in 2010 to the total number of pencils manufactured by Natraj and Classmate together in 2010?
    5:6
    8:7
    2:3
    1:2
    5:4
    Option E
    Number of camlin pencils manufactured in 2010 = 1296/1.20 = 1080
    Total number of pencils manufactured by all the five companies together in 2010 = 1080/0.18 = 6000
    Required ratio = 2700:2160 = 5:4

     

  15. What is the total number of pencils manufactured by Camlin and Classmate together in 2010?
    1500
    1700
    1800
    1600
    1900
    Option C
    Number of camlin pencils manufactured in 2010 = 1296/1.20 = 1080
    Total number of pencils manufactured by all the five companies together in 2010 = 1080/0.18 = 6000
    Number of pencils manufactured by Camlin and Classmate =1080+720 = 1800

     

  16. What is the average number of pencils manufactured by Natraj, Apsara and Pringle in 2010?
    1500
    1400
    1600
    1300
    1200
    Option B
    Number of camlin pencils manufactured in 2010 = 1296/1.20 = 1080
    Total number of pencils manufactured by all the five companies together in 2010 = 1080/0.18 = 6000
    Average number of pencils = (1440+1620+1140)/3 = 1400

     

  17. If Natraj sold 75% of the pencil manufactured by it in 2010 at the rate Rs. 2.50 per pencil. Find the revenue generated by Natraj in 2010 by selling pencils.
    Rs.2700
    Rs.2000
    Rs.2500
    Rs.2200
    Rs.2800
    Option A
    Number of camlin pencils manufactured in 2010 = 1296/1.20 = 1080
    Total number of pencils manufactured by all the five companies together in 2015 = 1080/0.18 = 6000
    Number of pencils sold by Natraj in 2010 = 0.75*1440 = 1080
    Revenue generated by Natraj in 2010 = 100*2.5 = Rs.2700

     

  18. Directions(16-20): Find the missing term ‘?’ of the following series.

  19. 24,11,10,14,27,?
    53.4
    71.4
    58.7
    66.5
    62.2
    Option D
    *0.5-1
    *1-1
    *1.5-1
    *2-1
    *2.5-1
    ? = 66.5

     

  20. 13,15,20,30,?,73
    32
    40
    47
    50
    38
    Option C
    Difference of difference = 3,5,7,9
    ? = 47

     

  21. 14,7,7,14,56,?
    422
    387
    400
    448
    395
    Option D
    *0.5
    *1
    *2
    *4
    *8
    ? = 448

     

  22. 24,31,43,60,82,?
    99
    86
    112
    109
    97
    Option D
    +7,+12,+17,+22,+27
    ? = 109

     

  23. 9,13,21,37,?,133
    74
    69
    50
    60
    72
    Option B
    +4,+8,+16,+32,+64
    ? = 69

     


  24. Directions(21-25):
    Compare both the equations and choose a correct option.

  25. I.2x^2 + 13x + 20 = 0
    II.3y^2 – y -10 = 0
    y >= x
    y > x
    x > y
    No relation
    x >= y
    Option B
    I.2x^2 + 13x + 20 = 0
    =>2x^2 + 8x + 5x + 20 = 0
    =>(2x+5)(x+4) = 0
    =>x= -2.5,-4
    II.3y^2 – y -10 = 0
    =>3y^2 – 6y + 5y – 10 = 0
    =>(3y+5)(y -2) = 0
    =>y = -1.66,2
    y > x

     

  26. I.4x^2 – 2x – 12 = 0
    II.y^2 – 9y + 20 = 0
    x > y
    No relation
    x >= y
    y > x
    y >= x
    Option D
    I.4x^2 – 2x – 12 = 0
    =>4x^2 – 8x + 6x – 12 = 0
    =>(4x+6)(x-2) = 0
    =>x = -1.5,2
    II.y^2 – 9y + 20 = 0
    =>(y-4)(y-5) = 0
    =>y = 4,5
    y>x

     

  27. I.x^2 – 3x – 28 = 0
    II.y^2 – y – 72 = 0
    No relation
    x >= y
    x > y
    y >= x
    y > x
    Option A
    I.x^2 – 3x – 28 = 0
    =>x^2 – 7x + 4x – 28 = 0
    =>(x+4)(x-7) = 0
    =>x = 7,-4
    II.y^2 – y – 72 = 0
    =>y^2 + 9y – 8y – 72 = 0
    =>(y+8)(y-9) = 0
    =>y = -8,9
    No relation

     

  28. I.2x^2 – 6x – 36 = 0
    II.3y^2 + 24y + 45 = 0
    y > x
    y >= x
    x >= y
    No relation
    x > y
    Option C
    I.2x^2 – 6x – 36 = 0
    =>2x^2 – 12x + 6x – 36 = 0
    =>(2x+6)(x-6) = 0
    =>x= -3,6
    II.3y^2 + 24y + 45 = 0
    =>3y^2 + 9y + 15y + 45 = 0
    =>(3y+15)(y+3) = 0
    =>y = -5,-3
    x>=y

     

  29. I.9x+8y = 4+5x+13y
    II.5x – 4y = 2 + 2x
    x >= y
    y > x
    y >= x
    x > y
    No relation
    Option D
    I.9x+8y = 4+5x+13y
    =>4x -5y = 4 – (1)
    II.5x – 4y = 2 + 2x
    3x – 2y = 2 – (2)
    Solve both the equations, we get
    x = 6
    y = 4
    x > y

     

  30. Directions(26-35): What will be the approximate value of the following questions.

  31. 54.97% of 800 + 32.89*4 – 396.12 /17.91 = ?
    488
    450
    500
    550
    620
    Option D
    54.97% of 800 + 32.89*4 – 396.12 /17.91 = ?
    =>55% of 800 + 33*4 – 396/18 = ?
    =>440+132 – 22 = ?
    =>? = 550

     

  32. 19^2 + (1024)^1/2 – 256 – 9*7 = ?
    66
    70
    58
    74
    82
    Option D
    19^2 + (1024)^1/2 – 256 – 9*7 = ?
    =>361 + 32 – 256 -63 = ?
    =>? = 74

     

  33. 35% of √3136 x 5 = ? + 54
    50
    48
    36
    30
    44
    Option E
    35% of √3136 x 5 = ? + 54
    =>(65/100)*56*5 = ? + 54
    =>98 – 54 = 44

     

  34. √7396 x √1296 ÷ √676 = ?
    125
    119
    115
    108
    110
    Option B
    √7396 x √1296 ÷ √676 = ?
    =>86 x 36 ÷ 26 = 119

     

  35. (23.1)^2 + (48.6)^2 – (39.8)^2 = 163.84 + ?
    1440
    1525
    1148
    1384
    1220
    Option C
    (23.1)^2 + (48.6)^2 – (39.8)^2 = 163.84 + ?
    =>533.61 + 2361.96 – 1584.04 = 163.84 + ?
    =>1311.53 – 163.84 = 1147.69 ==1148

     

  36. (441)^1/2 + (169)^1/2 – 14.04^2 + 207.89 = ?
    35
    33
    40
    42
    46
    Option E
    (441)^1/2 + (169)^1/2 – 14.04^2 + 207.89 = ?
    =>21 + 13 – 196 + 208 = ?
    =>? = 46

     

  37. 44.97 + 310.08 + 9.13 *4.89 =?^2
    20
    10
    30
    50
    40
    Option A
    44.97 + 310.08 + 9.13 *4.89 =?^2
    =>45 + 310 + 9*5 = ?^2
    =>? = 20

     

  38. 348/29 + 24*9 – 211 = ?
    11
    19
    15
    17
    13
    Option D
    348/29 + 24*9 – 211 = ?
    =>12+216 = ? + 211
    =>? = 17

     

  39. 1226 + 3*13 = ? + 1690 – 1864 + 903
    490
    486
    520
    475
    536
    Option E
    1226 + 3*13 = ? + 1690 – 1864 + 903
    =>1226 + 39 = ?+ 729
    =>? = 536

     

  40. 80% of 310 – 24% of 350 = (?)^1/2 + 13^2
    21
    25
    20
    26
    28
    Option B
    80% of 310 – 24% of 350 = (?)^1/2 + 13^2
    =>248 – 84 = (?)^1/2 + 169
    =>? = 25

     


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