**Directions(1-5):** Find the missing term of the following series.

- 192,96,?,360,1260,5670
150100125144130Option D

*0.5,*1.5,*2.5,*3.5,*4.5

? = 144 - 37,60,89,?,157,198
1071201159890Option B

+23,+29,+31,+37,+41

? = 120 - 25,46,88,?,235,340
144160151142155Option C

+21*1

+21*2

+21*3

+21*4

+21*5

? = 151 - 17,28,?,116,193,292
4850305361Option E

+11*1

+11*3

+11*5

+11*7

+11*9

? = 61 - 39,40,49,74,123,?
210204190200198Option B

+1^2,+3^2,+5^2,+7^2,+9^2 = 204 -
**Quantity I:**A shopkeeper marks up an item by 50% above the cost price and sold it after offering a discount of 20%. The profit earned by shopkeeper is what percentage less than the profit earned by him, if he marks up the item by 75% above the cost price and offers a discount of 20%.

**Quantity II:**The area of the square built on the side of a square is what percentage less than the area of square built on the diagonal of a square?Quantity I =< Quantity IIQuantity I < Quantity IIQuantity I > Quantity IIQuantity I >= Quantity IIQuantity I = Quantity IIOption

From I: case 1: Let the CP of the item be Rs.x.

SP = 1.5x*0.8 = Rs. 1.2x

Profit = 1.2x – x = Rs. 0.2x

case 2: Let the CP of the item be Rs.x.

SP = 1.75x*0.8 = Rs.1.4x

Required% = {(0.4x-0.2x)/0.4x}*100 = 50%

From II: Let side of the square be a unit.

Length of the diagonal of the square = (2)^1/2a

Area of the square = a^2 units

Area of the square built on the diagonal = [(2)^1/2*a]^2 = 2a^2 unit

Required% = (2a^2-a^2)/2a^2*100 = 50%

Quantity I = Quantity II - >Quantity I: X and Y together started a business with an investment of Rs. 2400 and Rs. 3600 resp. After x months, Z joined them with an investment of Rs. 3000. If after a year, Y received Rs. 2700 out of total profit of Rs. 6000 find the value of x.

**Quantity II:**A and B together started a business with total investments of Rs. 4500 in the ratio of investment 5:x resp. If after a year, B received Rs. 3200 as profit out of a total profit of Rs. 7200 find the value of x.Quantity I > Quantity IIQuantity I < Quantity IIQuantity I = Quantity IIQuantity I =< Quantity IIQuantity I >= Quantity IIOption C

From I: Ratio of investments of X:Y:Z = 4:6:5

Ratio of profit share of X:Y:Z = 48:72:5(12-x) 72/[48+72+5(12-x)] = 9/20

=> x = 4

From II: Ratio of profit share of A:B = 5:x x/(5+x) =4/9

=> x= 4

Quantity I = Quantity II -
**Quantity I:**Radius of the base and the height of the circular cylinder are in the ratio is 3:7 resp. Find the diameter of the base, if its volume is 1584 cm^2.

**Quantity II:**Radius of the base and the height of the circular cone are in the ratio 6:7 resp. Find the radius of the base if its volume is 2112 cm^3.Quantity I =< Quantity IIQuantity I > Quantity IIQuantity I >= Quantity IIQuantity I = Quantity IIQuantity I < Quantity IIOption D

From I:Volume = 22/7*(3x)^2*7x = 1584

=> x = 2

Diameter of the base of the cylinder = 2*3*2 = 12 cm

From II: Volume = 1/3*22/7*(6x)^2*7x =2112

=> x = 2

Quantity I = Quantity II - Quantity I: Two positive numbers are in the ratio of 3:5 resp. The difference between the squares of the two numbers is 1024. Find the larger of the two numbers. Quantity II: A number is 25% more than the another number. Average of these two numbers is 36. Find the largest number.
Quantity I = Quantity IIQuantity I >= Quantity IIQuantity I =< Quantity IIQuantity I < Quantity IIQuantity I > Quantity IIOption A

From I: Let the numbers be 3x and 5x.

(5x)^2 – (3x)^2 = 1024

=> x = -8,8

Numbers are 24,40.

Larger number = 40

From II: First number be x and second number be 1.25x.

x+1.25x = 2*36

=> x= 32

Largest number = 1.25*32 = 40

Quantity I = Quantity II -
**Quantity I:**x^2 + 17x + 72 =0

**Quantity II:**y^2 + 15y + 56 =0Quantity I =< Quantity IIQuantity I = Quantity IIQuantity I < Quantity IIQuantity I > Quantity IIQuantity I >= Quantity IIOption A

From I:x^2 + 17x + 72 =0

=>x^2 +8x + 9x + 72 =0

=> (x+8)(x+9) = 0

=> x = -9,-8

From II:y^2 + 15y + 56 =0

=>y^2 + 8y + 7y + 56 = 0

=> (y+8)(y+7) =0

=> y = -7,-8

Quantity I =< Quantity II

**Directions(6-10):** In the following questions you have two equations and solve both individually to establish a relation between them and choose a correct option.