**Directions(1-5):** What is the approximate value of question mark “?” in the following questions.

- (? + 9.97) × 12.8 = 20.12% of 1319.97
81012186Option B

(? + 9.97) × 12.8 = 20.12% of 1319.97

=>20% of 1320 = 264

=>264/13= 20

=>20-10==10 - ? % of 179.99 = [(24.02)^2 + (17.98)^2]^1/2 + 60% of 659.98
220200238225222Option C

? % of 179.99 = [(24.02)^2 + (17.98)^2]^1/2 + 60% of 659.98

=>? % of 179.99 = 30+400

=>?= 43000/180

=>?= 238 - 339.99/? = (143.99)^1/2 + (64.01)^1/2
1015131711Option D

339.99/? = (143.99)^1/2 + (64.01)^1/2

=>?=340/(12+8)=17 - 34.02% of 550.09 + ? = 297.07 + (728.95)^1/2
115120128130137Option E

34.02% of 550.09 + ? = 297.07 + (728.95)^1/2

=>34*5.5 + x =297 + 27

=>187+ x =297 + 27

=>x=137 - 2^? = 32. 01 ÷ 128.01 × 1023.99 ÷ 7.99
3224222520Option A

2^? = 32. 01 ÷ 128.01 × 1023.99 ÷ 7.99

=> 2^? = 32. 01 ÷ 128.01 × 1023.99 ÷ 7.99

=>2^? = 32. 01 ÷ 128.01 × 1023.99 ÷ 7.99

=> (32/128)*(1024/8)

=> (1/4)*(128) = 32

=>2^5 = 32 - Upstream speed of the boat is 20% less than the downstream speed of the boat. If the boat can cover 90 km is still water in 4 hours, then find the time taken by the boat to cover 120 km downstream and 125 km downstream.
12 hrs.18 hrs.14 hrs.11 hrs.10 hrs.Option D

Speed of the boat in still water = 90/4 = 22.5 km/hr.

Let the speed of the stream = x km/hr.

Now, 0.80*(22.5+x) = 22.5 – x

=> x = 2.5

Upstream speed of the boat = 22.5 – 2.5 = 20 km/hr.

Downstream speed of the boat = 22.5+2.5 = 25 km/hr.

Time taken by boat to cover 120 km upstream and 125 km downstream

= 120/20+125/25 = 6+5 = 11 hrs. - Train A of length 120 m can cross a platform of length 240 m in 18 second. The ratio of speed of train A and train B is 4:5. Then find the length of the train B if train B can cross a pole in 12 seconds.
315 m220 m350 m280 m300 mOption E

Let speed of train A be x. x*18 = 360

=>x = 20 m/s

speed of B = 25 m/s

Length of train B = 25*12 = 300 m - Amit had certain number of toffees with him. He gave 2/15,2/7 and 1/6 of the toffees to Abhishek, Vishal and Govind respectively. Now Amit is left with only 522 toffees. Find the total number of toffees received by Abhishek.
168122150147130Option A

Let the total number of toffees Amit had be x.

Number of toffees given to Abhishek, Vishal and Govind = 2x/15, 2x/7 and x/6 resp.

Number of toffees left with Amit = x – 2x/15 – 2x/7 – x/6 = 522

=> x = 1260

Number of toffees given to Abhishek = (1260*2)/15 = 168 - Sum of volume of cylinder and volume of cone is 2190π cm^2 & height of both cylinder and cone is same i.e, 10 cm. if radius of cone is 15 cm find the ratio of radius of cylinder to radius of cone?
7:42:14:52:34:7Option C

Let r , h be the dimensions of cylinder

And R , H be the dimensions of the cone

ATQ

h=H=10

πr2+ R^2h = 2190

r =12 R=15

Therefore, r:R = 4:5 - In a box there are 6 blue ball, X red balls & 10 green balls. Probability of choosing one red ball from the given box is 1/3 , then find the sum of red and blue balls in the box?
1210161418Option D

Probability of choosing one red ball from the given box

= X/(6+X+10) = 1/3

=>2X = 16

=>X = 8

Sum of red and blue ball=8+6=14