# Quant Test for IBPS Clerk 2018 Main Exam Set – 31

Directions(1-5): Find the odd one out from the following series.

1. 10,16,28,48,78,125,176
78
48
125
176
10
Option C
+(3*2)
+(4*3)
+(5*4)
+(6*5)
+(7*6)
+(8*7)
120 should be in place of 125.

2. 1022,510,508,764,1514,3780
1022
764
510
1514
3780
Option B
*0.5-1
*1-2
*1.5-3
*2-4
*2.5-5
759 should be in place of 764.

3. 23,48,273,898,2123,4145
48
273
898
23
4145
Option E
+5^2,+15^2,+25^2,+35^2,+45^2
4148 should be in place of 4145.

4. 21,42,73,104,141,182
141
73
42
21
104
Option C
+23,+29,+31,+37,+41
44 should be in place of 42.

5. 23,27,18,30,9,45
30
27
18
23
9
Option A
+2^2,-3^2,+4^2,-5^2,+6^2
34 should be in place of 30.

6. Directions(6-10): Compare statement I and statement II and choose a required answer.

7. Find the present age of Varun.
Statement I: Present age of Varun is 25% less than the present age of Vinit. Difference in the present ages of Varun and Vinit is 10 years.
Statement II: Present ages of Varun and Vinit are in the ratio 3:4 resp. Varun is 10 years younger than Vinit.

I alone.
Both I and II.
Either I or II.
II alone.
Neither I nor II.
Option C
From I:
Let the present age of Vinit be x years.
Present age of Varun = 0.75x years
Now, x – 0.75x = 10
=> x = 40
Present age of Varun = 0.75*40 = 30 years
I alone is sufficient.
From II:
Let the present ages of Varun and Vinit be 3x years and 4x years resp.
4x – 3x = 10
=> x = 10
II alone is sufficient.
Either I or II.

8. Find the length of the Shatabdi express.
Statement I: Shatabdi express can cross a pole and a platform 216 m long in 9 seconds and 17 seconds resp.
Statement II: Shatabdi express moving with a speed of 27 m/s can cross a man standing on platform in 9 seconds.

Either I or II.
II alone.
Neither I nor II.
I alone.
Both I and II.
Option A
From I:
Let the length of the train be x m.
Now, x/9 = (x+216)/17
=> x = 243
I alone is sufficient.
From II:
Length of train = 27*9 = 243 m
II alone is sufficient.
Either I or II.

9. A bag contains red, blue and green balls in the ratio 7:4:10 resp. Find the number of balls in the bag.
Statement I: Probability of drawing a red ball from the bag is 1/3.
Statement II: Two balls are randomly drawn from the bag and the probability that a red and a green ball are drawn is 1/3.

Neither I nor II.
II alone.
Both I and II.
Either I or II.
I alone.
Option B
From I:
Probability of red ball from the bag = 7C1/21C1 = 1/3
I alone is not sufficient.
From II:
Probability of a red and a green ball from the bag = (7C1*10C1)/21C2 = 1/3
(2*7x*10x)/21*(21x-1) = 1/3
=> x = 1
So, the number of balls in the bag = 7+4+10 = 21
II alone is sufficient.

10. There are five consecutive odd numbers. Find the second largest odd number.
Statement I: Largest odd number is three less than twice the smallest odd number.
Statement II: Largest odd number is eight more than the smallest odd number.

I alone.
Both I and II.
Neither I nor II.
II alone.
Either I or II.
Option A
From I:
Let the five consecutive odd numbers are (2x+1),(2x+3),(2x+5),(2x+7) and (2x+9)
2*(2x+1) – 3 = 2x + 9
=> x = 5
second largest odd number = 2*5+7 = 17
I alone is sufficient.
From II:
Let the five consecutive odd numbers are (2x+1),(2x+3),(2x+5),(2x+7) and (2x+9)
2x+9 – (2x+1) = 8
=> 8 = 8
II alone is not sufficient.

11. Gopal invested Rs.x in a scheme offering simple interest. Find the value of x.
Statement I: Interest earned by Gopal after three years is Rs. 1800.
Statement II: Interest earned by Gopal after seven years is Rs. 4200.

Both I and II.
Either I or II.
I alone.
Neither I nor II.
II alone.
Option D
From I:
Let the rate of interest be y%.
Interest earned after three years = (x*3*y)/100 = 1800
=> xy = 60000 I alone is not sufficient.
From II:
Let the rate of interest be y%.
Interest earned after seven years = (x*7*y)/100 = 4200
=> xy = 60000
II alone is not sufficient.
Combining I and II, Not sufficient.