# Quant Test for IBPS Clerk 2018 Main Exam Set – 5

Directions(1-5): Find the missing term “?” of the following series.

1. 7,7,?,13,19,27
5
7
9
10
8
Option C
+0,+2,+4,+6,+8
? = 9

2. 7,9,15,?,87,249
20
28
15
33
24
Option D
Multiple of 3.
? = 33

3. 12,17,7,?,2,27,-3
18
20
15
10
22
Option E
+5*1
-5*2
+5*3
-5*4
+5*5
-5*6
? =22

4. 9,73,241,561,1081,?
1800
1778
1640
1849
1809
Option D
1^2 + 2^3
3^2 + 4^3
5^2 + 6^3
7^2 + 8^3
9^2 + 10^3
11^2 + 12^3
? = 1849

5. 19,28,?,100,163,244
55
42
59
35
44
Option A
+(9*1)
+(9*3)
+(9*5)
+(9*7)
+(9*9)
? = 55

6. Directions(6-10): Compare quantity I and II and choose a required option.

7. Quantity I: The respective ratio of the present age of X and Y is 6:11. After 6 years , the respective ratio of age of Y and X will become 5:3. If R who is 8 years older than X is married to a girl who is 16 years younger to Y , then find the difference between the age of R and his wife.
Quantity II: M is 2 years older than N and the difference between the age of M and S is 3 years. If age of N is 5 years , then find the age of S.

Quantity I = Quantity II
Quantity I > Quantity II
Quantity I >= Quantity II
Quantity I < Quantity II
Quantity I =< Quantity II
Option
From I:
Let present age of X and Y be 6x and 11x resp.
(6x+6)/(11x+6) = 3/5
=> x = 4
Age of R = 6x+8 = 32 years
Age of R’s wife = 11x – 16 = 28 years
Required Difference = 4 years
From II:
Age of M = 7 years
Age of S will be either 4 years or 10 years.
Quantity I =< Quantity II

8. Quantity I: Find the value of x = (5*6+434/14-19)
Quantity II: The product of two numbers is 10548 and their LCM is 252. Find the HCF of the numbers

Quantity I > Quantity II
Quantity I >= Quantity II
Quantity I < Quantity II
Quantity I = Quantity II
Quantity I =< Quantity II
Option D
From I:
x = 42
From II:
Product of two numbers =LCM*HCF
=> 10548 = 252*HCF
=> HCF = 42
Quantity I = Quantity II

9. Quantity I: Anita was travelling from point A to B. He increased his speed by 4km/hr. after every hour. He reached his destination in 8 hours and his initial speed was 50km/hr. What was the average speed of Anita in her journey?
Quantity II: A train of length x metre crosses a boy in 19 seconds and y metre long platform in 47 seconds. Find the speed of train if (x-y) = 180 metre.

Quantity I >= Quantity II
Quantity I > Quantity II
Quantity I < Quantity II
Quantity I =< Quantity II
Quantity I = Quantity II
Option C
From I:
(8/2)*{2*50+(8-1)*4} = 512 km
Average speed = 512/8 = 64 km/hr.
From II:
(x+y)/(y/19) = 47
=> y = 28x/19
Also, y-x = 180
=> (28x/19) – x = 180
=> x = 380
Speed of train = 380/19 = 72 km/hr
Quantity I < Quantity II

10. Quantity I: A and B together started a business with initial investment of Rs. (x+600) and Rs. (y+400). After a year , A and B increased their investments by Rs. 600 and Rs. 800 resp. At the end of 2 years, A received Rs. 840 as profit out of total profit of Rs. 1500. Find the value of x if (y+800) = 1100.
Quantity II: Rs. 600

Quantity I < Quantity II
Quantity I = Quantity II
Quantity I >= Quantity II
Quantity I =< Quantity II
Quantity I > Quantity II
Option A
From I:
y+800 = 1100
=> y = 300
Total investment of A and B resp.
Rs. 2x +1800 and Rs. 2200 {2y+1600} {(2x+1800)/(2x+1800+2200)}*1500 = 840
=> x = 500
Quantity I < Quantity II

11. Quantity I: A is 20% more than B while C is 30% less than A. If (A+B+C) = 608 then find the value of C.
Quantity II: An election is held between P and Q. P got 35% of the total valid votes and 10% of the votes were invalid . Find the difference between the number of votes secured by P and Q, if the total votes cast was 600.

Quantity I >= Quantity II
Quantity I < Quantity II
Quantity I =< Quantity II
Quantity I = Quantity II
Quantity I > Quantity II
Option E
From I:
Let the value of B be x and A be 1.2x.
Value of C = 70% of 1.2x = 0.84x
=> x+1.2x +0.84x = 608
=> x = 200
Value of C = 0.84x = 168
From II:
Total valid votes = 90% of 600 = 540
Total votes got by P and Q = 35% of 540 (189) and 65% of 540 (351)
Required Difference = 351 – 189 = 162
Quantity I > Qunatity II