**Directions(1-5):** Find the missing term “?” of the following series.

- 7,7,?,13,19,27
579108Option C

+0,+2,+4,+6,+8

? = 9 - 7,9,15,?,87,249
2028153324Option D

Multiple of 3.

? = 33 - 12,17,7,?,2,27,-3
1820151022Option E

+5*1

-5*2

+5*3

-5*4

+5*5

-5*6

? =22 - 9,73,241,561,1081,?
18001778164018491809Option D

1^2 + 2^3

3^2 + 4^3

5^2 + 6^3

7^2 + 8^3

9^2 + 10^3

11^2 + 12^3

? = 1849 - 19,28,?,100,163,244
5542593544Option A

+(9*1)

+(9*3)

+(9*5)

+(9*7)

+(9*9)

? = 55 -
**Quantity I:**The respective ratio of the present age of X and Y is 6:11. After 6 years , the respective ratio of age of Y and X will become 5:3. If R who is 8 years older than X is married to a girl who is 16 years younger to Y , then find the difference between the age of R and his wife.

**Quantity II:**M is 2 years older than N and the difference between the age of M and S is 3 years. If age of N is 5 years , then find the age of S.Quantity I = Quantity IIQuantity I > Quantity IIQuantity I >= Quantity IIQuantity I < Quantity IIQuantity I =< Quantity IIOption

From I:

Let present age of X and Y be 6x and 11x resp.

(6x+6)/(11x+6) = 3/5

=> x = 4

Age of R = 6x+8 = 32 years

Age of R’s wife = 11x – 16 = 28 years

Required Difference = 4 years

From II:

Age of M = 7 years

Age of S will be either 4 years or 10 years.

Quantity I =< Quantity II -
**Quantity I:**Find the value of x = (5*6+434/14-19)

**Quantity II:**The product of two numbers is 10548 and their LCM is 252. Find the HCF of the numbersQuantity I > Quantity IIQuantity I >= Quantity IIQuantity I < Quantity IIQuantity I = Quantity IIQuantity I =< Quantity IIOption D

From I:

x = 42

From II:

Product of two numbers =LCM*HCF

=> 10548 = 252*HCF

=> HCF = 42

Quantity I = Quantity II -
**Quantity I:**Anita was travelling from point A to B. He increased his speed by 4km/hr. after every hour. He reached his destination in 8 hours and his initial speed was 50km/hr. What was the average speed of Anita in her journey?

**Quantity II:**A train of length x metre crosses a boy in 19 seconds and y metre long platform in 47 seconds. Find the speed of train if (x-y) = 180 metre.Quantity I >= Quantity IIQuantity I > Quantity IIQuantity I < Quantity IIQuantity I =< Quantity IIQuantity I = Quantity IIOption C

From I:

(8/2)*{2*50+(8-1)*4} = 512 km

Average speed = 512/8 = 64 km/hr.

From II:

(x+y)/(y/19) = 47

=> y = 28x/19

Also, y-x = 180

=> (28x/19) – x = 180

=> x = 380

Speed of train = 380/19 = 72 km/hr

Quantity I < Quantity II -
**Quantity I:**A and B together started a business with initial investment of Rs. (x+600) and Rs. (y+400). After a year , A and B increased their investments by Rs. 600 and Rs. 800 resp. At the end of 2 years, A received Rs. 840 as profit out of total profit of Rs. 1500. Find the value of x if (y+800) = 1100.

**Quantity II:**Rs. 600Quantity I < Quantity IIQuantity I = Quantity IIQuantity I >= Quantity IIQuantity I =< Quantity IIQuantity I > Quantity IIOption A

From I:

y+800 = 1100

=> y = 300

Total investment of A and B resp.

Rs. 2x +1800 and Rs. 2200 {2y+1600} {(2x+1800)/(2x+1800+2200)}*1500 = 840

=> x = 500

Quantity I < Quantity II -
**Quantity I:**A is 20% more than B while C is 30% less than A. If (A+B+C) = 608 then find the value of C.

**Quantity II:**An election is held between P and Q. P got 35% of the total valid votes and 10% of the votes were invalid . Find the difference between the number of votes secured by P and Q, if the total votes cast was 600.Quantity I >= Quantity IIQuantity I < Quantity IIQuantity I =< Quantity IIQuantity I = Quantity IIQuantity I > Quantity IIOption E

From I:

Let the value of B be x and A be 1.2x.

Value of C = 70% of 1.2x = 0.84x

=> x+1.2x +0.84x = 608

=> x = 200

Value of C = 0.84x = 168

From II:

Total valid votes = 90% of 600 = 540

Total votes got by P and Q = 35% of 540 (189) and 65% of 540 (351)

Required Difference = 351 – 189 = 162

Quantity I > Qunatity II

**Directions(6-10):** Compare quantity I and II and choose a required option.